Physics (Science 086) · Class X · Chapter-wise Board Questions
Physics questions from CBSE Class X Science board papers 2022 to 2026, plus CBSE Sample Question Papers. Chapters as per CBSE Curriculum 2026-27. 323 questions, shown by marks, lowest first. Click Reveal answer under any question to see the official marking scheme.
Unit I · Light
1. Light – Reflection and Refraction
Q1.2026 Exam 2 31/7/1 · Q301 mark
Pushkar was studying a light phenomenon and wrote down the following statements in that context :
(i) A concave mirror can be used as a shaving mirror because it can form an enlarged, virtual image when the object is placed between the pole and focus.
(ii) A convex lens always forms real, inverted images, regardless of the position of the object.
(iii) The relationship between object distance (u), image distance (v) and focal length (f) of the lens is given by 1f = 1v − 1u.
Choose the option enlisting all the correct statements :
(i) and (ii)
(i) and (iii)
(ii) and (iii)
(i), (ii) and (iii)
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Official CBSE Marking Scheme · CBSE Board 2026 (2nd Board Examination), Set 31/7/1
(B) (i) and (iii)
Q2.2026 Exam 2 31/7/1 · Q321 mark
Assertion (A) : For a medium of given refractive index, the value of the angle of refraction corresponding to an angle of incidence is not a constant.
Reason (R) : With change in angle of incidence, the value of angle of refraction changes. Hence, the ratio of sine of angle of incidence to sine of angle of refraction remains constant.
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.
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Official CBSE Marking Scheme · CBSE Board 2026 (2nd Board Examination), Set 31/7/1
(D) Assertion (A) is false but Reason (R) is true
Q3.2026 Exam 2 31/8/1 · Q301 mark
When a convergent beam of light is incident on a convex mirror, the reflected rays appear to be coming from a point 20 cm behind the mirror and retrace their path. The focal length of the mirror is
20 cm
10 cm
40 cm
30 cm
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Official CBSE Marking Scheme · CBSE Board 2026 (2nd Board Examination), Set 31/8/1
(B) 10 cm
Q4.2026 Exam 2 31/8/1 · Q311 mark
In the given ray diagram the values of the angle of incidence and the angle of reflection are :
i = 50°, r = 40°
i = 40°, r = 50°
i = 40°, r = 40°
i = 50°, r = 50°
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Official CBSE Marking Scheme · CBSE Board 2026 (2nd Board Examination), Set 31/8/1
(D) i = 50°, r = 50°
Q5.2026 Main 31/1/1 · Q301 mark
A convex lens of focal length 15 cm, is forming a real image. If the size of image is same as the size of object, then position of object and position of image will be, respectively :
Rays from the sun converge at a point 25 cm behind a convex lens. The distance at which an object be placed in front of the lens to get a virtual image, is :
Mirror ‘X’ is used to concentrate sunlight in solar furnace and Mirror ‘Y’ is fitted on the side of the vehicle to see the traffic behind the driver. Which of the following statements are true for the two mirrors ?
(i) The image formed by mirror ‘X’ is real, diminished and at its focus.
(ii) The image formed by mirror ‘Y’ is virtual, diminished and erect.
(iii) The image formed by mirror ‘X’ is virtual, diminished and erect.
(iv) The image formed by mirror ‘Y’ is real, diminished and at its focus.
(i) and (ii)
(ii) and (iii)
(iii) and (iv)
(i) and (iv)
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/1/1
A. (i) and (ii) [1]
Q9.2025 Main 31/2/1 · Q111 mark
If the absolute refractive indices of two media X and Y are 65 and 43 respectively, then the refractive index of Y with respect to X will be :
109
910
98
89
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/2/1
A. 109 [1]
Q10.2025 Main 31/2/1 · Q121 mark
An object is placed at a distance of 30 cm from the pole of a concave mirror. If its real and inverted image is formed at 60 cm in front of the mirror, the focal length of the mirror is :
– 15 cm
– 20 cm
+ 20 cm
+ 15 cm
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/2/1
B. – 20 cm [1]
Q11.2025 Main 31/3/1 · Q111 mark
Absolute refractive index of water and glass is 43 and 32 respectively. If the speed of light in glass is 2 × 108 m/s, the speed of light in water is :
94 m/s
73 m/s
169 m/s
98 m/s
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/3/1
NOTE: Full credit of one mark to all the students. [1]
Q12.2025 Main 31/4/1 · Q101 mark
To get an image of magnification –1 on a screen using a lens of focal length 20 cm, the object distance must be :
Less than 20 cm
30 cm
40 cm
80 cm
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/4/1
(c) 40 cm [1]
Q13.2025 Main 31/4/1 · Q111 mark
An optical device ‘X’ is placed obliquely in the path of a narrow parallel beam of light. If the emergent beam gets displaced laterally, the device ‘X’ is :
plane mirror
convex lens
glass slab
glass prism
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/4/1
(c) glass slab [1]
Q14.2025 Main 31/5/1 · Q131 mark
In order to obtain large images of the teeth of patients, the dentist holds the concave mirror in such a manner that the teeth are positioned
at the focus of mirror.
between pole and focus of the mirror.
between focus and centre of curvature of the mirror.
at the centre of curvature of the mirror.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/5/1
(B) Between pole and focus of the mirror [1]
Q15.2025 Main 31/6/1 · Q131 mark
Identify from the following the ray diagram which shows the correct path of the reflected ray for the ray incident on a concave mirror as shown :
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/6/1
(C) [1]
Q16.2025 Supp 31/S/1 · Q111 mark
A 5 cm long rod is placed vertically in front of a concave mirror. If its 5 cm long image is formed at 20 cm in front of the mirror, the focal length of the mirror is :
− 20 cm
− 10 cm
− 5 cm
20 cm
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Official CBSE Marking Scheme · CBSE Board 2025 (Supplementary), Set 31/S/1
(B) – 10 cm
Q17.2025 Supp 31/S/1 · Q121 mark
An optical device which always produces images of m = + 1 is :
Plane mirror
Convex mirror
Concave mirror
Convex lens
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Official CBSE Marking Scheme · CBSE Board 2025 (Supplementary), Set 31/S/1
(A) Plane mirror
Q18.2024 Main 31/1/1 · Q121 mark
At what distance from a convex lens should an object be placed to get an image of the same size as that of the object on a screen ?
Beyond twice the focal length of the lens.
At the principal focus of the lens.
At twice the focal length of the lens.
Between the optical centre of the lens and its principal focus.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/1/1
(c) At twice the focal length of the lens
Q19.2024 Main 31/4/1 · Q111 mark
Absolute refractive index of glass and water is 32 and 43 respectively. If the speed of light in glass is 2 × 108 m/s, the speed of light in water is :
94 × 108 m/s
52 × 108 m/s
73 × 108 m/s
169 × 108 m/s
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/4/1
(A) 94 × 108 m/s
Q20.2024 Main 31/5/1 · Q111 mark
How will the image formed by a convex lens be affected, if the upper half of the lens is wrapped with a black paper ?
The size of the image formed will be one-half of the size of the image due to complete lens.
The image of upper half of the object will not be formed.
The brightness of the image will reduce.
The lower half of the inverted image will not be formed.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/5/1
(C) The brightness of the image will reduce
Q21.2024 Main 31/5/1 · Q131 mark
The colour of light for which the refractive index of glass is minimum, is :
Red
Yellow
Green
Violet
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/5/1
(A) Red
Q22.2024 Supp 31/S/1 · Q131 mark
The image formed by a concave mirror of focal length 50 cm is real and of magnification – 1. In this case the distance between the object from its own image is :
50 cm
100 cm
200 cm
Zero
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Official CBSE Marking Scheme · CBSE Board 2024 (Supplementary), Set 31/S/1
(D) Zero
Q23.2023 Main 31/2/1 · Q131 mark
An object is placed in front of a convex mirror at infinity. According to the New Cartesian Sign Convention, the sign of the focal length and the sign of the image distance in this case are respectively :
+ , −
− , +
− , −
+ , +
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/2/1
(d) [1]
Q24.2023 Main 31/6/1 · Q71 mark
A student wants to obtain an erect image of an object using a concave mirror of 10 cm focal length. What will be the distance of the object from mirror ?
Less than 10 cm
10 cm
between 10 cm and 20 cm
more than 20 cm
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/6/1
(a)
Q25.2023 Supp 31/C/1 · Q121 mark
When an object is placed beyond 2F of a convex lens, the nature of the image formed is :
Real, inverted and diminished
Real, erect and magnified
Virtual, erect and magnified
Real, inverted and magnified
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Official CBSE Marking Scheme · CBSE Board 2023 (Supplementary), Set 31/C/1
(a)
Q26.SQP 2025-26 · Q301 mark
Arnav was making notes and he wrote down the following statements from his understanding of reflection from curved surfaces.
I. Concave mirrors can produce both real and virtual images depending on the position of the object.
II. Convex mirrors always produce real, inverted images regardless of the object’s position.
III. In both concave and convex mirrors, the image location can be determined using the mirror formula 1f = 1v + 1u where f is the focal length, v is the image distance, and u is the object distance.
Choose from the following the correct option that lists the correct statements about reflection from curved surfaces.
I and II
I, II and III
II and III
I and III
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Official CBSE Marking Scheme · CBSE Sample Question Paper 2025-26 Marking Scheme
D. I and III
Q27.SQP 2025-26 · Q321 mark
The following question consists of two statements – Assertion (A) and Reason (R). Answer these questions by selecting the appropriate option given below:
Assertion (A): A point object is placed at a distance of 26 cm from a convex mirror of focal length 26 cm. The image will not form at infinity.
Reason (R): For above given system the equation 1f = 1v + 1u gives v = ∞.
Both A and R are true, and R is the correct explanation of A.
Both A and R are true, and R is not the correct explanation of A.
A is true but R is false.
A is false but R is true.
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Official CBSE Marking Scheme · CBSE Sample Question Paper 2025-26 Marking Scheme
C. A is true but R is false
Q28.SQP 2026-27 · Q301 mark
A student wants to determine the focal length of a convex lens using sunlight. Which of the following practical procedures will give the most accurate result?
Move the lens close to a wall and measure the blurred circle.
Hold the lens above a sheet of paper and adjust until the smallest, brightest spot is formed.
Measure the thickness of the lens with a scale.
Look through the lens at a distant object.
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Official CBSE Marking Scheme · CBSE Sample Question Paper 2026-27 Marking Scheme
B. Hold the lens above a sheet of paper and adjust until the smallest, brightest spot is formed.
Q29.SQP 2026-27 · Q321 mark
The following one question consists of two statements – Assertion (A) and Reason (R). Answer these questions by selecting the appropriate option given below:
Assertion (A): The apparent depth of a coin in water is less than its real depth.
Reason (R): Light bends away from the normal when it travels from water to air.
Both A and R are true, and R is the correct explanation of A.
Both A and R are true, and R is not the correct explanation of A.
A is true but R is false.
A is false but R is true.
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Official CBSE Marking Scheme · CBSE Sample Question Paper 2026-27 Marking Scheme
A. Both A and R are true, and R is the correct explanation of A.
Q30.2026 Main 31/1/1 · Q332 marks
The given figure shows image formation by a lens. Analyse the figure and answer the following questions :
(a) What is the type of lens used for image formation in the given ray diagram ?
(b) If the real image is formed at a distance of 30 cm from the lens and the size of image is twice the size of the object, then where was the object placed ?
(a) In optically rarer medium speed of light is more and in optically denser medium speed of light is less. [1]
(b) A < C < B [1]
Q34.2025 Main 31/1/1 · Q242 marks
An object is placed at a distance of 60 cm from a concave lens of focal length 30 cm. Use lens formula to find the position of the image formed in this case.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/1/1
u = – 60 cm, f = –30 cm
1f = 1v – 1u [½]
1– 30 cm = 1v – 1– 60 cm [½]
1v = 1–30 – 160 = –360
v = – 20 cm [1]
Position of image is 20 cm from a concave lens.
Q35.2025 Main 31/2/1 · Q252 marks
(a) Out of the two lenses, one concave and the other convex, state which one will diverge a parallel beam of light falling on it. Draw a ray diagram to show the principal focus of the lens.
OR
(b) A ray of light after refraction from a convex lens emerges parallel to its principal axis.
(i) Draw a labelled ray diagram to show it.
(ii) In this case, the incident ray before refraction from the lens passes through a point on its principal axis. Name the point.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/2/1
(a) Concave lens [1]
[1]
OR
(b) (i)
[1]
(ii) Principal focus / Focus [1]
Q36.2025 Main 31/5/1 · Q242 marks
The values of absolute refractive indices of kerosene and water are 1.44 and 1.33 respectively. Compare the two media on the basis of their
(a) optical density
(b) mass density
(c) relative speed of propagation of light.
What do you infer on the basis of above comparisons ?
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/5/1
Kerosene (1·44)
Water (1·33)
Marks
(a)
Higher optical density
Lower optical density
½
(b)
Lower mass density
Higher mass density
½
(c)
Lower speed of light
Higher speed of light
½
Inference: Although, kerosene is optically denser than water but its mass density is less than water / An optically denser medium may not possess greater mass density. [½]
Q37.2025 Main 31/6/1 · Q242 marks
Study the figure in which the path of a ray of light going from Medium 1 to Medium 2 is shown.
(a) Out of the two Media – Medium 1 and Medium 2, in which is the speed of light more ?
(b) State reason of bending of the refracted ray away from the normal.
(c) Express refractive index of Medium 2 with respect to Medium 1 in terms of speed of light in two media.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/6/1
(a) Medium 2 [½]
(b) Ray bends away from the normal because it is travelling from optically denser medium to rarer medium / speed of light in medium 2 increases. [½]
(c) n21 = Speed of light in medium 1Speed of light in medium 2 [1]
Q38.2025 Supp 31/S/1 · Q252 marks
An object is placed 25 cm in front of a concave mirror of focal length 15 cm. Use mirror formula and new cartesian sign convention to determine the position of the image formed.
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Official CBSE Marking Scheme · CBSE Board 2025 (Supplementary), Set 31/S/1
u = – 25 cm, f = – 15 cm, v = ? [½]
1v + 1u = 1f [½]
1v = −115 + 125 = −5 + 375 = −275
v = − 752 = – 37.5 cm (Image is formed 37.5 cm in front of the mirror.) [1]
Q39.2024 Main 31/1/1 · Q242 marks
An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Find the position of the image formed by the mirror.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/1/1
u = −10 cm; f = +15 cm [½]
1f = 1v + 1u [½]
115 = 1v + 1−10 cm, so 1v = 115 cm + 110 cm = 16 cm
v = + 6 cm [1]
Image is formed behind the mirror.
Q40.2024 Main 31/2/1 · Q242 marks
(a) State two laws of refraction of light.
OR
(b) Define the term absolute refractive index of a medium. A ray of light enters from vacuum to glass of absolute refractive index 1.5. Find the speed of light in glass. The speed of light in vacuum is 3 × 108 m/s.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/2/1
(a) Laws of Refraction of light :
(i) The incident ray, the refracted ray and the normal to the interface of two transparent media at the point of incidence, all lie in the same plane. [1]
(ii) The ratio of the sine of angle of incidence to the sine of angle of refraction is a constant, for the light of a given colour and for the given pair of media. [1]
Note: If a student writes sin isin r = constant instead of statement, award ½ mark only.
OR
(b) Absolute refractive index of a medium is the ratio of speed of light in air/vacuum to the speed of light in the given medium. [1]
Given: c = 3 × 108 m/s; nm = 1·5; vm = ?
Absolute refractive index of a medium (nm) = speed of light in vacuumspeed of light in medium = cvm [½]
vm = cnm = 2 × 108 m/s [½]
Q41.2024 Main 31/5/1 · Q252 marks
The heat produced at a point due to concentration of sunlight by a convex lens burns a paper.
(a) Explain why it happens.
(b) Name the term (in the context of the lens used) given to the point at which the paper starts burning. What does the bright spot formed on the paper represent ?
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/5/1
(a) The sun light is converged at a point by convex lens which generates heat causing the paper to burn. [1]
(b) • Principal Focus [½]
• Real image of the Sun. [½]
Q42.2024 Supp 31/S/1 · Q242 marks
Draw a labelled ray diagram to show the formation of image due to a concave mirror when an object is placed between its pole and principal focus.
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Official CBSE Marking Scheme · CBSE Board 2024 (Supplementary), Set 31/S/1
[P : Pole, F : Principal Focus, AB : Object, A′B′ : Image]
Ray diagram [1]; Labelling of pole and principal focus [½]; Direction of rays [½]
Q43.2023 Main 31/6/1 · Q252 marks
A light ray enters from medium A to medium B as shown in the figure.
(a) Which one of the two media is denser w.r.t. other medium ? Justify your answer. [1]
(b) If the speed of light in medium A is va and in medium B is vb, what is the refractive index of B with respect to A. [1]
OR
(a) A ray of light starting from diamond is incident on the interface separating diamond and water. Draw a labelled ray diagram to show the refraction of light in this case. [1]
(b) Absolute refractive indices of diamond and water are 2.42 and 1.33 respectively. Find the value of refractive index of water w.r.t. diamond. [1]
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/6/1
(a) Medium B [½]
In medium B ray of light bends towards normal / ∠r < ∠i [½]
(b) Refractive index of Medium B with respect to Medium A is nBA = vavb [1]
OR
(a)
[1] (Credit marks for ∠i, ∠r and arrows.)
(b) n21 = n2an1a [½]
= 1·332·42 or 0·55 [½]
Q44.2023 Supp 31/C/1 · Q242 marks
(a) Find the magnification of the image formed by a spherical mirror from the following data : u = – 20 cm, f = – 15 cm.
OR
(b) Draw a labelled ray diagram for the image formation by a concave mirror when an object is placed between its centre of curvature and focus.
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Official CBSE Marking Scheme · CBSE Board 2023 (Supplementary), Set 31/C/1
(a) 1f = 1v + 1u [½]
1v = 1f – 1u = 1–15 – 1–20 = –160 [½]
v = – 60 cm [½]
m = –v/u = – –60–20 = – 3 [½]
OR
(b)
Diagram [1½]; Direction of the rays [½]
Q45.SQP 2025-26 · Q332 marks
The above image shows the formation of an image with an optical instrument.
A. Identify the optical instrument (shown schematically as a rectangle) in the image.
B. What type of image is formed in this case?
C. Based on the measurements given in the image, calculate the focal length of the instrument.
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Official CBSE Marking Scheme · CBSE Sample Question Paper 2025-26 Marking Scheme
A. The optical instrument shown in the figure is a concave lens.
B. The image formed is a virtual image.
C. To find the focal length of a concave lens, we can use the lens formula: 1f = 1v − 1u, where u = − 20 cm (object distance, taken as negative for concave lenses), v = − 10 cm (image distance, also taken as negative since the image formed by a concave lens is virtual).
Solution: 1f = 1−10 − 1−20 = −220 + 120 = −120
f = − 20 cm
Q46.SQP 2026-27 · Q332 marks
A. State Snell’s Law of refraction.
B. Define the refractive index of a material with respect to another material giving the mathematical expression.
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Official CBSE Marking Scheme · CBSE Sample Question Paper 2026-27 Marking Scheme
A. The ratio of sine of angle of incidence to the sine of angle of refraction is a constant, for the light of a given colour and for the given pair of media. [1]
B. Consider a ray of light travelling from medium 1 into medium 2. Let v1 be the speed of light in medium 1 and v2 be the speed of light in medium 2. The refractive index of medium 2 with respect to medium 1 is given by n21 = v1v2 [1]
Q47.2026 Main 31/2/1 · Q353 marks
(a) Write the expression for the magnification produced by a lens in terms of object distance and image distance.
(b) A 4 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 20 cm. Calculate the size of the image formed, if the distance of the object from the lens is 10 cm.
(a) Magnification, m = Image distance / Object distance, i.e. m = vu [1]
(b) ho = +4 cm, f = +20 cm, u = −10 cm, hi = ?
1v − 1u = 1f [½]
1v = 1f + 1u = 120 + 1−10 = −120
v = −20 cm [½]
m = vu = −20−10 = 2; m = height of imageheight of object
height of image = m × height of object = 2 × 4 cm = 8 cm [1]
Q48.2026 Main 31/4/1 · Q353 marks
(a) Observe the given ray diagram and compare :
(i) the speed of light in medium A and the speed of light in medium B.
(ii) the optical densities of medium B and medium C.
(b) Draw a ray diagram for refraction where the optical density of medium ‘A’ becomes equal to the optical density of medium ‘C’ and optical density of medium ‘B’ is greater than the optical density of medium ‘A’ and medium ‘C’.
Image is formed when object is placed between Pole and Principal Focus
Small / diminished
Enlarged / magnified
(Any one difference) [1]
(ii) m = −2; m = height of imageheight of object = h′h [½]
h = h′m = −20−2 = 10 cm [½]
Q50.2025 Main 31/1/1 · Q313 marks
Draw ray diagrams to show the nature, position and relative size of the image formed by a convex mirror when the object is placed (i) at infinity and (ii) between infinity and pole P of the mirror.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/1/1
(i)
[1½]
(ii)
[1½]
(Note: Deduct ½ mark if arrows are not drawn.)
Q51.2025 Main 31/2/1 · Q313 marks
A convex lens forms an 8·0 cm long image of a 2·0 cm long object which is kept at a distance of 6·0 cm from the optical centre of the lens. If the object and the image are on the same side of the lens, find (i) the nature of the image, (ii) the position of the image, and (iii) the focal length of the lens.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/2/1
(i) Nature: Virtual and erect [1]
(ii) Given h′ = + 8·0 cm, h = + 2·0 cm, u = – 6 cm
m = h′h = vu [½]
= 8·0 cm2·0 cm = v–6 cm
or v = – 24 cm [½]
Thus, the image is at a distance of 24 cm from the lens.
(iii) Lens formula 1v – 1u = 1f [½]
1–24 – 1–6 = 1f
–124 + 16 = 1f
18 = 1f
f = 8 cm [½]
Thus the focal length of the lens = 8 cm
Q52.2025 Main 31/4/1 · Q313 marks
If we want to obtain a virtual and magnified image of an object by using a concave mirror of focal length 18 cm, where should the object be placed? Use mirror formula to determine the object distance for an image of magnification +2 produced by this mirror to justify your answer.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/4/1
Object should be placed between F and P / At less than 18 cm distance from the mirror. [1]
Mirror formula: 1/v + 1/u = 1/f [½]
Magnification m = +2, f = – 18 cm
m = – v/u = +2 ⇒ v = –2u [1]
1/(–2u) + 1/u = 1/(–18 cm)
1/(2u) = 1/(–18 cm) [½]
u = – 9 cm
Q53.2025 Main 31/5/1 · Q313 marks
The power of a lens is –0.25 D. Based on this information, find out
(a) The type of lens and its focal length.
(b) The eye defect for which it may be used as a corrective lens.
(c) The nature and size of the image formed by this lens when an object is placed between F and 2F from the optical centre of this lens.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/5/1
(a) Concave lens [½]
P = 1f (m) ⇒ f = 1–0.25 ⇒ f = – 4 m [½]
(b) Myopia [1]
(c) Virtual, Erect [½]
Diminished [½]
Q54.2025 Main 31/6/1 · Q313 marks
A student placed a candle flame at different distances from a convex lens and focused its image on a screen. He recorded his observation in tabular form as given below :
S.No.
Distance of flame from the lens (cm)
Distance of the image from the lens
1
– 90
+ 18
2
– 60
+ 20
3
– 40
+ 24
4
– 30
+ 30
5
– 24
+ 40
6
– 20
+ 60
7
– 18
+ 90
8
– 12
+ 120
Analyse the observation table and on the basis of your analysis only, answer the following questions (without doing any calculations) :
(a) What is the focal length of the convex lens used ? Give reason to justify your answer.
(b) Which one of the sets of observations is not correct and why ?
(c) Draw ray diagram to show image formation for any correct set of observation.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/6/1
(a) Focal length = + 15 cm (Ignore units) [½]
Reason: when object distance and image distance are same i.e. object is at 2F, image is also formed at 2F on the other side; 2f = 30 cm [½]
(b) Observation No. 8 [½]
Reason: here the object is between optical centre and principal focus of the lens hence image is formed on the same side as the object and v is not equal to + 120 cm. (it should be – 120 cm) [½]
(c) Ray diagram
Any one ray diagram [1]
Q55.2023 Main 31/1/1 · Q303 marks
(a) Complete the following ray diagram to show the formation of image :
(b) Mention the nature, position and size of the image formed in this case.
(c) State the sign of the image distance in this case using the Cartesian sign convention.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/1/1
(a)
A′B′ is the image formed. [1]
Credit full mark if attempted.
(b) Nature: Virtual and erect [½]
Position: Behind the mirror (between P and F) [½]
Size: Diminished [½]
(c) Positive [½]
Q56.2023 Main 31/2/1 · Q313 marks
(a) A student has focussed the image of an object of height 3 cm on a white screen using a concave mirror of focal length 12 cm. If the distance of the object from the mirror is 18 cm, find the values of the following :
(i) Distance of the image from the mirror
(ii) Height of the image
OR
(b) Define power of a lens. The focal length of a lens is – 10 cm. Write the nature of the lens and find its power. If an object is placed at a distance of 20 cm from the optical centre of this lens, according to the New Cartesian Sign Convention, what will be the sign of magnification in this case ?
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/2/1
(a) Here h = 3 cm; f = −12 cm, u = −18 cm [½]
(Award full marks if data not written but calculations are correct)
(i) v = ?, h′ = ?
1f = 1v + 1u [½]
1v = 1f − 1u = 1−12 cm − 1−18 cm [½]
v = −36 cm [½]
(ii) h′ = − vu h [½]
h′ = (−) −36 cm−18 cm × 3 cm = −6 cm [½]
OR
(b) • Power of lens : Ability of a lens to converge or diverge light rays falling on it / Degree of convergence or divergence of light achieved by a lens / Reciprocal of focal length of lens in metre. (Any one) [1]
It is diverging/concave lens [½]
P = 1f(m) = 100f(cm) [½]
P = 100−10 cm = −10 D [½]
Sign of magnification = + or positive [½]
Q57.2023 Main 31/4/1 · Q303 marks
(A) Define the following terms in the context of a diverging mirror :
(i) Principal focus
(ii) Focal length
Draw a labelled ray diagram to illustrate your answer.
OR
(B) An object of height 10 cm is placed 25 cm away from the optical centre of a converging lens of focal length 15 cm. Calculate the image-distance and height of the image formed.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/4/1
(A) (i) It is a point on the principal axis of a diverging mirror from where the rays parallel to principal axis appear to diverge after reflection. [1]
(ii) The distance between the pole and the principal focus of a mirror. [1]
[1]
OR
(B) 1v − 1u = 1f [½]
1v = 1f + 1u
f = 15 cm, u = −25 cm, h = 10 cm [½]
1v = 115 cm + 1−25 cm = 275 = + 137.5
v = 37.5 cm [1]
Height of the image = vu × height of the object [½]
= 37.5−25 cm × 10 cm
h′ = −15 cm [½]
Q58.2023 Main 31/4/1 · Q313 marks
The power of a lens is +4D. Find the focal length of this lens. An object is placed at a distance of 50 cm from the optical centre of this lens. State the nature and magnification of the image formed by the lens and also draw a ray diagram to justify your answer.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/4/1
• Focal length of lens, f(m) = 1P [½]
P = +4.0 D
⇒ f = 1+4 D = 0.25 m = 25 cm [½]
• Real and inverted [½]
• Magnification = −1 [½]
•
[1] [Deduct ½ mark if direction of rays is not marked]
Q59.2023 Main 31/5/1 · Q303 marks
(a) (i) An object of 5 cm height is placed at a distance of 20 cm from the optical centre of a concave lens of focal length 18 cm. Calculate (1) image distance and (2) the magnification in this case.
(ii) Compare the values of magnification obtained by a concave lens and a convex lens when both the lenses form virtual images.
OR
(b) A convex lens can form a (i) real, inverted and magnified image as well as (ii) virtual, erect and magnified image of an object. If the focal length of the lens is 10 cm, what should be the range of the object distance in both cases ? Draw ray diagrams to justify your answer.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/5/1
(a) Given, height of object (h) = 5 cm, object distance (u) = – 20 cm, focal length (f) = – 18 cm, image distance (v) = ?
(ii) For convex lens : m > 1, for concave lens m < 1 [½, ½]
OR
(b) (i) 20 cm > u > 10 cm / Between 10 cm and 20 cm [½]
(ii) Object distance less than 10 cm / 10 > u > 0 [½]
[1 + 1 for the two ray diagrams] (Deduct ½ mark for not marking the direction of ray)
Q60.SQP 2026-27 · Q353 marks
A concave lens forms an image that is 1/3rd the size of the object, as shown in the diagram. If the object is placed 24 cm in front of the lens, determine:
A. the type of lens.
B. the image distance
C. the focal length of the lens
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Official CBSE Marking Scheme · CBSE Sample Question Paper 2026-27 Marking Scheme
A. Object distance u = 24 cm (in front of lens). Type of lens: Concave (diverging) lens (given). [1]
B. Image distance, v: Magnification m = hiho = vu. For a concave lens the image is upright and diminished, so m = + 13. Using sign convention u = −24 cm, v = mu = 13 × (−24) = −8 cm. [1] Thus, the image is located 8 cm on the same side of the lens as the object (virtual image).
C. Focal length f : Use lens formula 1f = 1v − 1u. Substitute v = −8 cm, u = −24 cm: 1f = 1−8 + 1−24 = − 18 + 124 = − 3 + 124 = − 224 = − 112
So, f = −12 cm [1]
Q61.2026 Main 31/1/1 · Q384 marks
Read the following passage and answer the questions given :
Lenses can form different types of images depending upon their focal length and position of object. A convex lens can create real, inverted or virtual, erect images, while a concave lens forms only virtual and diminished images. The focal length determines the power of lens. Convex lenses have positive focal length while concave lenses have negative focal length by convention. When lenses are placed together, their combined power is determined by the sum of their individual powers. Ray diagrams help to visualize how light converges or diverges through lens to form an image.
(a) A convex lens of focal length 20 cm is used to form an image. If an object is placed at 40 cm from the lens, what will be the position and nature of image ? [1]
(b) Illustrate the formation of image with the help of ray diagram, when the object is placed between the optical centre and principal focus of concave lens. [1]
(c) (i) A lens combination consists of a convex lens of focal length 30 cm and a concave lens of focal length 15 cm placed together. Find the equivalent focal length and power of this lens combination. [2]
OR
(c) (ii) Two lenses are placed in contact. One is a concave lens with focal length 2 m and the other is a convex lens with focal length 1.5 m. What type of lens will the combination behave as (convex or concave) ? Give reason. [2]
(a) • Position – Image will form at 40 cm / 2F / C [½]
• Nature – Real and inverted [½]
Alternate answer: f = +20 cm, u = −40 cm. Using lens formula, 1v − 1u = 1f; 1v = 120 + 1−40; v = +40 cm. Position – 40 cm on the other side of the lens. Nature – Real and inverted.
(b) [1]
(c) (i) f1 = 30 cm = 0.3 m, f2 = −15 cm = −0.15 m
P = 1f [½]
P1 = +10.3 D; P2 = −10.15 D [½]
Equivalent power, P = P1 + P2 [½]; P = −3.33 D
Equivalent focal length, f = 1P = −13.33 = −0.3 m = −30 cm [½]
OR
(c) (ii) • Combination lens will behave like convex lens [1]
• f1 = −2 m, f2 = 1.5 m; P = 1f; P1 = −12 D, P2 = +11.5 D; P = P1 + P2 = 16 D; f = +6 m. The focal length of combination is positive. [1]
Alternate answer: • Combination lens will behave like convex lens. • Convex lens – Less ‘f’, More ‘P1’; Concave lens – More ‘f’, Less ‘P2’. Combined Power = P1 + P2, which will be positive.
Q62.2026 Main 31/3/1 · Q384 marks
The variation of image distance (v) with the object distance (u) for a convex lens is given in the following observation table. Analyse it and answer the questions given below :
S.No.
Object distance (u) cm
Image distance (v) cm
1
– 150
+ 30
2
– 75
+ 37·5
3
– 50
+ 50
4
– 37·5
+ 75
5
– 30
+ 150
6
– 15
+ 37·5
(a) Without calculation, find out the focal length of the given convex lens. Justify your answer. [1]
(b) Which one of the observations given in the table is not correct and why ? [1]
(c) (i) Find out the value of magnification for u = – 30 cm. Write the nature of the image formed. Give reason for your answer. [2]
OR
(c) (ii) Analyse the data given in the table above and draw the labelled ray diagram for u = – 30 cm and v = 150 cm. [2]
(a) In observation no. 3, the object distance is equal to image distance, which is only possible when the object is at 2F (C) = 50 cm. Therefore, the focal length is 25 cm. [1]
(b) • Observation no. 6 [½]
• Because when object is kept between F and O, image formed by lens will be on same side of object. Hence, image distance (v) should be negative. [½]
(c) (i) m = vu = 150−30 [½]; m = −5 [½]
• Nature of image: Image will be real and inverted [½]
• Reason: because the value of m is negative. [½]
OR
(c) (ii) [2] (deduct ½ mark for no or incorrect direction of rays)
Q63.2026 Main 31/4/1 · Q384 marks
The above ray diagram is to show image formation by a reflecting telescope. Reflecting telescope revolutionized our way of looking into the sky. Reflecting telescopes employ large mirrors to gather and focus light rather than relying solely on lenses as we do in the refracting telescopes. These telescopes utilize precisely shaped and polished mirrors to capture incoming light and reflect it to a focal point, where the telescope forms an image for observation.
(a) What kind of image of a star is seen by the observer in the eye-piece ? [1]
(b) What kind of mirror is used in this reflecting telescope ? [1]
(c) Explain with the reason, what kind of optical device (type of lens or mirror) is used at the eye-piece. [2]
OR
(c) What is the role of plane mirror in image formation by this telescope ? [2]
• It magnifies the image formed by the curved mirror [1]
OR
(c) The plane mirror redirects / reflects the light rays coming from the curved mirror towards eyepiece. [2]
Q64.2024 Main 31/1/1 · Q394 marks
Study the data given below showing the focal length of three concave mirrors A, B and C and the respective distances of objects placed in front of the mirrors :
Case
Mirror
Focal Length (cm)
Object Distance (cm)
1
A
20
45
2
B
15
30
3
C
30
20
(i) In which one of the above cases the mirror will form a diminished image of the object ? Justify your answer. [1]
(ii) List two properties of the image formed in case 2. [1]
(iii) (A) What is the nature and size of the image formed by mirror C ? Draw ray diagram to justify your answer. [2]
OR
(iii) (B) An object is placed at a distance of 18 cm from the pole of a concave mirror of focal length 12 cm. Find the position of the image formed in this case. [2]
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/1/1
(i) • Mirror A. [½] • as the object is placed beyond the centre of curvature of the mirror. [½]
(ii) Same size / Real / Inverted (Any two) [½ + ½]
[1] (Deduct ½ mark if direction of rays are not marked)
OR
(iii) (B) Here f = −12 cm, u = −18 cm, v = ? [½]
Mirror formula 1f = 1v + 1u or 1v = 1f − 1u = 1−12 − 1−18 [½]
v = − 36 cm. In front of the mirror at a distance of 36 cm from the pole of the mirror. [1]
Q65.2024 Main 31/5/1 · Q394 marks
A highly polished surface such as a mirror reflects most of the light falling on it. In our daily life we use two types of mirrors – plane and spherical. The reflecting surface of a spherical mirrors may be curved inwards or outwards. In concave mirrors, reflection takes place from the inner surface, while in convex mirrors reflection takes place from the outer surface.
(a) Define the principal axis of a concave mirror. [1]
(b) A ray of light is incident on a concave mirror, parallel to its principal axis. If this ray after reflection from the mirror passes through the principal axis from a point at a distance of 10 cm from the pole of the mirror, find the radius of curvature of the mirror. [1]
(c) (i) An object is placed at a distance of 10 cm from the pole of a convex mirror of focal length 15 cm. Find the position of the image. [2]
OR
(c) (ii) A mirror forms a virtual, erect and diminished image of an object. Identify the type of this mirror. Draw a ray diagram to show the image formation in this case. [2]
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/5/1
(a) It is straight line passing through the pole and centre of curvature of a concave mirror. [1]
(b) Radius of curvature, R = 20 cm [1]
(c) (i) u = −10 cm, f = +15 cm [½]; 1f = 1v + 1u [½]
1v = 1f − 1u = 115 − 1−10 = 16 ⇒ v = + 6 cm [1]
OR
(c) (ii) Convex mirror / Diverging mirror [½]
[1½] [Note: Deduct ½ mark if direction of rays is not shown]
Q66.2024 Supp 31/S/1 · Q394 marks
In our laboratories we use compound microscopes to see the magnified image of a microscopic object. A compound microscope is made up of two lenses. The lens nearest to the object to be viewed, called objective lens, forms real, inverted and magnified image of the object. This image serves as an object for the second lens called eyepiece. The eyepiece forms virtual, erect and magnified image of its object. Thus, the resultant image formed by a microscope is virtual, inverted and magnified with respect to the microscopic object viewed.
(a) The image of an object formed by a convex lens of focal length 2 cm is real, inverted and magnified. What is the range of object distance in this case ? [1]
(b) The image of an object formed by a convex lens of focal length 6 cm is virtual, erect and magnified. What is the range of object distance in this case ? [1]
(c) (i) An object is placed at a distance of 12 cm from the optical centre of a convex lens of focal length 18 cm. Draw a labelled ray diagram to show the formation of image in this case. [2]
OR
(c) (ii) The image formed by a convex lens is real, inverted and of the same size as the object. If the distance between the objects and the image is 60 cm, determine the focal length of the lens. Give justification for your answer. [2]
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Official CBSE Marking Scheme · CBSE Board 2024 (Supplementary), Set 31/S/1
(a) More than 2 cm and less than 4 cm from the optical centre of the lens [1]
(b) Less than 6 cm from the optical centre of the lens [1]
(c) (i)
OB = 12 cm, OF = 18 cm, A′B′ : Image [2] (Deduct ½ mark if direction of rays is not shown)
OR
(c) (ii) As per the information given in the question, the lens lies at the centre of the object placed and image formed.
The position of the object is at 2F1 therefore object distance = image distance = 2f
∴ 2f + 2f = 60 cm [1]; 4f = 60; f = 15 cm
∴ The focal length of the lens = 15 cm [1]
Note : Do not deduct marks if diagram is not drawn.
Q67.2023 Main 31/1/1 · Q394 marks
Hold a concave mirror in your hand and direct its reflecting surface towards the sun. Direct the light reflected by the mirror on to a white card-board held close to the mirror. Move the card-board back and forth gradually until you find a bright, sharp spot of light on the board. This spot of light is the image of the sun on the sheet of paper; which is also termed as “Principal Focus” of the concave mirror.
(a) List two applications of concave mirror. [1]
(b) If the distance between the mirror and the principal focus is 15 cm, find the radius of curvature of the mirror. [1]
(c) Draw a ray diagram to show the type of image formed when an object is placed between pole and focus of a concave mirror. [2]
OR
(c) An object 10 cm in size is placed at 100 cm in front of a concave mirror. If its image is formed at the same point where the object is located, find : [2]
(i) focal length of the mirror, and
(ii) magnification of the image formed with sign as per Cartesian sign convention.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/1/1
(a) Torches, search light, vehicles head lights, shaving mirrors, dentist’s mirror, solar furnaces. (any two) [½, ½]
(b) f = 15 cm
R = 2f [½]
R = 2 × 15 cm = 30 cm [½]
(c)
[2]
(Note: ½ mark to be deducted for not drawing the arrows.)
OR
(c) (i) h = +10 cm, u = −100 cm, v = −100 cm
1v + 1u = 1f [½]
1−100 + 1−100 = 1f ⇒ −2100 = 1f
f = −50 cm [½]
Alternate answer for (i): Since u = v, the object is placed at the centre of curvature (C). f = R2 = −1002 = −50 cm
(ii) m = −vu = −(−100)−100 = −1 [½, ½]
Q68.2023 Main 31/4/1 · Q394 marks
The ability of a medium to refract light is expressed in terms of its optical density. Optical density has a definite connotation. It is not the same as mass density. On comparing two media, the one with the large refractive index is optically denser medium than the other. The other medium with a lower refractive index is optically rarer. Also the speed of light through a given medium is inversely proportional to its optical density.
(i) Determine the speed of light in diamond if the refractive index of diamond with respect to vacuum is 2.42. Speed of light in vacuum is 3×108 m/s. [1]
(ii) Refractive indices of glass, water and carbon disulphide are 1.5, 1.33 and 1.62 respectively. If a ray of light is incident in these media at the same angle (say θ), then write the increasing order of the angle of refraction in these media. [1]
(iii) (A) The speed of light in glass is 2×108 m/s and in water is 2.25×108 m/s. [2]
(a) Which one of the two is optically denser and why ?
(b) A ray of light is incident normally at the water-glass interface when it enters a thick glass container filled with water. What will happen to the path of the ray after entering the glass ? Give reason.
OR
(iii) (B) The absolute refractive indices of water and glass are 43 and 32 respectively. If the speed of light in glass is 2×108 m/s, find the speed of light in (i) vacuum and (ii) water. [2]
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/4/1
(i) Refractive index of diamond = Speed of light in vacuumSpeed of light in diamond [½]
Speed of light in diamond = 3 × 108 m/s2.42 = 1.23 × 108 m/s [½]
(ii) r in carbon disulphide < r in glass < r in water [1]
(iii) (A) (a) • Glass [½]
• The speed of light in water is more than the speed of light in glass. / Refractive index of glass is more than the refractive index of water. [½]
(b) Light will enter from water to glass without bending (undeviated / straight) because in this case ∠i = 0 ; ∠r = 0. [1]
nglass = speed of light in vacuum (c)speed of light in glass (vg)
c = nglass × vglass = 32 × 2 × 108 m/s = 3 × 108 m/s [1]
vwater = cnwater = 3 × 108 m/s4/3 = 94 × 108 m/s or 2.25 × 108 m/s [1]
Q69.2023 Main 31/5/1 · Q394 marks
Many optical instruments consist of a number of lenses. They are combined to increase the magnification and sharpness of the image. The net power (P) of the lenses placed in contact is given by the algebraic sum of the powers of the individual lenses P1, P2, P3 … as
P = P1 + P2 + P3 …
This is also termed as the simple additive property of the power of lens, widely used to design lens systems of cameras, microscopes and telescopes. These lens systems can have a combination of convex lenses and also concave lenses.
(a) What is the nature (convergent / divergent) of the combination of a convex lens of power + 4 D and a concave lens of power – 2 D ? [1]
(b) Calculate the focal length of a lens of power – 2·5 D. [1]
(c) Draw a ray diagram to show the nature and position of an image formed by a convex lens of power + 0·1 D, when an object is placed at a distance of 20 cm from its optical centre. [2]
OR
(c) How is a virtual image formed by a convex lens different from that formed by a concave lens ? Under what conditions do a convex and a concave lens form virtual images ? [2]
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/5/1
(a) Convergent [1]
(b) f (m) = 1P = 1– 2.5 = – 0.4 m or – 40 cm [½, ½]
(c)
[2]
OR
(c) • Convex lens – magnified [½]
Concave lens – diminished [½]
• Convex – object between O and F [½]
Concave – object anywhere between optical centre and infinity. [½]
Q70.2023 Main 31/6/1 · Q394 marks
A student took three concave mirrors of different focal lengths and performed the experiment to see the image formation by placing an object at different distances with these mirrors as shown in the following table.
Case No.
Object-distance
Focal length
I
45 cm
20 cm
II
30 cm
15 cm
III
20 cm
30 cm
Now answer the following questions :
(a) List two properties of the image formed in Case I. [1]
(b) In which one of the cases given in the table, the mirror will form real image of same size and why ? [1]
(c) Name the type of mirror used by dentists. Give reason why do they use such type of mirrors. [2]
OR
(c) Look at the table and identify the situation (object distance and focal length) which resembles the situation in which concave mirrors are used as shaving mirrors ? Draw a ray diagram to show the image formation in this case. [2]
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/6/1
(a) Real, inverted, diminished (Any two) [½, ½]
(b) Case II [½]
Because focal length of mirror is 15 cm, object distance is 30 cm which means the object is placed at C. [½]
(c) Dentists use concave mirrors [1]
Because concave mirror forms erect and enlarged image when object is very close to the mirror. [1]
OR
(c) Case III [1]
[1] (Deduct ½ mark if direction of ray is not marked.)
Q71.2023 Supp 31/C/1 · Q394 marks
When a ray of light moving in a medium enters obliquely into another medium, it bends from its path. This phenomenon is called refraction of light. The ability of a medium to refract light is also expressed in terms of optical density. It is not the same as mass density. We use the terms ‘rarer medium’ and ‘denser medium’ which actually means ‘optically rarer medium’ and ‘optically denser medium’ respectively. When we say that a medium ‘A’ is optically denser than the other medium ‘B’, we mean that the refractive index of medium A is more than the refractive index of medium ‘B’. The speed of light is higher in a rarer medium than a denser medium. Thus a ray of light travelling from a rarer medium to a denser medium slows down and bends towards the normal.
(a) Define the term absolute refractive index of a medium. [1]
(b) Absolute refractive indices of water and glass are 43 and 32 respectively.
(i) In which one of the two media is the speed of light more ?
(ii) If a ray of light enters obliquely from glass to water, will it bend towards the normal or away from the normal ? [1]
(c) The absolute refractive indices of water and glass are 43 and 32 respectively. If the speed of light in glass is 2 × 108 m/s, find the speed of light in (i) water and (ii) vacuum. [2]
OR
(c) “A ray of light incident on a rectangular glass slab immersed in any medium emerges parallel to itself.” Draw a labelled ray diagram to justify this statement. [2]
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Official CBSE Marking Scheme · CBSE Board 2023 (Supplementary), Set 31/C/1
(a) The refractive index of a medium with respect to air or vacuum / Absolute refractive index of a medium = speed of light in vacuum / speed of light in medium [1]
(b) (i) speed of light is more in water [½] (ii) bends away from normal [½]
(c) Absolute refractive index of a medium = speed of light in vacuum / speed of light in medium
3/2 = speed of light in vacuum / (2 × 108) [½]
Speed of light in vacuum = 3 × 108 m/s [½]
Speed of light in water = 3/4 × 3 × 108 m/s = 9/4 × 108 m/s [1]
OR
(c)
Diagram [1]; Labelling [1]
Q72.SQP 2025-26 · Q384 marks
The above image is that of a Digital Single Lense Reflector (DSLR) Camera which are used to take high resolution photographs by professional photographers. The second image of the above two is a schematic diagram of how an image is formed on the sensor of the camera. Based on your understanding of the lenses, answer the following questions.
A. What type of lens is used in the DSLR camera shown in the image?
B. What type of image is formed on the sensor?
Attempt either subpart C or D.
C. A photographer is using a DSLR camera with a lens of focal length f = 50 mm to take a close-up photograph of a small object. The lens projects an image onto the camera sensor that is located 60 mm behind the lens. Calculate the object distance (i.e., the distance between the object and the lens).
OR
D. A photographer is using a DSLR camera to take a picture of a flower. The flower is positioned 150 mm away from the camera lens. The actual height of the flower is 80 mm, and the image height formed on the camera’s sensor is measured to be 20 mm. Calculate the focal length of the camera lens.
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Official CBSE Marking Scheme · CBSE Sample Question Paper 2025-26 Marking Scheme
A. Convex Lens
B. Real and Inverted
Student to attempt either subpart C or D.
C. To find the object distance (u) for the lens, we can use the lens formula: 1f = 1v − 1u, where f = 50 mm (focal length), v = 60 mm (image distance), u is the object distance, which we need to calculate. Rearranging the formula to solve for u: 1u = 1v − 1f. Substitute the values: 1u = 160 − 150. Calculate each term: 1u = 50 − 603000 = −103000 = − 1300. Thus, the negative sign indicates that the object is located 300 mm in front of the lens (on the opposite side from the image). So, the object distance is: u = 300 mm
OR
D. image height = − 20 mm, object height = 80 mm. The magnification (m) of the lens is given by m = image heightobject height. Substituting the values: m = −20 mm80 mm = − 14. Thus, the magnification m = − 0.25. Magnification is also given by m = vu, where v is the image distance and u = −150 mm. Rearrange to solve for v: v = m × u = −0.25 × −150 mm = 37.5 mm. So, the image distance v = 37.5 mm.
The lens formula is: 1f = 1v − 1u. Substituting the values of v and u: 1f = 137.5 + 1150. Thus, f = 30 mm.
Answer: The focal length of the camera lens is 30 mm.
Q73.2026 Exam 2 31/8/1 · Q395 marks
(A) (i) In which mirror we can always see the full image of a distant object ? Support your answer by a ray diagram for it.
(ii) A convex mirror forms an erect image of an object of size, one-third of the size of the object. Find the position of the object if the radius of curvature of convex mirror is 30 cm.
OR
(B) (i) Define the optical centre of a lens.
(ii) The light from an object placed on a meter scale at 8 cm mark, was focused on a white screen placed at 92 cm mark, with the help of a converging lens placed on the scale at 50 cm mark :
(I) Find the focal length of converging lens.
(II) Find the position of image if the object is shifted towards the lens and kept at 29 cm mark.
(III) What will be the nature of the image formed if the object is further shifted towards the lens ?
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Official CBSE Marking Scheme · CBSE Board 2026 (2nd Board Examination), Set 31/8/1
(A) (i) Convex Mirror [½]
[2]
(ii) m = + 13; f = R2 = +15 cm [½]
m = −vu [½]; 13 = −vu; v = −u3
1v + 1u = 1f [½]; −3u + 1u = 115 [½]; −2u = 115; u = −30 cm [½]
OR
(B) (i) The central point of a lens through which a ray of light passes without any deviation. [1]
(ii) (I) u = −(50 − 8) = −42 cm [½]; v = (92 − 50) = 42 cm [½]; 1v − 1u = 1f [½]; 142 + 142 = 1f; f = 21 cm [½]
Alternate answer for (I): u = −42 cm, v = 42 cm [½ + ½]. Since object distance is same as image distance, object is placed at 2F1. 2f = 42 cm or f = 21 cm [½ + ½]
(II) u = −(50 − 29) = −21 cm. As now object is kept at focus F1, image will be formed at infinity. [1]
(III) Now, object is kept between Optical centre and focus F1, nature of image is virtual and erect. [1]
Q74.2025 Main 31/1/1 · Q365 marks
(a) (i) The power of a lens ‘X’ is – 2·5 D. Name the lens and determine its focal length in cm. For which eye defect of vision will an optician prescribe this type of lens as a corrective lens ?
(ii) ‘‘The value of magnification ‘m’ for a lens is – 2.’’ Using new Cartesian Sign Convention and considering that an object is placed at a distance of 20 cm from the optical centre of this lens, state :
(I) the nature of the image formed;
(II) size of the image compared to the size of the object;
(III) position of the image, and
(IV) sign of the height of the image.
(iii) The numerical values of the focal lengths of two lenses A and B are 10 cm and 20 cm respectively. Which one of the two will show higher degree of convergence/divergence ? Give reason to justify your answer.
OR
(b) (i) Draw a ray diagram to show the refraction of a ray of light through a rectangular glass slab when it falls obliquely from air into glass.
(ii) State Snell’s law of refraction of light.
(iii) Differentiate between the virtual images formed by a convex lens and a concave lens on the basis of :
(I) object distance, and
(II) magnification.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/1/1
(a) (i)
Concave lens [½]
P = 1f (m) [½]
– 2·5 = 1f
f = 1– 2·5 m = – 0·4 m = – 40 cm [½]
Myopia [½]
(ii) (I) Real and inverted
(II) Magnified image / size of image is double the size of object
(III) Beyond 2F / on the other side as that of object
(IV) Negative [½ × 4]
(iii) The lens with focal length 10 cm [½]
Less focal length, more converging/diverging power [½]
OR
(b) (i)
[2] (if arrows not marked, deduct half mark)
(ii) The ratio of sine of angle of incidence to the sine of angle of refraction is a constant, for the light of a given colour and for a given pair of media. / sin isin r = constant [1]
(iii)
Convex Lens
Concave Lens
(I) Object to be placed between O and F
Object can be placed anywhere in front of the lens
(II) Magnified image
Diminished image
[1]
Q75.2025 Main 31/3/1 · Q365 marks
(a) (i) “In refraction of light through a rectangular glass slab, the emergent ray is always parallel to the direction of the incident ray.” Why ? Explain with the help of a ray diagram. What happens when a ray of light falls normally on one of the faces of a rectangular glass prism ? Draw diagram.
(ii) An object is placed at a distance of 30 cm from the optical centre of a concave lens of focal length 20 cm. Use Lens formula to determine the position of the image formed in this case.
OR
(b) (i) A student wishes to study the image formation by a concave mirror using candle flame as object. State the type of the image formed by the mirror and mention the change in the image formed, if any, that he observes when the candle flame is gradually moved away from the pole of the mirror. Draw a ray diagram to show the image formation when the object distance is nearly equal to the radius of curvature of the mirror.
(ii) A convex mirror used for rear-view on an automobile has a focal length of 3·0 m. If a bus is located at 6·0 m from this mirror, use mirror formula to find the position of the image of the bus as seen in the mirror.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/3/1
(a) (i) The extent of bending of the ray of light at the opposite parallel faces of the rectangular glass slab is equal and opposite. This is why the ray emerges parallel to the incident ray. [1]
[1]
NORMAL INCIDENCE
/
[1]
(ii) u = – 30 cm, f = – 20 cm
1v – 1u = 1f or 1v = 1u + 1f [½]
1v = 1– 30 cm + 1– 20 cm [½]
= 1– 12 cm or v = – 12 cm [1]
The image is at – 12 cm on the same side of the lens.
OR
(b) (i) Type of image: Real and inverted (when candle is beyond F) / Virtual and erect (when candle is between P and F) [1]
As the object is moved gradually away from the pole of the mirror, the image gets diminished. [1]
[1]
(ii) Object distance, u = – 6·00 m; Image distance, v = ?; Focal length, f = 3·00 m
1v + 1u = 1f or 1v = 1f – 1u [½]
1v = 1+ 3·00 m – 1(– 6·00 m) [½]
= 1+ 3·00 m + 16·00 m = 2 + 16 m [½]
or v = 63 = 2·0 m
Q76.2025 Main 31/5/1 · Q365 marks
(A) (a) Observe the following diagram and compare (i) speed of light and (ii) optical densities of the three media A, B and C. Also give justification for your answer of any one of the two cases in terms of refractive indices of A, B and C.
(b) Redraw the path of a ray of light through the three media, if the ray of light starting from medium A falls on the medium B
(i) Obliquely and the optical density of medium B is made more than that of A and C.
(ii) The ray falls normally from medium A to medium B.
OR
(B) Analyse the following observation table showing variation of image distance (v) with object distance (u) in case of a convex lens and answer the questions that follow without doing any calculations :
Observation Number
Object distance (u) in cm
Image distance (v) in cm
1
–15
–60
2
–25
+100
3
–30
+60
4
–40
+40
5
–60
+30
6
–100
+25
(a) Determine the focal length of the lens. Give reason for your answer.
(b) Find magnification of the image formed in Observation No. 3.
(c) The numerical value of magnifications in cases of observation 1 and 2 is same. List two differences in the images formed in these two cases.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/5/1
(A) (a) (i) Speed of light in A and B is same whereas the speed of light in C is greater than that of A and B. [1]
(ii) Optical density of A and B is same whereas optical density of C is less than that of A and B. [1]
Since the ray of light does not bend while passing from A to B the refractive indices of A and B are same and since it bends away from the normal while passing from B to C the refractive index of C is less than that of A and B. / Refractive index of a medium is inversely proportional to the speed of light in that medium. [1]
(b) (i) Oblique Incidence
[1]
(ii) Normal Incidence
[1]
OR
(B) (a) 2f = 40 cm ⇒ f = 20 cm [1]
Reason: When an object is placed at 2f (– 40 cm) of a convex lens its real image formed at 2f (+ 40 cm) on the other side of the lens. [1]
(b) m = vu = +60 cm–30 cm = – 2 [1]
(c) Observation No. 1 – image is virtual and erect [1]
Observation No. 2 – image is real and inverted [1]
Q77.2024 Main 31/2/1 · Q365 marks
(a) Upper half of a convex lens is covered with a black paper. Draw a ray diagram to show the formation of image of an object placed at a distance of 2F from such a lens. Mention the position and nature of the image formed. State the observable difference in the image obtained if the lens is uncovered. Give reason to justify your answer.
(b) An object is placed at a distance of 30 cm from the optical centre of a concave lens of focal length 15 cm. Use lens formula to determine the distance of the image from the optical centre of the lens.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/2/1
(a)
[1] Note: Any one of the above drawn ray diagrams should be marked.
When the upper half of lens is covered:
• Position of image: at 2F on the other side of the lens [½]
• Nature of image: Real and inverted [½]
• Observable difference in the image, if the lens is uncovered: The brightness of the image will increase [½]
• Reason: More number of rays will pass through the lens to form the image. [½]
(b) Here u = − 30 cm, f = − 15 cm, v = ? [½]
1v − 1u = 1f [½]
1v = 1f + 1u = 1−15 + 1−30
v = − 10 cm [1]
Q78.2024 Main 31/3/1 · Q365 marks
(a) (i) Draw a ray diagram to show the path of the refracted ray in each of the following cases :
A ray of light incident on a concave lens
(1) parallel to its principal axis, and
(2) is directed towards its principal focus.
(ii) A 4 cm tall object is placed perpendicular to the principal axis of convex lens of focal length 24 cm. The distance of object from the lens is 16 cm. Find the position and size of image formed.
OR
(b) (i) Draw a ray diagram to show the path of the reflected ray in each of the following cases :
A ray of light incident on a convex mirror
(1) parallel to its principal axis, and
(2) is directed towards its principal focus
(ii) A 1.5 cm tall candle flame is placed perpendicular to the principal axis of a concave mirror of focal length 12 cm. If the distance of the flame from the pole of the mirror is 18 cm, use mirror formula to determine the position and size of the image formed.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/3/1
(a) (i) (1)
[1] (Fig. 9.13(b), page 153, NCERT)
(2)
[1] (Fig. 9.14(b), page 154, NCERT) (Note: Deduct half mark if directions of rays are not shown)
(ii) Given u = −16 cm, f = + 24 cm, h = 4 cm [½]
Formula used: 1v − 1u = 1f [½]
∴ 1v − 1(−16) = 1+ 24; 1v = −148
v = − 48 cm [1]
Image is formed on the same side as the object [½]
m = h′h = vu; h′4 = −48−16; h′ = 12 cm [½ + ½]
OR
(b) (i) (1)
[1]
(2)
[1] (Note: Deduct half mark if directions of rays are not shown)
(ii) Here f = − 12 cm, u = − 18 cm, v = ?, h = 1·5 cm, h′ = ? [½]
Mirror formula 1v + 1u = 1f [½]; 1v = 1f − 1u = 1−12 cm − 1−18 cm = −136
v = − 36 cm [1]
m = h′h = − vu [½]; h′1.5 = − (−36)(−18); h′ = − 3·0 cm [½]
Q79.2024 Main 31/4/1 · Q365 marks
(a) The variation of image distance (v) with object distance (u) for a convex lens is given in the following observation table. Analyse it and answer the questions that follow :
S. No.
Object distance (u) cm
Image distance (v) cm
1
− 150
+ 30
2
− 75
+ 37·5
3
− 50
+ 50
4
− 37·5
+ 75
5
− 30
+ 150
6
− 15
+ 37·5
(i) Without calculation, find the focal length of the convex lens. Justify your answer.
(ii) Which observation is not correct ? Why ? Draw ray diagram to find the position of the image formed for this position of the object.
(iii) Find the approximate value of magnification for u = − 30 cm.
OR
(b) (i) Define principal axis of a lens. Draw a ray diagram to show what happens when a ray of light parallel to the principal axis of a concave lens passes through it.
(ii) The focal length of a concave lens is 20 cm. At what distance from the lens should a 5 cm tall object be placed so that its image is formed at a distance of 15 cm from the lens ? Also calculate the size of the image formed.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/4/1
(a)
(i) S. No. 3, 2f is 50 cm. ∴ 2f = 50 cm, or f = 25 cm. [1]
Justification: Object distance (u) and image distance (v) are same so it implies that object is placed at 2F. [1]
(ii) S. No. 6, is not correct. [½]
Reason: For u = −15 cm, sign of v must be – ve (as the image is formed on the same side of the lens as the object) [½]
[1] (deduct ½ mark if the direction of the rays are not shown)
(iii) Magnification : m = vu = + 150 cm− 30 cm = −5 [1]
OR
(b)
(i) Principal axis : It is an imaginary line passing through the two centres of curvatures of a lens. [1]
or u = − 60 cm, object is at a distance of 60 cm from the lens
• Size of the image (magnification): m = h′h = vu [1]
h′ = vu × h = (−15)(−60) × 5 = 1·25 cm [1]
Q80.2023 Main 31/2/1 · Q365 marks
(a) An object is placed in front of a convex lens of focal length f. If the distance of the object from the lens is 2f, draw a ray diagram to show the formation of the image. Write the value of magnification in this case.
(b) A student has focussed the image of a candle flame on a white screen using a convex lens. The situation is as given below :
Length of the flame = 2 cm Focal length of the lens = 12 cm Distance of the flame from the lens = 16 cm
If the flame is perpendicular to the principal axis of the lens, calculate the values of the following :
(i) Distance of the image from the lens
(ii) Length of the image formed
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/2/1
(a)
[1½] (Deduct ½ mark for not marking arrows)
Magnification = −1 [½]
(b) (i) u = −16 cm; f = +12 cm [½]
Formula 1v − 1u = 1f [½]
Substitution: 1v = 1u + 1f = 1−16 cm + 112 cm = +148 cm [½]
Result: v = +48 cm [½]
(Award full marks if data not written but calculations are correct)
(ii) hi = vu × ho [½]
= +48 cm−16 cm × 2 cm [½]
= −6 cm [½]
Image is 6 cm in size. [½]
Unit I · Light
2. The Human Eye and the Colourful World
Q1.2026 Main 31/1/1 · Q311 mark
When you look at an object very close to your eyes, the :
Ciliary muscles of your eye contract and the eye lens becomes thick.
Ciliary muscles of your eye get relaxed and the eye lens becomes thick.
Ciliary muscles of your eye contract and the eye lens becomes thin.
Ciliary muscles of your eye get relaxed and the eye lens becomes thin.
(A) Ciliary muscles of your eye contract and the eye lens become thick [1]
Q2.2026 Main 31/1/1 · Q321 mark
Directions : For question number 32, two statements are given, one labelled as Assertion (A) and the other is labelled as Reason (R). Select the correct answer to this question from the codes (A), (B), (C) and (D) as given below :
Both, Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
Both, Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.
Assertion (A) : When rays of white light pass through a prism, on emerging they give spectrum of seven colours.
Reason (R) : It is due to the scattering of light that red light bends minimum and violet light bends the maximum.
(C) Assertion (A) is true, but Reason (R) is false. [1]
Q3.2026 Main 31/2/1 · Q311 mark
A thin beam of white light falls on a face of a glass prism and a spectrum is obtained on a screen. Which of the following options is the correct sequence of colours from top to bottom on the screen ?
An old person is suffering from an eye defect caused by weakening of ciliary muscles and diminishing flexibility of the eye lens. If the defect of vision is ‘a’ which can be corrected by lens ‘b’, then ‘a’ and ‘b’ respectively are :
hypermetropia and convex lens
presbyopia and bifocal lens
myopia and concave lens
myopia and bifocal lens
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/1/1
B. presbyopia and bifocal lens [1]
Q9.2025 Main 31/2/1 · Q131 mark
In the given figure the angle of incidence and the angle of deviation respectively are :
1 and 5
7 and 6
7 and 4
1 and 6
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/2/1
D. 1 and 6 [1]
Q10.2025 Main 31/3/1 · Q121 mark
When a beam of white light passes through a region of very fine dust particles, the colour of light that scatters the most in that region is :
red
orange
blue
yellow
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/3/1
C. blue [1]
Q11.2025 Main 31/4/1 · Q201 mark
Question Nos. 17 to 20 consist of two statements – Assertion (A) and Reason (R). Answer these questions selecting the appropriate option (a), (b), (c) and (d) as given below :
Both, Assertion (A) and Reason (R) are true, and Reason (R) is the correct explanation of Assertion (A).
Both, Assertion (A) and Reason (R) are true, and Reason (R) is not the correct explanation of Assertion (A).
Reason (R) : Ciliary muscles control the power of the eye lens.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/4/1
(d) Assertion (A) is false but Reason (R) is true. [1]
Q12.2025 Main 31/5/1 · Q141 mark
The possible way to restore clear vision of those people whose eyeball has elongated is the use of suitable
bifocal lens
concave lens
converging lens
convex lens
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/5/1
(B) Concave lens [1]
Q13.2025 Main 31/6/1 · Q141 mark
The part of human eye which controls the amount of light entering into it.
Iris
Cornea
Ciliary muscles
Pupil
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/6/1
(D) Pupil [1]
Q14.2025 Supp 31/S/1 · Q201 mark
Assertion (A) : Due to scattering of sunlight, the clear sky predominantly appears blue.
Reason (R) : The wavelength of blue light is nearly 1·8 times the wavelength of red light.
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.
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Official CBSE Marking Scheme · CBSE Board 2025 (Supplementary), Set 31/S/1
(C) Assertion (A) is true, but Reason (R) is false.
Q15.2024 Main 31/1/1 · Q131 mark
The lens system of human eye forms an image on a light sensitive screen, which is called as :
Cornea
Ciliary muscles
Optic nerves
Retina
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/1/1
(d) Retina
Q16.2024 Main 31/1/1 · Q201 mark
Assertion (A) : The rainbow is a natural spectrum of sunlight in the sky.
Reason (R) : Rainbow is formed in the sky when the sun is overhead and water droplets are also present in air.
For Q. Nos. 17 to 20, two statements are given – One labelled as Assertion (A) and the other labelled as Reason (R). Select the correct answer to these questions from the codes (a), (b), (c) and (d) as given below :
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/1/1
(c) Assertion (A) is true, but Reason (R) is false.
Q17.2024 Main 31/2/1 · Q131 mark
Consider the following statements in the context of human eye :
(a) The diameter of the eye ball is about 2.3 cm.
(b) Iris is a dark muscular diaphragm that controls the size of the pupil.
(c) Most of the refraction for the light rays entering the eye occurs at the crystalline lens.
(d) While focusing on the objects at different distances the distance between the crystalline lens and the retina is adjusted by ciliary muscles.
The correct statements are –
(a) and (b)
(a), (b) and (c)
(b), (c) and (d)
(a), (c) and (d)
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/2/1
(A) (a) and (b)
Q18.2024 Main 31/2/1 · Q191 mark
Q. Nos. 17 to 20 are Assertion – Reason based questions : These questions consist of two statements – Assertion (A) and Reason (R). Answer these questions selecting the appropriate option given below :
Assertion (A) : Myopic eye cannot see distant objects distinctly.
Reason (R) : For the correction of myopia converging lenses of appropriate power are prescribed by eye-surgeons.
Both (A) and (R) are true and (R) is the correct explanation of (A).
Both (A) and (R) are true, but (R) is not the correct explanation of (A).
(A) is true, but (R) is false.
(A) is false, but (R) is true.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/2/1
(C) Assertion (A) is true, but Reason (R) is false.
Q19.2024 Main 31/3/1 · Q131 mark
The Phenomena of light involved in the formation of a rainbow in the sky are
Refraction, dispersion and reflection
Refraction, dispersion and total internal reflection
Dispersion, scattering and reflection
Dispersion, refraction and internal reflection
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/3/1
(D) Dispersion, refraction and internal reflection
Q20.2024 Main 31/3/1 · Q191 mark
Q. Nos. 17 to 20 consists of two statements – Assertion (A) and Reason (R), answer these questions selecting the appropriate option given below :
Assertion (A) : Red light signals are used to stop the vehicles on the road.
Reason (R) : Red coloured light is scattered the most so as to be visible from a large distance.
Both (A) and (R) are true and (R) is the correct explanation of (A).
Both (A) and (R) are true and (R) is not correct explanation of (A).
(A) is true, but (R) is false.
(A) is false, but (R) is true.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/3/1
(C) Assertion (A) is true, but Reason (R) is false
Q21.2024 Main 31/4/1 · Q121 mark
When a beam of white light passes through a region having very fine dust particles, the colour of light mainly scattered in that region is :
Red
Orange
Blue
Yellow
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/4/1
(C) Blue
Q22.2024 Main 31/5/1 · Q121 mark
The phenomena of light involved in the formation of rainbow are :
Refraction, reflection and dispersion
Refraction, dispersion and internal reflection
Reflection, dispersion and internal reflection
Refraction, dispersion, scattering and total internal reflection
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/5/1
(B) Refraction, Dispersion and internal reflection
Q23.2023 Main 31/2/1 · Q191 mark
For Questions number 17 to 20, two statements are given – one labelled as Assertion (A) and the other labelled as Reason (R). Select the correct answer from the codes (a), (b), (c) and (d) as given below.
Assertion (A) : A person suffering from myopia cannot see the distant objects clearly.
Reason (R) : A converging lens is used for the correction of myopic eye as it can form real as well as virtual images of the objects placed in front of it.
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/2/1
(c) [1]
Q24.2023 Main 31/6/1 · Q131 mark
In the following diagram showing dispersion of white light by a glass prism, the colours ‘P’ and ‘Q’ respectively are –
Red and Violet
Violet and Red
Red and Blue
Orange and Green
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/6/1
(b)
Q25.2023 Main 31/6/1 · Q161 mark
In human eye the part which allows light to enter into the eye is –
Retina
Pupil
Eye lens
Cornea
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/6/1
(d)
Q26.2023 Supp 31/C/1 · Q131 mark
When a narrow beam of white light passes through a glass prism it splits into its component colours ? This phenomenon is called :
Diffusion of light
Total reflection of light
Scattering of light
Dispersion of light
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Official CBSE Marking Scheme · CBSE Board 2023 (Supplementary), Set 31/C/1
(d)
Q27.2023 Supp 31/C/1 · Q201 mark
For Questions number 17 to 20, two statements are given – one labelled as Assertion (A) and the other labelled as Reason (R). Select the correct answer to these questions from the codes (a), (b), (c) and (d) as given below.
Assertion (A) : A rainbow is an artificial spectrum of white light appearing in the sky after a rain shower.
Reason (R) : The water droplets act like small prisms.
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.
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Official CBSE Marking Scheme · CBSE Board 2023 (Supplementary), Set 31/C/1
(d)
Q28.SQP 2025-26 · Q311 mark
Choose the correct option from the below which explains the reason for us to perceive the day sky as blue.
As sunlight passes through the atmosphere, shorter wavelengths, such as blue are scattered more than other colors.
The sky appears blue because all colors are scattered equally, but blue light is stronger and more visible to the human eye.
The blue color of the sky is due to longer wavelengths like red and orange scattering more than shorter wavelengths, making blue stand out more.
The atmosphere contains blue-colored particles that give the sky its blue appearance.
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Official CBSE Marking Scheme · CBSE Sample Question Paper 2025-26 Marking Scheme
A. As sunlight passes through the atmosphere, Rayleigh scattering causes shorter wavelengths, such as blue and violet, to scatter more than other colors, but our eyes are more sensitive to blue than violet.
Q29.2026 Exam 2 31/8/1 · Q332 marks
(A) What is meant by scattering of light ? How do our observations differ when white light (sun light) is scattered from (i) very fine particles of the medium and (ii) very large particles of the medium ?
OR
(B) With the help of a ray diagram, explain a phenomenon of formation of spectrum in nature.
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Official CBSE Marking Scheme · CBSE Board 2026 (2nd Board Examination), Set 31/8/1
(A) The phenomenon in which a part of light incident on a particle is redirected in different directions is called scattering of light. [1]
(i) Shorter wavelength (blue light) is scattered. [½]
(ii) White light is scattered. [½]
OR
(B)
[1]
A rainbow is a natural spectrum appearing in sky after a rain shower. The tiny water droplets present in atmosphere act like small prisms. They refract and disperse the incident sunlight, they reflect it internally and finally refract it again when it comes out of rain drop. Due to the dispersion of light and internal reflection, different colours reach the observer’s eye. [1]
Q30.2026 Main 31/2/1 · Q342 marks
Attempt either (a) or (b) :
(a) How does the focal length of eye lens change as the distance of the object from the eyes is altered ? Explain.
OR
(b) Why is the concave lens used as a corrective lens for a myopic eye ?
(a) • If the distance of the object from the eye is increased, ciliary muscles relax, lens becomes thin and so the focal length increases. [1]
• If the distance between the object from the eye is decreased, the ciliary muscles contract, lens becomes thick and the focal length decreases. [1]
OR
(b) In myopic eye image is formed in front of the retina. A concave lens / diverging lens of suitable power will bring the image back on to the retina. [2]
Q31.2026 Main 31/3/1 · Q342 marks
Attempt either (a) or (b) :
(a) What happens when light is scattered from (i) very fine particles and (ii) very large size particles of medium ? Justify your answer in each case.
OR
(b) With the help of a ray diagram, explain any phenomenon of formation of spectrum in nature.
(a) (i) Mainly blue coloured light is scattered because very fine particles scatter shorter wavelength. [1]
(ii) Scattered light may appear white because very large size particles scatter light of all wavelengths. [1]
OR
(b) [1]
A natural spectrum like rainbow is formed when sunlight passes through tiny water droplets present in the atmosphere. The water droplets disperse the incident light ray, then reflect it internally and finally refract it again when it comes out of the raindrop. (any other phenomenon of spectrum in nature) [1]
Q32.2026 Main 31/5/1 · Q342 marks
(A) (i) How does the change in curvature of the eye lens helps us in the process of seeing the nearby objects clearly ?
(ii) State the range of the power of accommodation of a normal human eye.
OR
(B) Draw a ray diagram to show the correction of eye defect of an old man who can not see an object placed closer than 1 m from his eye, clearly.
(A) (i) While looking at objects nearer to eye, the curvature of the eye lens increases. Consequently, the focal length of the eye lens decreases. [1]
(ii) From 25 cm (near point) to infinity (far point) [1]
OR
(B) [2]
(Deduct ½ mark for not showing the direction of light)
Q33.2025 Main 31/3/1 · Q252 marks
(a) A student has difficulty in reading his textbooks but can read the blackboard clearly while sitting in the last row. Name the defect of vision the student is suffering from. List two reasons due to which this defect arises. Write the nature of the lenses required to correct this defect.
OR
(b) Draw a ray diagram to show the path of a ray of light falling obliquely on one of the refracting faces of a triangular glass prism and mark the angle of deviation on it.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/3/1
Diagram [1]; Direction of rays [½]; Marking of angle [½]
Q34.2025 Main 31/4/1 · Q252 marks
(A) Draw a ray diagram to show the refraction of a ray of light passing through an equilateral glass prism. Mark the angle through which the emergent ray bends from the direction of the incident ray and also name it.
OR
(B) Name the type of lenses required by the persons for the correction of their defect of vision called presbyopia. Write the structure of the lenses commonly used for the correction of this defect giving reason for such designs.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/4/1
(A)
(one mark for diagram and ½ for labelling.) [1½]
Angle of deviation [½]
OR
(B) I.
Bi-focal lens. [½]
Bi-focal lens having upper portion consists of a concave lens and lower portion consists convex lens. [1]
to facilitate the distant and near vision respectively. [½]
OR
II. convex lens. [½]
Convex lens is thickened at the middle as compared to edges [1]
to facilitate the near vision. [½]
(either of I or II)
Q35.2025 Main 31/6/1 · Q252 marks
(a) Give reasons :
(i) The sky appears dark to passengers flying at very high altitude.
(ii) ‘Danger’ signal lights are red in colour.
OR
(b) What is a rainbow ? “We see a rainbow in the sky only after the rainfall.” Why ?
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/6/1
(a) (i) Scattering of light is not prominent at such heights. [1]
(ii) The red colour is least scattered by smoke or fog. / Red colour has longer wavelength. [1]
OR
(b) • Rainbow is a natural spectrum appearing in the sky after a rain shower. [1]
• After rain, small water droplets act as a tiny prism, when light enters, it gets refracted and dispersed. [1]
Q36.2025 Supp 31/S/1 · Q262 marks
Draw a ray diagram to show the path of a ray of light which falls obliquely on one of the faces of an equilateral triangular prism made of glass and mark on it the angle of incidence (i) and the angle of deviation (D).
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Official CBSE Marking Scheme · CBSE Board 2025 (Supplementary), Set 31/S/1
Ray diagram [1]; Labelling ∠i and ∠D [½ + ½]
Q37.2024 Main 31/3/1 · Q242 marks
When do we say that a particular person is suffering from hypermetropia ? List two causes of this defect. Name the type of lens used to correct this defect.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/3/1
• When he cannot see nearby objects distinctly but can see far object clearly. [½]
• 2 causes: Focal length of the eye lens is too long. [½] Eyeball becomes too small. [½]
• Convex or Converging lens [½]
Q38.2024 Main 31/4/1 · Q252 marks
A person suffering from presbyopia needs bifocal lens. If he needs two lens of power − 4·0 dioptre and + 2·0 dioptre, which one of these two lenses is for the correction of distant vision and what is its focal length ?
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/4/1
• For distant vision: lens of power − 4·0 dioptre [1]
• f (metre) = 1P = 1−4·0 D = −0.25 m or −25 cm [1]
Q39.2024 Supp 31/S/1 · Q252 marks
(a) Draw a ray diagram to show the formation of a rainbow in the sky. Mark on the diagram three points A, B and C as given below :
A – where dispersion of light occurs
B – where internal reflection of dispersed light occurs
C – where refraction of dispersed light occurs
OR
(b) Name the muscles present in the human eye which enable it to focus on objects at varied distances (i.e., distant as well as nearby objects). Explain how it happens.
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Official CBSE Marking Scheme · CBSE Board 2024 (Supplementary), Set 31/S/1
(a)
Diagram [½]; Correct labelling of A, B and C [1½]
OR
(b)
• Ciliary muscles [1]
• Ciliary muscles adjust/change the focal length of eye lens by changing the curvature of eye lens. [1]
Q40.2023 Main 31/1/1 · Q252 marks
(a) A narrow beam XY of white light is passing through a glass prism ABC as shown in the diagram :
Trace it on your answer sheet and show the path of the emergent beam as observed on the screen PQ.
Name the phenomenon observed and state its cause.
OR
(b) It is observed that the power of an eye to see nearby objects as well as far off objects diminishes with age.
(i) Give reason for the above statement.
(ii) Name the defect that is likely to arise in the eyes in such a condition.
(iii) Draw a labelled ray diagram to show the type of corrective lens used for restoring the vision of such an eye.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/1/1
(a)
[1] for the diagram
Dispersion of white light [½]
Cause: Different colours of light bend through different angles w.r.t. the incident ray. / Different colours have different wavelengths. [½]
OR
(b) (i) It is due to gradual weakening of the ciliary muscles and diminishing flexibility of the eye lens. [½, ½]
(a) When and where does a rainbow appear in the sky ? Draw a labelled ray diagram to show its formation.
OR
(b) What is scattering of light ? Why does the clear sky appear blue ?
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/2/1
(a) • It is formed after a rain shower. [½]
• It is always formed in a direction opposite to that of the Sun. [½]
[1]
OR
(b) (i) The phenomenon of the change in direction of propagation of light caused by large sized molecules / caused by colloidal particles. [1]
(ii) When sunlight passes through the atmosphere, fine particles in the air scatter blue light (shorter wavelengths) more than the red colour (longer wavelengths). [1]
Q42.2023 Main 31/4/1 · Q252 marks
(A) Observe the following diagram and answer the questions following it :
(i) Identify the defect of vision shown.
(ii) List its two causes.
(iii) Name the type of lens used for the correction of this defect.
OR
(B) The colour of clear sky from the earth appears blue but from the space it appears black. Why ?
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/4/1
(A) (i) Myopia / Short sightedness [½]
(ii) • Excessive curvature of eye lens [½]
• Elongation of eye ball [½]
(iii) Concave lens / Diverging lens [½]
OR
(B) • Size of particles in the atmosphere is smaller than the wavelength of visible light, so they scatter light of shorter wavelengths i.e. blue. [1]
• In space, there is no scattering of light due to absence of particles. (no atmosphere) [1]
Q43.2023 Main 31/5/1 · Q252 marks
Observe the following diagram showing an image formation in an eye :
(a) Identify the defect of vision shown in the figure.
(b) List its two causes and suggest a suitable corrective lens to overcome this defect.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/5/1
(a) Hypermetropia / Far sightedness [½]
(b) • Focal length is too long [½]
• Size of eyeball is small. [½]
Convex lens / Converging lens [½]
Q44.2026 Exam 2 31/7/1 · Q353 marks
State the reasons for myopia. With the help of a ray diagram, show the :
(a) Image formation by myopic eye, and
(b) Correction of myopic eye by using an appropriate lens.
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Official CBSE Marking Scheme · CBSE Board 2026 (2nd Board Examination), Set 31/7/1
Reasons : (i) Excessive curvature of eye lens (ii) Elongation of eye ball [½ + ½]
(a) Myopic eye [1]
(b) Correction [1]
Q45.2026 Exam 2 31/7/1 · Q363 marks
What is meant by atmospheric refraction of light ? Explain the following natural phenomenon by using the concept of atmospheric refraction :
(a) Twinkling of stars
(b) Flickering of objects seen through a turbulent stream of hot air
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Official CBSE Marking Scheme · CBSE Board 2026 (2nd Board Examination), Set 31/7/1
Refraction of light by the earth’s atmosphere due to variation in optical density of different layers of air is called as atmospheric refraction. [1]
(a) The starlight, on entering the earth’s atmosphere undergoes refraction continuously in a medium of gradually increasing refractive index and we see the apparent position of the star. Since the physical conditions of atmosphere are not stationary, the apparent position of the star fluctuates and gives twinkling effect. [1]
(b) The air just above the fire becomes hotter than the air further up. The hotter air is lighter (less dense) than cooler air above it and has a refractive index slightly less than that of cooler air. Since the physical conditions of refracting medium are not stationary, the apparent position of objects, as seen through hot air fluctuates. And we see flickering objects. [1]
Q46.2026 Exam 2 31/8/1 · Q363 marks
(A) The elderly people, may have both near sightedness and far sightedness. Write the possible solutions, can be proposed for correction of their eye defect.
(B) How does the eye control the amount of light entering into it ?
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Official CBSE Marking Scheme · CBSE Board 2026 (2nd Board Examination), Set 31/8/1
(A) (i) They either use two sets of spectacles one for correcting Near sightedness and other for correcting farsightedness [1]
(ii) Use bifocal spectacles / use progressive lenses. [1]
(B) The pupil regulates and controls the amount of light entering the eye. The size of pupil is regulated by Iris (a muscular diaphragm). [1]
Q47.2026 Main 31/1/1 · Q353 marks
A person is unable to read a book placed closer than 1 meter from his eyes. Identify the defect of vision in his eyes. Draw the ray diagrams to show the defect of vision and its correction.
• The phenomenon of spreading light in different directions on interaction with particles of the medium. [1]
• Light bounces back in a fixed direction after reflection while in scattering of light, it spreads in different directions. / Reflection of light is independent of the size of reflecting particles whereas the colour of the scattered light depends upon the size of scattering particles. [2]
Q49.2026 Main 31/3/1 · Q353 marks
Study the given diagram and answer the questions that follow :
(a) Write the name of the eye defect shown in the diagram. Where is the image formed in this eye defect with respect to the retina of the eye ?
(b) List two causes of this eye defect.
(c) With the help of a diagram, show how this eye defect of vision is corrected.
Rainbow is caused by dispersion of sunlight by tiny water droplets, present in the atmosphere. The water droplets act like small prisms. They refract and disperse the incident sunlight, then reflect it internally, and finally refract it again when it comes out of the raindrop. [2]
[1]
Q51.2026 Main 31/5/1 · Q353 marks
(a) Draw the ray diagram for refraction of light through a glass prism and mark angle of refraction and angle of deviation.
(b) When the path of a light ray refracted through a glass prism is reversed how will the angle of deviation change ? Explain.
• The ray of light will retrace its original path. [½]
Q52.2025 Main 31/3/1 · Q313 marks
What is a rainbow ? Draw a labelled diagram to show its formation.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/3/1
A rainbow is a natural spectrum appearing in the sky after a rain shower. [1]
[2] (Deduct half mark if arrows are not marked)
Q53.2025 Main 31/6/1 · Q323 marks
A person uses lenses of +2.0 D power in his spectacles for the correction of his vision.
(a) Name the defect of vision the person is suffering from.
(b) List two causes of this defect.
(c) Determine the focal length of the lenses used in the spectacles.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/6/1
(a) Hypermetropia [1]
(b) Two causes:
• Eye ball has become too small / Eye ball is shortened
• The focal length of the eye lens is long / eye lens becomes less convergent [½ × 2]
(c) Focal length = 1P [½]
= 12 = + 0.5 m [½]
Q54.2024 Main 31/1/1 · Q313 marks
Study the diagram given below and answer the questions that follow :
(i) Name the defect of vision represented in the diagram. Give reason for your answer.
(ii) List two causes of this defect.
(iii) With the help of a diagram show how this defect of vision is corrected.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/1/1
(i) Hypermetropia or Far-sightedness. [½]
Reason – Image is formed behind the retina. / Near point for the person is farther away from the normal near point (25 cm) [½]
(ii) • Focal length of the eye lens is too long. [½] • The eyeball has become too small. [½]
(iii)
N = Near point of a hypermetropic eye; N′ = Near point of a normal eye [1]
Q55.2024 Main 31/2/1 · Q313 marks
(a) Define the term power of accommodation of human eye. Write the name of the part of eye which plays a major role in the process of accommodation and explain what happens when human eye focuses (i) nearby objects and (ii) distant objects.
OR
(b) Draw a ray diagram to show the formation of a rainbow in the sky. On this diagram mark A – where dispersion of light occurs, B – where internal reflection of light occurs and C – where refraction of light occurs. List two necessary conditions to observe a rainbow.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/2/1
(a) • Ability of the eye lens to adjust its focal length. [1]
• Ciliary muscles [1]
• (i) While focusing on nearby objects ciliary muscles contract, eye lens becomes thick and its focal length decreases. [½]
(ii) While focusing on distant objects ciliary muscles relax, eye lens becomes thin and its focal length increases. [½]
• Two conditions: (i) Presence of tiny water droplets in the atmosphere. [½] (ii) Position of Sun at the back (behind) the observer. [½]
Q56.2024 Main 31/3/1 · Q313 marks
Name and explain the phenomenon of light due to which the path of a beam of light becomes visible when it enters a smoke filled room through a small hole. Also state the dependence of colour of the light we receive on the size of the particle of the medium through which the beam of light passes.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/3/1
• Scattering of light / Tyndall effect [1]
• When a beam of light strikes fine particles of smoke, it is reflected diffusely and the path of the light becomes visible. [1]
• Very fine particles scatter mainly blue light/short wavelength colours while the particles of larger size scatter longer wavelength colours. [1]
Q57.2024 Main 31/4/1 · Q313 marks
Define the term power of accommodation of human eye. What happens to the image distance in the eye when we increase the distance of an object from the eye ? Name and explain the role of the part of human eye responsible for it in this case.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/4/1
• Ability of the eye lens to adjust its focal length. [1]
• Image distance remains unchanged [1]
• Ciliary muscles – [½]
• While focusing on distant objects ciliary muscles relax, eye lens becomes thin and its focal length increases. [½]
Q58.2024 Main 31/5/1 · Q313 marks
(a) Study the diagram given below and answer the questions that follow :
(i) Name the defect of vision depicted in this diagram stating the part of the eye responsible for this condition.
(ii) List two causes of this defect.
(iii) Name the type of lens used to correct this defect and state its role in this case.
OR
(b) What is dispersion of white light ? State its cause. Draw a diagram to show dispersion of a beam of white light by a glass prism.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/5/1
(ii) • Focal length of the eye lens is too long. [½] • Eyeball becomes too small. [½]
(iii) Converging lenses / convex lens [½]. They provide the additional focussing power required for forming the image on the retina. / Helps to decrease the focal length of the eye lens. [½]
OR
(b) The splitting of white light into its constituent colours is called dispersion. [1]
Cause: Different colours of white light bend through different angles with respect to incident ray. [1]
[1]
Q59.2024 Supp 31/S/1 · Q333 marks
Draw a ray diagram to show the refraction of a ray of light through a triangular glass prism and mark on it (i) angle of incidence (i), (ii) angle of emergence (e), and (iii) angle of deviation (D). What would happen, if instead of a ray, a beam of white light falls on the prism ? Give reason for the phenomenon that occurs in this case.
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Official CBSE Marking Scheme · CBSE Board 2024 (Supplementary), Set 31/S/1
Labelled diagram [1½]
• White light will split into a band of seven colours of spectrum. [½]
• Different colours of white light bend / refract through different angles with respect to incident ray as they pass through a prism. [1]
Q60.2023 Main 31/1/1 · Q313 marks
Give reasons for the following :
(a) Danger signals installed at airports and at the top of tall buildings are of red colour.
(b) The sky appears dark to the passengers flying at very high altitudes.
(c) The path of a beam of light passing through a colloidal solution is visible.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/1/1
(a) Red coloured light is least scattered by fog or smoke and can be easily seen from a distance. / Red colour has high wavelength thus scattering is less. [1]
(b) There is no scattering of light due to lack of atmosphere. [1]
(c) Particles of colloid are big enough to scatter the beam of light. [1]
Q61.2023 Main 31/5/1 · Q313 marks
(a) State one important function of the following parts of the human eye :
(i) Retina
(ii) Pupil
(b) State the role of ciliary muscles in focussing objects at varying distances from the eye.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/5/1
(a) (i) Retina behaves like a light sensitive screen on which image of an object is formed. [1]
(ii) Pupil : regulates and controls the amount of light entering the eye. [1]
(b) When ciliary muscles relax or contract they change the curvature of eye lens and hence the focal length to focus objects at varying distances from the eye. [1]
[Alternate answer of (b): It regulates the focal length or thickness of the lens.]
Q62.2023 Main 31/6/1 · Q313 marks
State reasons for Myopia. With the help of ray diagrams, show the
(a) image formation by a myopic eye, and
(b) correction of myopia using an appropriate lens.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/6/1
• excessive curvature of the eye lens [½]
• elongation of the eyeball [½]
(a)
[1]
(b)
[1]
Q63.2023 Supp 31/C/1 · Q313 marks
What is Tyndall effect ? Give two examples where this phenomenon is observed. Give reason to explain this phenomenon.
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Official CBSE Marking Scheme · CBSE Board 2023 (Supplementary), Set 31/C/1
• It is the phenomenon of scattering of light by the colloidal particles due to which the path of the light becomes visible. [1]
• Examples : 1. When sunlight passes through a canopy of dense forest. [½] 2. A fine beam of sunlight enters a smoke / dust filled dark room through a small hole. [½]
• Explanation : When a beam of light passes through a heterogenous mixture of minute particles (dust, smoke etc) it is reflected diffusely by the particles and gets scattered. This scattering of light makes the beam of light visible. [1]
Q64.SQP 2025-26 · Q353 marks
The above image shows a corrective measure for a particular defect of vision.
(i) Identify the defect of vision and state what kind of lens is used to correct this deficiency.
(ii) Draw and label a ray diagram that shows the defect of vision in the above case before correction.
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Official CBSE Marking Scheme · CBSE Sample Question Paper 2025-26 Marking Scheme
(i) Hypermetropia is the deficiency in vision and the lens is convex lens.
(ii)
Q65.2026 Exam 2 31/7/1 · Q384 marks
Read the following passage and answer the questions that follow :
Two students, A and B were performing an activity on refraction through glass slab and refraction through prism respectively. Student ‘A’ observed that the emergent light ray is parallel to the direction of incident ray, while student ‘B’ observed that the emergent ray is making a certain angle with respect to the direction of the incident ray in the prism, called angle of deviation. He also noted that the angle of deviation is different for different colours of light.
(a) When white light passes through a glass slab, it does not show dispersion, while it shows dispersion when it passes through a glass prism. Why ?
(b) Why do we get spectrum when white light passes through tiny water droplets present in air ?
(c) (i) For a given pair of mediums, if we change the angle of incidence gradually, will it change the speed of light in that medium ? Explain.
OR
(c) (ii) Calculate the speed of light in a given medium if angle of incidence in air is 60° and angle of refraction in the medium is 30°. Given that speed of light in air is 3 × 108 m/s.
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Official CBSE Marking Scheme · CBSE Board 2026 (2nd Board Examination), Set 31/7/1
(a) Glass slab shows no dispersion because the colours dispersed by first refracting surface recombine and emerge out as white light at the second surface. In a glass prism different colours bend at different angles hence shows dispersion. [1]
(b) Tiny water droplets act like prism. They refract and disperse the sunlight to show spectrum. [1]
(c) (i) With change in angle of incidence, angle of refraction will also change. Hence refractive index remains constant. [1] Refractive index = speed of light in airspeed of light in given medium. Hence speed of light in that medium will also remain constant. [1]
OR
(c) (ii) n = sin isin r [½]; n = sin 60°sin 30° = √3 / 21 / 2 = √3 [½]
n = speed of light in airspeed of light in medium [½]; √3 = 3 × 108v; v = 3 × 108√3 = √3 × 108 m/s [½]
Q66.2025 Main 31/2/1 · Q394 marks
A person allowed a narrow beam of white light from the sun to enter a dark room through a small aperture and placed a glass prism in its path in such a manner that the beam falls on the face AB of the prism as shown in the figure.
A screen S is placed on the other side of the prism, facing AC. On turning the prism slowly, a beautiful band of colours is obtained on the screen. It is the spectrum of sunlight.
(a) Name the phenomenon due to which a prism splits the incident white light into a band of colours.
(b) State the reason of getting a band of seven colours in the above case.
(c) (i) Explain with the help of a labelled ray diagram, an experimental arrangement to show the recombination of the spectrum of white light.
OR
(c) (ii) Draw a labelled ray diagram to show the formation of a rainbow.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/2/1
(a) Dispersion of light [1]
(b) Different colours of light bend through different angles with respect to the incident ray as they pass through a prism. [1]
(c) (i) Two identical prisms are placed in inverted position with respect to each other as shown. When spectrum produced by prism A is passed through the prism B, a beam of white light emerges from the other side of the prism B.
[2] (award full marks even if only labelled ray diagram is given)
OR
(c) (ii)
[2] (deduct ½ mark if arrows are not marked)
Q67.2025 Main 31/4/1 · Q394 marks
The students in a class took a thick sheet of cardboard and made a small hole in its centre. Sunlight was allowed to fall on this small hole and they obtained a narrow beam of white light. A glass prism was taken and this white light was allowed to fall on one of its faces. The prism was turned slowly until the light that comes out of the opposite face of the prism appeared on the nearby screen. They studied this beautiful band of light and concluded that it is a spectrum of white light.
(i) Give any one more instance in which this type of spectrum is observed.
(ii) What happens to white light in the above case?
(iii) (A) List two conditions necessary to observe a rainbow.
OR
(iii) (B) Draw a ray diagram to show the formation of a rainbow. Mark on it, points (a), (b) and (c) as given below :
(a) Where dispersion of light occurs.
(b) Where light gets reflected internally.
(c) Where final refraction occurs.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/4/1
(i) A rainbow (or any other) [1]
(ii) Dispersion of white light takes place. [1]
(iii) (A)
• The presence of water droplets in the atmosphere.
• The sun must be at the back of the observer. [1 + 1]
OR
(iii) (B)
(½ mark for diagram and ½ for labelling a, b, c) [½ × 4]
Q68.2025 Supp 31/S/1 · Q355 marks
(a) (i) Define the term power of accommodation of human eye. What happens to the image distance in the eyes when the distance of an object is increased gradually from about 5 m to 500 m from our eyes ? Name and explain the role of the part of human eye responsible for it in this case.
(ii) A person is unable to see distinctly the objects placed beyond 2 m from his eyes. Name the defect of vision the person is suffering from. List two possible causes of this defect and write the type of lenses used for the correction of this defect.
OR
(b) (i) Name and explain the phenomenon of light responsible to make the path of a beam of light visible when it enters a smoke/dust-filled room through a small hole. Also state the dependence of the colour of the light we receive on the size of the particles of the medium through which the light passes.
(ii) A person suffering from presbyopia needs spectacles having bifocal lenses. If the power of two lenses used in his spectacles is + 2·0 D and − 0·5 D, which one of the two lenses is for the correction of his distant vision and what is its focal length ?
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Official CBSE Marking Scheme · CBSE Board 2025 (Supplementary), Set 31/S/1
(a) (i) The ability of eye lens to adjust its focal length. [1] Image distance remains the same. [1] Ciliary muscles [½]; Ciliary muscles modify the curvature of eye lens / change the focal length of eye lens. [½]
(ii) Myopia / near-sightedness [½]; Causes – (i) excessive curvature of eye lens (ii) elongation of eyeball [½ + ½]; Concave lens of suitable power. [½]
OR
(b) (i) Tyndall effect / Scattering of light [1]. When a beam of light strikes fine particles in a smoke or dust filled room, light gets scattered by these particles and reaches us, this makes the path of light visible. [1] Very fine particles scatter mainly blue light while particles of larger size scatter light of longer wavelength. If the size of scattering particles is large enough, then the scattered light may even appear white. [1]
(ii) Lens of power −0.5 D will be used for the correction of his distant vision. [1]
P = 1f; −0.5 D = 1f; f = 1−0.5 = −2 m [1]
Q69.SQP 2026-27 · Q395 marks
Attempt either option A or B.
A.
I. What is meant by accommodation of the human eye?
II. What is the near point of a normal eye and what does it signify?
III. Name which type of lens is used to correct the defect in which a person cannot see distant objects clearly.
IV. Draw a diagram to show how the choice of your lens in (d) helps to see distant objects clearly?
OR
B.
I. What is dispersion of light?
II. Which colour of light deviates the least during dispersion through a prism?
III. State why the sky appears dark to an astronaut in outer space.
IV. Draw a simple labelled diagram to show how white light splits into different colours while passing through a glass prism.
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Official CBSE Marking Scheme · CBSE Sample Question Paper 2026-27 Marking Scheme
A. I. Accommodation: Ability of the eye lens to change its focal length to focus objects at different distances on the retina. [1]
II. Near point: The nearest point (about 25 cm for a normal eye) at which an object can be seen distinctly; it signifies the closest comfortable focus. [1]
III. Lens for defect (cannot see distant objects): A diverging (concave) lens is used to correct myopia (short-sightedness). [1]
IV. Diagram: [2]
OR
B. I. Dispersion: Splitting of white light into its component colours due to wavelength-dependent refraction. [1]
II. Colour deviating least in prism: Red deviates least (longest wavelength). [1]
III. Sky dark in space: No atmosphere to scatter sunlight — space appears dark. [1]
IV. Diagram: [2]
Unit II · Effects of Current
3. Electricity
Q1.2026 Main 31/3/1 · Q301 mark
The correct way to connect an ammeter and a voltmeter in an electric circuit is :
(C) Ammeter in series and voltmeter in parallel. [1]
Q2.2025 Main 31/2/1 · Q141 mark
An electric bulb is connected to a power supply of 220 V. If the current drawn by the bulb from the supply is 500 mA, the power of the bulb is :
11 W
110 W
220 W
1100 W
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/2/1
B. 110 W [1]
Q3.2025 Main 31/2/1 · Q151 mark
Four identical resistors of 12 Ω each are connected in series to form a square ABCD as shown in the figure. The resistance of the network between the two points 1 and 2 is :
48 Ω
36 Ω
9 Ω
6 Ω
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/2/1
C. 9 Ω [1]
Q4.2025 Main 31/2/1 · Q191 mark
For Questions number 17 to 20, two statements are given — one labelled as Assertion (A) and the other labelled as Reason (R). Select the correct answer to these questions from the codes (A), (B), (C) and (D) as given below.
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.
Assertion (A) : Nichrome is an alloy which is commonly used in electrical heating devices such as electric irons, toasters, etc.
Reason (R) : The resistivity of nichrome is high and its resistance decreases with increase in temperature.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/2/1
C. Assertion (A) is true, but Reason (R) is false. [1]
Q5.2025 Main 31/3/1 · Q131 mark
A wire of length ‘l’ is gradually stretched so that its length increases to 3l. If its original resistance is R, then its new resistance will be :
3R
6R
9R
27R
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/3/1
C. 9R [1]
Q6.2025 Main 31/4/1 · Q121 mark
A piece of wire of resistance ‘R’ is cut lengthwise into three identical parts. These parts are then connected in parallel. If the equivalent resistance of this combination is R′, then the value of R/R′ is :
1/9
1/3
3
9
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/4/1
(d) 9 [1]
Q7.2025 Main 31/4/1 · Q131 mark
An electric bulb is rated 220 V; 11W. The resistance of its filament when it glows with a power supply of 220 V is :
4400 Ω
440 Ω
400 Ω
20 Ω
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/4/1
(a) 4400 Ω [1]
Q8.2025 Main 31/4/1 · Q141 mark
The minimum number of identical bulbs of rating 4V; 6W, that can work safely with desired brightness, when connected in series with a 240 V mains supply is :
20
40
60
80
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/4/1
(c) 60 [1]
Q9.2025 Supp 31/S/1 · Q131 mark
Which one of the following factors affects the electrical resistivity of a conductor ?
Temperature
Length
Shape
Thickness
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Official CBSE Marking Scheme · CBSE Board 2025 (Supplementary), Set 31/S/1
(A) Temperature
Q10.2024 Main 31/2/1 · Q141 mark
The maximum resistance of a network of five identical resistors of 15 Ω each can be –
1 Ω
0.5 Ω
0.25 Ω
0.1 Ω
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/2/1
(A) 1
Q11.2024 Main 31/2/1 · Q151 mark
Study the I-V graph for three resistors of resistances R1, R2 and R3 and select the correct statement from the following :
R1 = R2 = R3
R1 > R2 > R3
R3 > R2 > R1
R2 > R3 > R1
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/2/1
(C) R3 > R2 > R1
Q12.2024 Main 31/3/1 · Q141 mark
In case of four wires of same material, the resistance will be minimum if the diameter and length of the wire respectively are
D/2 and L/4
D/4 and 4L
2D and L
4D and 2L
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/3/1
(D) 4D and 2L
Q13.2024 Main 31/4/1 · Q131 mark
Consider the following combinations of resistors :
The combinations having equivalent resistance 1 Ω is/are :
I and IV
Only IV
I and II
I, II and III
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/4/1
(C) I and II
Q14.2024 Main 31/4/1 · Q141 mark
An electric iron of resistance 20 Ω draws a current of 5 A. The heat developed in the iron in 30 seconds is :
15000 J
6000 J
1500 J
3000 J
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/4/1
(A) 15000 J
Q15.2024 Main 31/5/1 · Q191 mark
Assertion (A) : Electrons move from lower potential to higher potential in a conductor.
Reason (R) : A dry cell maintains electric potential difference across the ends of a conductor.
For Questions number 17 to 20, two statements are given one labelled as Assertion (A) and the other labelled as Reason (R). Select the correct answer to these questions from the codes (A), (B), (C) and (D) as given below.
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/5/1
(B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not a correct explanation of Assertion (A).
Q16.2024 Supp 31/S/1 · Q141 mark
When we connect too many electrical appliances to a single socket in a circuit having a fixed value of current rating :
the total resistance of the circuit increases.
the current drawn from the source decreases.
the current increases beyond the rated value.
each appliance starts drawing more and more current from the source.
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Official CBSE Marking Scheme · CBSE Board 2024 (Supplementary), Set 31/S/1
(C) the current increases beyond the rated value.
Q17.2024 Supp 31/S/1 · Q191 mark
Assertion (A) : The commercial unit of electric energy is kilowatt hour (kWh).
Reason (R) : 1 kWh = 106 joule (J)
For Questions number 17 to 20, two statements are given — one labelled as Assertion (A) and the other labelled as Reason (R). Select the correct answer to these questions from the codes (A), (B), (C) and (D) as given below.
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.
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Official CBSE Marking Scheme · CBSE Board 2024 (Supplementary), Set 31/S/1
(C) Assertion (A) is true, but Reason (R) is false.
Q18.2023 Main 31/1/1 · Q131 mark
If four identical resistors, of resistance 8 ohm, are first connected in series so as to give an effective resistance Rs, and then connected in parallel so as to give an effective resistance Rp, then the ratio RsRp is
32
2
0.5
16
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/1/1
(d) [1]
Q19.2023 Main 31/1/1 · Q151 mark
In the following diagram, the position of the needle is shown on the scale of a voltmeter. The least count of the voltmeter and the reading shown by it respectively are :
0.15 V and 1.6 V
0.05 V and 1.6 V
0.15 V and 1.8 V
0.05 V and 1.8 V
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/1/1
(c) [1]
Q20.2023 Main 31/2/1 · Q141 mark
For verifying Ohm’s law, we design an electric circuit diagram in which we show the arrangement of different circuit components. We find that with respect to the resistor, the :
ammeter is connected in parallel and the voltmeter in series.
ammeter is connected in series and the voltmeter in parallel.
ammeter and voltmeter are both connected in series.
ammeter and voltmeter are both connected in parallel.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/2/1
(b) [1]
Q21.2023 Main 31/2/1 · Q151 mark
In a resistive circuit if the current is increased to two times, the percentage change in the amount of heat dissipated in the circuit would be :
400%
300%
200%
100%
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/2/1
(b) [1]
Q22.2023 Main 31/4/1 · Q131 mark
Two LED bulbs of 12W and 6W are connected in series. If the current through 12W bulb is 0.06A the current through 6W bulb will be :
0.04A
0.06A
0.08A
0.12A
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/4/1
(b) [1]
Q23.2023 Main 31/4/1 · Q151 mark
The resistance of a resistor is reduced to half of its initial value. If other parameters of the electrical circuit remain unaltered, the amount of heat produced in the resistor will become :
four times
two times
half
one fourth
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/4/1
(b) [1]
Q24.2023 Main 31/5/1 · Q131 mark
The expressions that relate (i) Q, I and t and (ii) Q, V and W respectively are (Here the symbols have their usual meanings) :
(i) I = Qt (ii) W = VQ
(i) Q = I × t (ii) W = V × Q
(i) Q = It (ii) V = WQ
(i) I = Qt (ii) Q = VW
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/5/1
(b)
Q25.2023 Main 31/5/1 · Q151 mark
An electric kettle consumes 1 kW of electric power when operated at 220 V. The minimum rating of the fuse wire to be used for it is
1 A
2 A
4 A
5 A
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/5/1
(d)
Q26.2023 Supp 31/C/1 · Q141 mark
A material used for making heating elements of electrical heating devices should have :
High resistivity and high melting point.
High resistivity and low melting point.
Low resistivity and high melting point.
Low resistivity and low melting point.
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Official CBSE Marking Scheme · CBSE Board 2023 (Supplementary), Set 31/C/1
(a)
Q27.2023 Supp 31/C/1 · Q151 mark
The resistance of a wire does not depend on its :
Length
Area of cross-section
Shape
Material
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Official CBSE Marking Scheme · CBSE Board 2023 (Supplementary), Set 31/C/1
(c)
Q28.SQP 2026-27 · Q311 mark
An electrical appliance rated 1000 W is operated at 250 V. What current does it draw?
0.25 A
2.5 A
4.0 A
10 A
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Official CBSE Marking Scheme · CBSE Sample Question Paper 2026-27 Marking Scheme
C. 4.0 A
Q29.2026 Exam 2 31/7/1 · Q332 marks
(a) Calculate the total resistance of the given circuit and find the total current flowing in it.
OR
(b) How would you join three resistors each of resistance 6 Ω, so that the equivalent resistance of the combination is (i) 9 Ω, and (ii) 4 Ω ?
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Official CBSE Marking Scheme · CBSE Board 2026 (2nd Board Examination), Set 31/7/1
(a) Rs = R3 + R4 (R3 and R4 are in series); Rs = 6 + 4 = 10 Ω
Rs and R2 are in parallel: 1Rp = 110 + 110 = 210 = 15; Rp = 5 Ω
R1 and Rp are in series: Total Resistance = 5 + 1 = 6 Ω [1]
Total Current I = VR = 126 = 2 A [1]
OR
(b) (i)
[1]
(ii)
[1]
Q30.2026 Exam 2 31/8/1 · Q342 marks
A bulb consumed 24 J of energy per second, when connected to a 12 V supply. Calculate the power consumed when it is connected to a 6 V supply.
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Official CBSE Marking Scheme · CBSE Board 2026 (2nd Board Examination), Set 31/8/1
P = 24 J/s. When connected to 12 V supply: P = V2R [½]; R = 12 × 1224 [½]; R = 6 Ω [½]
When connected to 6 V supply: P = V2R = 6 × 66; P = 6 W [½]
Q31.2026 Main 31/1/1 · Q342 marks
(a) The resistance of a wire of 0.01 cm radius and 1.0 cm length is 7 Ω. Calculate its resistivity.
OR
(b) An electric heater is rated 220 V; 11 A. Calculate the power consumed if the heater is operated at 200 V.
(a) 1 Volt is the potential difference between two points in a current carrying conductor when one Joule work is done to move a charge of 1 Coulomb from one point to the other. / 1 V = 1 J1 C [1]
(b) V = WQ [½]
W = Q × V = 1·6 × 10−19 × 100
W = 1·6 × 10−17 J [½]
Q33.2025 Main 31/1/1 · Q252 marks
(a) A wire of resistance R is cut into three equal parts. If these three parts are then joined in parallel, calculate the total resistance of the combination so formed.
OR
(b) Define electric power. When do we say that the power consumed in an electric circuit is 1 watt ?
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/1/1
(a) Resistance of each part = R3 [½]
1Rp = 1R1 + 1R2 + 1R3 [½]
1Rp = 1R/3 + 1R/3 + 1R/3 [½]
1Rp = 3R + 3R + 3R = 9R
Rp = R9 [½]
OR
(b) Electric power is the rate at which electrical energy is consumed or dissipated in an electrical circuit. / Electric power is electrical energy consumed per unit time. [1]
When 1 A current at 1 V potential difference flows in a circuit. / Power consumed is 1 W when 1 J electrical energy is consumed in 1 s. [1]
Q34.2025 Main 31/2/1 · Q262 marks
An electric kettle is rated 750 W; 220 V. Can this kettle be used in a circuit which has a fuse of current rating 3 A ? Give reason for your answer.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/2/1
P = 750 W, V = 220 V
Current drawn by kettle, I = PV = 750 W/220 V = 3·4 A [½]
No, this kettle cannot be used. [½]
The current drawn by the kettle is more than the fuse rating (3 A). So, the fuse will melt and break the circuit. [1]
Q35.2025 Main 31/3/1 · Q262 marks
An electric kettle is rated 230 V; 1000 W. Calculate the resistance of its heating element when in operation.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/3/1
P = 1000 W, V = 230 V; Formula: P = V2R [½]
R = V2P
= (230)21000 [1]
= 52·9 Ω [½]
Q36.2025 Main 31/5/1 · Q252 marks
(A) State two applications of Joule’s heating in domestic electric circuit.
(B) (a) Establish the relationship between the commercial unit of electric energy and the SI unit of electric energy.
OR
(b) Determine the total resistance of the parallel combination of three resistances of 2 Ω, 4 Ω and 6 Ω.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/5/1
(A) Electric bulb / electric iron / Electric fuse / Electric heater / electric Oven (Any two) [½ + ½]
(B) (a) 1 kWh = 1000 watt × 3600 second [½ + ½]
= 3·6 × 106 watt second
= 3·6 × 106 Joule (J)
OR
(b) 1Rp = 1R1 + 1R2 + 1R3 [½]
1Rp = 12 + 14 + 16
Rp = 1211 = 1·09 Ω [½]
Q37.2024 Main 31/1/1 · Q252 marks
(A) Show how you would connect three resistors each of resistance 6 Ω, so that the combination has a resistance of 9 Ω. Also justify your answer.
OR
(B) In the given circuit calculate the power consumed in watts in the resistor of 2 Ω :
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/1/1
(A) When two 6 Ω resistances are connected in parallel and the third resistance of 6 Ω is connected in series combinations to this, then equivalent resistance will be 9 Ω / [1]
[Award marks for writing the statement or drawing the diagram]
Electric power, P = I2R [½] = (2 A)2 × 2 Ω = 4 × 2 W = 8 W [½]
Q38.2024 Main 31/2/1 · Q252 marks
Use Ohm’s law to determine the potential difference across the 3 Ω resistor in the circuit shown in the following diagram when key is closed :
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/2/1
Rs = R1 + R2 + R3 = 1 + 2 + 3 = 6 Ω [½]
I = VR [½] = 2 V6 Ω = 13 A [½]
V = IR = 13 A × 3 (Ω) = 1 V [½]
Q39.2024 Main 31/4/1 · Q262 marks
Two wires A and B of same material, having same lengths and diameters 0·2 mm and 0·3 mm respectively, are connected one by one in a circuit. Which one of these two wires will offer more resistance to the flow of current in the circuit ? Justify your answer.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/4/1
• Wire A will offer more resistance [1]
Justification:
• R = ρlA / thinner the wire, more resistance to the flow of current. [1]
Q40.2024 Main 31/5/1 · Q262 marks
An electric source can supply a charge of 500 coulomb. If the current drawn by a device is 25 mA, find the time in which the electric source will be discharged completely.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/5/1
Q = It [½]
t = 500 C25 / 1000 A [½]
= 20000 s [1]
Q41.2023 Main 31/2/1 · Q252 marks
V – I graph for two conducting wires A and B are as shown. If both wires are of the same length and same diameter, which of the two is made of a material of high resistivity ? Give reasons to justify your answer.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/2/1
• Wire B. [1]
• For the conductors of the same dimensions greater the resistance, greater is the resistivity. [1]
Q42.2023 Main 31/6/1 · Q242 marks
Let the resistance of an electrical device remain constant, while the potential difference across its two ends decreases to one fourth of its initial value. What change will occur in the current through it ? State the law which helps us in solving the above stated question.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/6/1
Current becomes one fourth of its original value. [1]
According to the Ohm’s law – potential difference is directly proportional to the current flowing through the conductor provided temperature remains constant. / V ∝ I (Temperature remaining constant for a given conductor) [1]
Q43.2022 Main 31/3/1 · Q42 marks
(a) An electric heater rated 1100 W operates at 220 V. Calculate (i) its resistance, and (ii) the current drawn by it.
OR
(b) Calculate the equivalent resistance of the following electric circuit :
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Official CBSE Marking Scheme · CBSE Board 2022 (Main), Set 31/3/1
(a) P (Power) = V (Potential difference) × I (Current)
Here P = 1100 W, V = 220 V, I = ?, R = ?
P = V2R [½]
(i) R = V2P = 220 V × 220 V1100 W = 44 Ω [½ + ½]
(ii) I = VR [½]
I (Current) = VR = 220 V44 Ω = 5 A [½]
(Accept any other alternative method)
OR
(b) RS = R3 + R4 = 10 + 10 = 20 Ω [½]
1RP = 1R2 + 1RS = 120 + 120 = 110 Ω [½]
RP = 10 Ω [½]
Total equivalent resistance = R = R1 + RP + R5 = 20 + 10 + 10 = 40 Ω [½]
Q44.SQP 2025-26 · Q342 marks
Attempt either option A or B.
A.
Find out the following in the electric circuit given in the figure-
(i) Effective resistance of two 8 ohm resistors in the combination.
(ii) Current flowing through the 4-ohm resistor
OR
B.
Study the circuit and find out-
(i) Current in 12 ohm resistor
(ii) Difference in the readings of ammeter A1 and A2 if any
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Official CBSE Marking Scheme · CBSE Sample Question Paper 2025-26 Marking Scheme
A. (i) R = R1R2R1 + R2 = 8 × 88 + 8 = 4 ohms
(ii) I = VR = 8(4 + 4) = 1 A
OR
B. (i) 1RP = 1R1 + 1R2 = 124 + 124 = 224; Rp = 12 ohms; RT = Rp + 12 = 24 ohms; I = VR = 624 = 0.25 A
(ii) Same readings of A1 and A2
Q45.SQP 2026-27 · Q342 marks
Attempt either option A or B.
A.
I. State Joule’s Law of heating.
II. What happens to the heat produced in a conductor if the resistance is doubled while keeping other variables constant?
OR
B.
I. Define resistivity.
II. Justify with an example why resistivity is an intrinsic property of a material.
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Official CBSE Marking Scheme · CBSE Sample Question Paper 2026-27 Marking Scheme
A. I. Joule’s law of heating: The heat produced in a resistor is (i) directly proportional to the square of current for a given resistance, (ii) directly proportional to resistance for a given current, and (iii) directly proportional to the time for which the current flows through the resistor. H = I2Rt, where ‘I’ is current and ‘R’ is resistance. [1]
II. If resistance is doubled: For the same current I, heat H becomes H = I2(2R)t = 2I2Rt = 2H, i.e. heat doubles. [1]
OR
B. I. Definition: The resistivity (ρ) of a material is defined as the resistance of a wire having unit cross-sectional area and unit length. R = ρLA, where R is resistance of a wire of length L and cross-sectional area A. [1]
II. Intrinsic property justification: Resistivity depends only on material (not on dimensions). Example: Two copper wires of different lengths and thicknesses yield the same ρ when computed using R·A/L. [1]
Q46.2026 Main 31/2/1 · Q373 marks
The values of current I flowing in a given resistor for the corresponding values of potential difference V applied across the ends of resistor are given below in the table :
I (Amperes)
0·4
0·8
1·2
1·6
2·0
V (Volts)
1·2
2·4
3·6
4·8
6·0
Plot a graph between V and I and calculate the resistance of that resistor.
(i) Maintain a constant potential difference in a circuit.
(ii) Change the electric current in an electric circuit.
(b) When the potential difference between the terminals of an electric heater is 110 V, a current of 5 A flows through it. What will be the value of current flowing through it when the potential difference is increased to 220 V ?
(a) 4 Ω and 1 Ω are in series, Rs = 4 Ω + 1 Ω = 5 Ω
Resistance across R and S, 1R1 = 15 + 15; R1 = 52 Ω
2 Ω and 3 Ω are in series, Rs1 = 2 Ω + 3 Ω = 5 Ω
Resistance across P and Q, 1R2 = 15 + 15; R2 = 52 Ω
Total resistance: R = R1 + R2 = 52 + 52 = 5 Ω [1]
(b) I = VR = 105 = 2 A [1]
(c) V = I R = 2 × 52 = 5 V [1]
Q49.2026 Main 31/5/1 · Q373 marks
(a) Why does an electric bulb become dim when an electric heater in parallel circuit is switched ON ?
(b) How to connect three resistors each of resistance 8 Ω, so that the equivalent resistance of the combination is 12 Ω ? Draw diagram of the combination and justify your answer.
(a) When the electric heater is switched on in a parallel circuit, it draws a large amount of current. As a result, the current through the bulb decreases, making the bulb glow dim. [1]
(b) • [1]
• 1R1 = 18 + 18; R1 = 4 Ω
Req = R1 + 8 Ω = 12 Ω [1]
Q50.2025 Main 31/1/1 · Q323 marks
Consider the following electric circuit :
Calculate the values of the following :
(a) The total resistance of the circuit
(b) The total current drawn from the source
(c) Potential difference across the parallel combination of 10 Ω and 15 Ω resistors
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/1/1
(a) 1R1 = 110 Ω + 115 Ω = 16 Ω ⇒ R1 = 6 Ω
1R2 = 160 Ω + 140 Ω = 1002400 Ω ⇒ R2 = 24 Ω
∵ R1 and R2 are in series
∴ Rtotal = R1 + R2 = (6 + 24) = 30 Ω [1]
(b) V = IR ⇒ I = VR = 15 V30 Ω = 0·5 A [1]
(c) V = IR1 = 0·5 A × 6 Ω = 3·0 V [1]
Q51.2025 Main 31/1/1 · Q333 marks
(a) Write the relationship between resistivity and resistance of a cylindrical conductor of length l and area of cross-section A. Hence derive the SI unit of resistivity.
(b) Why are alloys used in electrical heating devices ?
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/1/1
(a) R = ρlA [1]
ρ = RAl [½]
SI unit of ρ = ohm × (metre)2metre = ohm meter [½]
(b) Resistivity of alloy is higher than pure metals. / They do not oxidise (burn) readily at high temperatures. [1]
Q52.2025 Main 31/2/1 · Q323 marks
Three resistors of 2 Ω, 3 Ω and 6 Ω are connected in (i) series, and (ii) parallel. Draw the arrangements of the resistors and find the equivalent resistance of each arrangement.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/2/1
(i)
[½]
In series, Rs = R1 + R2 + R3 [½]
= (2 + 3 + 6) Ω = 11 Ω [½]
(ii)
[½]
In parallel, 1Rp = 1R1 + 1R2 + 1R3 [½]
= 12 + 13 + 16 = 3 + 2 + 16
Rp = 1·0 Ω [½]
Q53.2025 Main 31/4/1 · Q323 marks
The electrical resistivity of three materials A, B and C at 20°C is given below :
Material
Resistivity (Ω m)
A
1017
B
44 × 10-6
C
1.62 × 10-8
(i) Classify these materials as conductor, alloy and insulator.
(ii) Give one example of each of these materials and state one use of each material in the design of an electrical appliance say an electric stove or an electric iron.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/4/1
(i)
A – Insulator [½]
B – Alloy [½]
C – Conductor [½]
(ii)
A: Plastic – handle of an electric iron. / Rubber – foot of the electric stove.
B: Nichrome – used as a heating element in an electric iron / electric stove.
C: Copper – electric wires.
(any other example with its use in an electric appliance) [½ × 3]
Q54.2025 Main 31/5/1 · Q323 marks
The resistance of a wire of 0.01 cm radius is 7 ohms. If the resistivity of the material of the wire is 44 × 10-6 ohm meter, calculate the length of the wire.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/5/1
r = 0.01 cm = 0.01 × 10-2 m, R = 7 ohm [½]
ρ = 44 × 10-6 Ω m
A = π r2 [½]
R = ρ lA ⇒ l = R × Aρ [½]
l = 7 Ω × (0.01 × 10-2)2 m2 × 22744 × 10-6 Ω m [1]
l = 0.5 × 10-2 m [½]
Q55.2025 Main 31/6/1 · Q333 marks
(a) Explain the statement “Potential difference between two points is 1 volt”.
(b) What do the symbols given below represent in an electric circuit ? Write one function of each.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/6/1
(a) It means 1 joule of work is done to move a charge of 1 coulomb from one point of the conductor to the other. [1]
(b) (i) • Ammeter. [½]
• Ammeter is used to measure electric current [½]
(ii) • Rheostat or variable resistance [½]
• Rheostat is used in a circuit to vary the resistance of the circuit [½]
Q56.2025 Supp 31/S/1 · Q313 marks
Show the arrangement of three resistors of 2 Ω, 3 Ω and 6 Ω which are connected in such a way that the total/equivalent resistance of the combination is (a) 1 Ω, and (b) 4 Ω. Justify your answer in each case.
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Official CBSE Marking Scheme · CBSE Board 2025 (Supplementary), Set 31/S/1
(a) State Ohm’s law. Write formula for the equivalent resistance Rp of the parallel combination of three resistors of values R1, R2 and R3.
(b) Find the resistance of the following network of resistors :
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/3/1
(a) Ohm’s Law − The potential difference, V, across the ends of a given metallic wire in an electric circuit is directly proportional to the current flowing through it, provided its temperature remains the same. [1]
Formula : 1Rp = 1R1 + 1R2 + 1R3 [1]
(b) R + R2 = 3R2 [1]
Q58.2024 Supp 31/S/1 · Q313 marks
In the given circuit when key is closed, determine the following :
(i) Total resistance offered by the three resistors
(ii) Reading of the ammeter
(iii) Reading of the voltmeter
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Official CBSE Marking Scheme · CBSE Board 2024 (Supplementary), Set 31/S/1
(i) R = 2 Ω + 4 Ω + 6 Ω = 12 Ω [1]
(ii) I = VR = 6 V12 Ω = 0.5 A [1]
(iii) V = IR = 0.5 A × 4 Ω = 2 V [1]
Q59.2022 Main 31/1/1 · Q113 marks
(a) Three resistors R1, R2 and R3 are connected in parallel and the combination is connected to a battery, an ammeter, a voltmeter and a key. Draw suitable circuit diagram to show the arrangement of these circuit components along with the direction of current flowing.
(b) Calculate the equivalent resistance of the following network :
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Official CBSE Marking Scheme · CBSE Board 2022 (Term II), Marking Scheme Set 31/1/1
(a) Circuit diagram with given components [1] Direction [½]
(b) Resistance between C and D is given by 1/RCD = 1/10 + 1/10 = 2/10 = 1/5 RCD = 5 Ω [½] D and B = R4 = 5 Ω [½] ∴ Total resistance is RS = RCD + R1 + R4 [½] Rtotal = 5 Ω + 5 Ω + 5 Ω [½] = 15 Ω
Q60.2022 Main 31/1/1 · Q123 marks
(a) (i) Define Electric Power and write its SI unit. (½ + ½)
(ii) Two bulbs rated 100 W; 220 V and 60 W; 220 V are connected in parallel to an electric mains of 220 V. Find the current drawn by the bulbs from the mains.
OR
(b) (i) State Joule's law of heating. Express it mathematically for the situation when an appliance of resistance R is connected to a source of voltage V and the current I flows through the appliance for a time t.
(ii) A 5 Ω resistor is connected across a battery of 6 volts. Calculate the energy that dissipates as heat in 10 s.
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Official CBSE Marking Scheme · CBSE Board 2022 (Term II), Marking Scheme Set 31/1/1
(a) (i) The rate at which electric energy is dissipated or consumed in an electric circuit. [½] S.I. unit - watt / V. A / joule per second [½]
(ii) Current drawn by first bulb I1 = 100 W / 220 V = 100/220 ampere [½] Current drawn by second bulb I2 = 60 W / 220 V = 60/220 ampere [½] Both the bulbs are in parallel, total current I = I1 + I2 [½] = 100/220 + 60/220 ampere = 160/220 A = 0·73 A [½] (Accept any other method)
OR
(b) (i) This law states that heat produced in a resistor is - • directly proportional to the square of current for a given resistance / (H ∝ I2) • directly proportional to the resistance for a given current / (H ∝ R) • directly proportional to the time for which the current flows through the resistor / (H ∝ t) [1] H = I2Rt = VIt [½]
(ii) V = 6 V; R = 5 Ω; t = 10 s Energy dissipated as heat in t = 10 s is H = V2t/R [½] = (6 V)2/5 Ω × 10 s [½] = 72 J [½]
Q61.2022 Main 31/2/1 · Q113 marks
(a) State Ohm's Law. Represent it mathematically.
(b) Define 1 ohm.
(c) What is the resistance of a conductor through which a current of 0.5 A flows when a potential difference of 2 V is applied across its ends ?
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Official CBSE Marking Scheme · CBSE Board 2022 (Term II), Marking Scheme Set 31/2/1
(a) The potential difference (V) across the ends of a given metallic wire or conductor is directly proportional to the current (I) flowing through it, provided the temperature / physical conditions of the conductor remains the same. [½] V ∝ I; V/I = Constant; V = IR [½]
(b) If the potential difference across the two ends of a conductor is 1 V and the current through it is 1 A, then the resistance R of the conductor is 1 ohm. [1] Alternative answer: 1 ohm = 1 volt / 1 ampere
(c) R = V/I [½] R = 2 V / 0.5 A = 4 ohm [½]
Q62.2022 Main 31/2/1 · Q123 marks
(a) List the factors on which the resistance of a uniform cylindrical conductor of a given material depends. (2)
(b) The resistance of a wire of 0.01 cm radius is 10 Ω. If the resistivity of the wire is 50 × 10-8 Ω m, find the length of this wire. (1)
OR
(a) What is the meaning of electric power of an electrical device ? Write its SI unit. (1½)
(b) An electric kettle of 2kW is used for 2h. Calculate the energy consumed in
(i) kilowatt hour and
(ii) joules. (1½)
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Official CBSE Marking Scheme · CBSE Board 2022 (Term II), Marking Scheme Set 31/2/1
(a) (i) Length of the conductor (l) [1] (ii) Area of cross-section of the conductor (A) [1]
(b) Radius of wire, r = 0·01 cm = 0·01 × 10-2 m Resistance, R = 10 Ω Resistivity, ρ = 50 × 10-8 Ω m R = ρ l/A = ρ l/πr2 ⇒ l = Rπr2/ρ [½] l = 10 Ω × 22 × (0·01 × 10-2)2 m / (7 × 50 × 10-8 Ω m) = 22/35 m = 0·629 m / 0.628 m / 0.62 m [½]
OR
(a) Rate at which electric energy is dissipated / consumed in an electric circuit [1] SI unit : watt / joule per second / volt . ampere [½]
(b) E = P × t [½] (i) 2 kW × 2h = 4 kWh [½] (ii) 4 × 3.6 × 106 joules = 14.4 × 106 J / 1.44 × 107 J [½]
Q63.2022 Main 31/4/1 · Q133 marks
An electric motor rated 1100 W is connected to 220 V mains. Find :
(i) The current drawn from the mains,
(ii) Electric energy consumed if the motor is used for 5 hours daily for 6 days.
(iii) Total cost of energy consumed if the rate of one unit is ₹ 5.
OR
Study the following circuit and find :
(i) Effective resistance of the circuit
(ii) Current drawn from the battery
(iii) Potential difference across the 5 Ω resistor
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Official CBSE Marking Scheme · CBSE Board 2022 (Term II), Marking Scheme Set 31/4/1
Power (P) = 1100 W, V = 220 V
(i) Current drawn = I = P/V [½] = 1100 W / 220 V = 5 A [½]
(ii) E = P × t [½] = 1100 W × 5 h × 6 = 33000 Wh [½]
(iii) Cost of one commercial unit = ₹ 5 Energy consumed = 33 kWh = 33 unit = 118.8 × 106 J [½] Cost of 33 unit = 33 × 5 = ₹ 165 [½]
OR
(i) Effective resistance of the circuit Rs = R3 + R4 = 4 Ω + 6 Ω = 10 Ω 1/Rp = 1/Rs + 1/R2 = 1/10 + 1/10 = 2/10 = 1/5 Rp = 5 Ω [½] Total resistance of the circuit = R1 + Rp + R5 = 5 + 5 + 10 = 20 Ω [½]
(ii) Current drawn from the battery: V = 20 V, R = 20 Ω I = V/R = 20 V / 20 Ω [½] I = 1 A [½]
(iii) Reading in voltmeter connected across 5 Ω resistance V = IR; I = 1 A [½]; R = 5 Ω V = 1 A × 5 Ω = 5 V [½]
Q64.2022 Supp 31/6/1 · Q113 marks
(a) (i) In the following figure, three cylindrical conductors A, B and C are shown along with their lengths and areas of cross-section.
If these three conductors are made of the same material and RA, RB and RC be their respective resistances, then find (I) RA / RB, and (II) RA / RC.
(ii) If the conductor A is made of copper and the conductor C is made of constantan (alloy of copper and nickel), then which one of the two will have more electrical resistance and why ?
OR
(b) (i) Write the formula for determining the equivalent resistance between A and B of the two combinations (I) and (II) of three resistors R1, R2 and R3 arranged as follows :
(ii) If the equivalent resistance of the arrangements (I) and (II) are Rs and Rp respectively, then which one of the following V – I graphs is correctly labelled ? Justify your answer.
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Official CBSE Marking Scheme · CBSE Board 2022 (Term II, Supplementary), Marking Scheme Set 31/6/1
(ii) Graph (I) [1] Reason: The resistance for the series combination is more than that of parallel combination and it is directly proportional to slope of V-I graph. As in the graph (I), slope of Rs is greater than Rp, hence graph I is correct. [1]
Q65.2022 Supp 31/6/1 · Q123 marks
Define the term electric power. An electric device of resistance R when connected across an electric source of voltage V draws a current I. Derive an expression for the power in terms of resistance R and voltage V. What is the power of a device of resistance 400 Ω operating at 200 V ?
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Official CBSE Marking Scheme · CBSE Board 2022 (Term II, Supplementary), Marking Scheme Set 31/6/1
Rate at which electrical energy is dissipated / consumed in an electric circuit. [1] Power P = VI [½] = V2/R (I = V/R) [½] P = V2/R = (200 V)2/400 Ω = 100 W [1]
Q66.SQP 2025-26 · Q363 marks
A student needs to make a 0.12 Ω resistor. She has some copper wire of 0.80 mm diameter. Resistivity of copper is 1.8 × 10–8 Ωm
(i) Determine the cross-sectional area of the wire.
(ii) Calculate the length of wire required for the 0.12 Ω resistor.
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Official CBSE Marking Scheme · CBSE Sample Question Paper 2025-26 Marking Scheme
(i) Show that the cross-sectional area of the wire is about 5 × 10-7 m2. The cross-sectional area A of a wire with diameter d is given by A = π(d2)2. Substitute d = 0.80 × 10-3 m: A = π (0.40 × 10-3)2 = π × (0.16 × 10-6) m2 ≈ 3.14 × 0.16 × 10-6 m2 ≈ 5.024 × 10-7 m2. Thus, the cross-sectional area A is approximately 5 × 10-7 m2.
(ii) To find the length l of the wire, we can use the formula of resistance: R = ρ · lA. Rearrange to solve for l : l = R · Aρ. Substitute the values: l = 0.12 · 5 × 10-71.8 × 10-8 = 6 × 10-81.8 × 10-8 = 61.8 m = 3.33 m
The student needs a length of approximately 3.33 m of given copper wire to make a 0.12 Ω resistor.
Q67.SQP 2026-27 · Q373 marks
The figure shows a circuit with a 15 V battery connected to several resistors. Using the given circuit diagram:
A. Find the total current supplied by the battery.
B. Calculate the potential difference between points A and B.
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Official CBSE Marking Scheme · CBSE Sample Question Paper 2026-27 Marking Scheme
A. 1 Ω and 1 Ω are in series and the combination is in parallel with 2 Ω: 1R = 12 + 12; RAB = 1 Ω
The two 3 Ω resistors are in parallel: 1R = 13 + 13; R = 1.5 Ω
5 Ω, 1 Ω and 1.5 Ω are in series: Rs = 5 + 1 + 1.5 = 7.5 Ω
V = IR; 15 V = I × 7.5; I = 2 A [2]
B. RAB = 1 Ω, net current between points A and B is 2 A. VAB = IAB × RAB = 2 × 1 = 2 V [1]
Q68.2026 Exam 2 31/8/1 · Q384 marks
Four cells, a thin wire AB, a voltmeter, an ammeter, a plug key and some thick connecting wires are taken. The circuit is set up as shown below.
The key is inserted into the plug and readings of ammeter (I) and voltmeter (V) are noted. Then the plug key is removed. Now two cells are connected in the circuit in series. Plugging in the key the new values of ‘V’ and ‘I’ are noted. The experiment is repeated by connecting three cells in series and then four cells. In each case ‘V’ and ‘I’ are noted.
(A) Why was the plug key removed after each measurement of ‘V’ and ‘I’ and inserted again for the next step ?
(B) What change takes place in the reading of the voltmeter when a new cell is added in series in the circuit ? Give reason.
(C) In which case will the readings of voltmeter and ammeter be maximum in the above experiment ? What conclusion can be drawn from the straight line graph between ‘V’ and ‘I’ ?
OR
(C) Suppose this experiment is carried out using only one cell but wires of same length & thickness but made of different materials like nichrome wire, fuse wire, copper wire and iron wire which are replaced one by one. Out of V and I which will change and why ?
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Official CBSE Marking Scheme · CBSE Board 2026 (2nd Board Examination), Set 31/8/1
(A) The plug key was removed to prevent overheating of circuit components / to avoid accidental burns / to stop the battery from draining. (any one) [1]
(B) Voltmeter reading increases [½] because larger potential difference is applied. [½]
(C) When all four cells were connected in series in the circuit. [1] Current is directly proportional to potential difference applied. [1]
OR
(C) I or current will change. [1] Wires made of different material have different resistance. [1]
Q69.2026 Main 31/2/1 · Q384 marks
Read the following passage and answer the questions that follow :
Swati, a class 10 student, observes that when she passes close to the refrigerator in her kitchen, she feels the heat, although the things kept inside the refrigerator are cool.
(a) Describe the cause of heating in the above-mentioned case. [1]
(b) A current I flows through a resistor of resistance R when the potential difference across it is V. Applying Ohm’s law, write the formula for amount of heat produced by the resistor in time t. [1]
(c) (i) Write any two practical applications of heating effect of electric current. [2]
OR
(c) (ii) Define the commercial unit of electric energy and express it in Joules (J). [2]
(a) A part of current is consumed into useful work and rest is expended in heat to raise the temperature of gadget. (any other suitable explanation) [1]
(b) W = V × Q = VIt = IR × It; H = I2Rt / V2Rt [1]
(c) (i) Electric heater, Oven, Electric iron (Any two, Any other) [1+1]
OR
(c) (ii) When 1 kilowatt of power is used for 1 hour then energy consumed is 1 kWh [1]
1 kWh = 3.6×106 J [1]
Q70.2026 Main 31/5/1 · Q384 marks
Three students Shweta, Ayesha and Samridhi were performing an experiment to understand the factors on which the resistance of a conductor depends. Each one of them completed electric circuit with the help of a cell, an ammeter, a plug key and wire.
Shweta put nichrome wire of length ‘l’ in the circuit and after plugging the key, noted current in the ammeter.
Ayesha put nichrome wire of same thickness but twice the length i.e. ‘2l’ in the circuit and after plugging the key, noted current in the ammeter.
Samridhi took copper wire of length ‘l’ and same thickness in the circuit and after plugging the key, noted current in the ammeter.
(a) If the ammeter reading is X ampere with nichrome wire of length ‘l’, then what will be the ammeter reading if the length of nichrome wire is doubled with same area of cross-section ? [1]
(b) What happens to the ammeter reading if the area of cross-section of nichrome wire is doubled, keeping the length of wire ‘l’ the same ? [1]
(c) Define ‘resistivity’. Write its SI unit. Compare the resistivity of an alloy with its constituents metals. [2]
OR
(c) Give reason :
(i) Tungsten is used almost exclusively for making the filament of electric lamps.
(ii) Conductors of bread-toasters are made of an alloy rather than a pure metal. [2]
(c) • Resistivity is equal to electrical resistance of a conductor of unit length and unit area of cross section. [1]
• SI unit = Ω m / ohm metre [½]
• Resistivity of an alloy is higher than its constituent metals. [½]
OR
(c) (i) It has high melting point. [1]
(ii) The resistivity of an alloy is generally higher than that of its constituent metals. / Alloys do not oxidise (burn) readily at high temperatures. [1]
Q71.2025 Main 31/3/1 · Q394 marks
As shown in the diagram, an electric circuit consisting of an ammeter, a voltmeter, 4 cells of 1·5 V each, a plug key with a gap XY was set up. Voltmeter and ammeter readings were recorded in the observation table for four arrangements as given below :
Arrangement No. 1 – only resistor R1 in gap XY
Arrangement No. 2 – only resistor R2 in gap XY
Arrangement No. 3 – Resistors R1 and R2 in series in gap XY
Arrangement No. 4 – Resistors R1 and R2 in parallel in gap XY
Based on the observations, four V – I graphs A, B, C and D as shown in figure were drawn. Study these graphs.
(a) Which one of the graphs represents the series combination of R1 and R2 ?
(b) Which one of these graphs represents the parallel combination of R1 and R2 ?
(c) (i) Show an arrangement of three resistors, each of resistance 10 Ω, so that the combination has a resistance of 15 Ω. Give justification for your answer.
OR
(c) (ii) A battery of 6 V is connected with a series combination of five resistors of 0·1 Ω, 0·2 Ω, 0·3 Ω, 0·4 Ω and 0·5 Ω. How much current would flow through the 0·3 Ω resistor ? Justify your answer.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/3/1
(c) (ii) I = VR = 6 V(0·1 + 0·2 + 0·3 + 0·4 + 0·5) Ω = 6 V1·5 Ω = 4·0 A [1]
Same current flows when resistors are connected in series. [1]
Q72.2025 Main 31/6/1 · Q394 marks
Study the circuit shown in which two resistors X and Y of resistances 3 Ω and 6 Ω respectively are joined in series with a battery of 2 V.
(I) Draw a circuit diagram showing the above two resistors X and Y joined in parallel with same battery and same ammeter and voltmeter.
(II) In which combination of resistors will the (i) potential difference across X and Y and (ii) current through X and Y, be the same ?
(III) (a) Find the current drawn from the battery by the series combination of the two resistors (X and Y).
OR
(III) (b) Determine the equivalent resistance of the parallel combination of the two resistors (X and Y).
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/6/1
(I)
(or Any other way) [1]
(II) (i) in parallel combination. [½]
(ii) in series combination. [½]
(III) (a) Resistance R = 3 Ω + 6 Ω = 9 Ω [1]
V = 2 V
I = VR = 2 V9 Ω = 0·22 A [1]
OR
(b) 1R = 1R1 + 1R2 [½]
= 13 Ω + 16 Ω [½]
= 6 + 318 Ω
∴ R = 2 ohm [1]
Q73.2025 Supp 31/S/1 · Q394 marks
In a domestic circuit, six LED bulbs and a ceiling fan are arranged as per the circuit shown in the figure. The source voltage is 220 volts and the power rating of each device is marked in the circuit diagram. Two fuses F1 and F2 are also provided in the circuit. Based on the circuit diagram, answer the following questions :
(a) State what happens when
(i) only key K1 is closed,
(ii) and key K2 is also closed.
(b) Find the current drawn by the bulb L.
(c) (i) Calculate the resistance of the bulb A. Find the total resistance offered by the circuit to the flow of current when only key K2 is closed.
OR
(c) (ii) What would happen to the glow of the bulbs in the circuit when K1 and K2 both are closed and the fuse F1 melts suddenly ? Give reason to justify your answer.
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Official CBSE Marking Scheme · CBSE Board 2025 (Supplementary), Set 31/S/1
(a) (i) Ceiling fan and bulb ‘L’ will draw current and work. [½]
(ii) All the devices in the circuit draw current and work. [½]
(b) P = VI; 20 W = 220 V × I; I = 20220 = 111 A = 0.09 A [1]
(c) (i) P = V2R; R = 44 × 4410 = 193.6 Ω [1]; Total resistance = 5 × 193.6 Ω = 968 Ω [1]
OR
(c) (ii) The bulb L will stop glowing and other bulbs in the circuit will continue to glow with same brightness. [1] The fuse F1 melts and breaks the circuit for bulb L. The circuit remains complete for other bulbs connected in parallel to bulb L. [1]
Q74.2024 Main 31/2/1 · Q394 marks
When electric current flows in a purely resistive circuit electrical energy gets fully converted into heat energy. The amount of heat produced (H) in the circuit is found to be directly proportional to (i) the square of current (I2) (ii) the resistance (R) of the conductor and (iii) the time (t) for which current flows. In other words H = I2Rt. Electrical devices such an electric fuse, electric heater, electric iron etc. are all based on this effect called heating effect of electric current.
(a) List two properties of heating elements. [1]
(b) List two properties of electric fuse. [1]
(c) Name the principle on which an electric fuse works. Explain how a fuse wire is capable of saving electrical appliances from getting damaged due to accidently produced high currents. [2]
OR
(c) The power of an electric heater is 1100 W. If the potential difference between the two terminals of the heater is 220 V, find the current flowing in the circuit. What will happen to an electric fuse of rating 5 A connected in this circuit ? [2]
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/2/1
(a) • Higher resistivity than pure metals • Do not oxidise (burn) at high temperature. [½, ½]
(b) • Higher resistivity than pure metals • Low melting point. [½, ½]
(c) • Heating effect of electric current [1]
• When high current flows in the circuit accidently, the fuse wire melts and breaks the circuit. [1]
OR
(c) P = 1100 W; V = 220 V, I = ?
P = VI [½]; I = PV = 1100 W220 V = 5 A [½]
• No effect on the fuse of 5 A rating. [1]
Q75.2024 Main 31/3/1 · Q394 marks
In a domestic circuit five LED bulbs are arranged as shown. The source voltage is 220 V and the power rating of each bulb is marked in the circuit diagram. Based on the following circuit diagram, answer the following questions :
(a) State what happens when (i) key K1 is closed. (ii) key K2 is closed. [1]
(b) Find the current drawn by the bulb B when it glows. [1]
(c) Calculate (i) the resistance of bulb B, and (ii) total resistance of the combination of four bulbs B, C, D and E. [2]
OR
(c) What would happen to the glow of all the bulbs in the circuit when keys K1 and K2 both are closed and the bulb C suddenly get fused ? Give reason to justify your answer. [2]
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/3/1
(a) (i) Bulb A glows [½] (ii) Bulbs B, C, D and E glow [½]
(b) P = V × I; 11 = 55 × I [½]; I = 15 = 0.2 A [½]
(c) (i) Resistance of bulb B, R = VI = 55 V0.2 A = 275 Ω [1] (alternative formula for calculation R = V2P)
(ii) Total resistance of the series combination of four bulbs = 4 × 275 = 1100 Ω [1]
OR
(c) • Bulb A will keep glowing with same brightness. [½]
• Other bulbs i.e., B, D and E will stop glowing. [½]
• Reason: As the bulbs B, D and E are connected in series with fused bulb C, so no current flows through them and thus they will not glow. The bulb A remains unaffected as it is connected in parallel combination. [1]
Q76.2024 Main 31/4/1 · Q394 marks
Study the following circuit :
On the basis of this circuit, answer the following questions :
(a) Find the value of total resistance between the points A and B. [1]
(b) Find the resistance between the points B and C. [1]
(c) (i) Calculate the current drawn from the battery, when the key is closed. [2]
OR
(c) (ii) In the above circuit, the 16 Ω resistor or the parallel combination of two resistors of 8 Ω, which one of the two will have more potential difference across its two ends ? Justify your answer. [2]
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/4/1
(a) Rs = 4 Ω + 6 Ω + 16 Ω = 26 Ω [1]
(b) 1RP = 18 Ω + 18 Ω = 14 Ω; Rp = 4 Ω [1]
(c) (i) Total resistance = 26 Ω + 4 Ω = 30 Ω [1]; Potential difference = V = 6 V; Current I = VR [½] = 630 = 15 A or 0·2 A [½]
OR
(c) (ii) 16 Ω [1]
Justification: According to Ohm’s law when same current flows, the potential difference across a higher resistance is always higher. / Potential difference across 16 Ω = V = IR = 0.2 × 16 = 3.2 V; Potential difference across 8 Ω = V = IR(total) = 0.2 × 4 = 0.8 V [1]
Q77.2023 Main 31/2/1 · Q394 marks
Consider the following electrical circuit diagram in which nine identical resistors of 3 Ω each are connected as shown. If the reading of the ammeter A1 is 1 ampere, answer the following questions :
(a) What is the relationship between the readings of A1 and A3 ? Give reasons for your answer. [1]
(b) What is the relationship between the readings of A2 and A3 ? [1]
(c) Determine the reading of the voltmeter V1. [2]
OR
(c) Find the total resistance of the circuit. [2]
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/2/1
(a) • Both have same reading / A1 = A3 [½]
• Both are connected in series [½]
(b) Reading of A2 = 14 A as current is equally divided in the four identical resistors. / Reading of A2 = 14 times reading of A3. / A2 = 0.25 A / A2 < A3 [1]
Study the following electric circuit in which the resistors are arranged in three arms A, B and C :
(a) Find the equivalent resistance of arm A. (1)
(b) Calculate the equivalent resistance of the parallel combination of the arms B and C. (1)
(c) (i) Determine the current that flows through the ammeter. (2)
OR
(ii) Determine the current that flows in the ammeter when the arm B is withdrawn from the circuit. (2)
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Official CBSE Marking Scheme · CBSE Board 2022 (Main), Set 31/3/1
(a) RS = R1 + R2 + R3 = 40 Ω [½ + ½]
(b) 1Rp = 1RB + 1RC [½]
1Rp = 130 Ω + 160 Ω
Rp = 20 Ω [½]
(c) (i) R = Rs + Rp [1]
= 40 Ω + 20 Ω = 60 Ω
∴ I = VR = 6 V60 Ω = 110 A = 0.1 A [½ + ½]
OR
(c) (ii) Resistance, R = 40 Ω + 60 Ω = 100 Ω [1]
∴ I = VR = 6 V100 Ω = 0.06 A [½ + ½]
Q79.2026 Exam 2 31/7/1 · Q395 marks
(a) A smart home uses energy monitoring system to track electricity usage of appliances. In a month of 30 days, the following devices are used :
1. An electric heater of 1500 W used for 4 hours daily.
2. A microwave oven rated at 1·5 kW used for 3 hours daily.
(i) Define electric power and write its SI unit.
(ii) Calculate the total energy consumed in joules and kWh in a whole month.
(iii) Find out the total cost of electricity for running both appliances for a month of 30 days if the cost of 1 unit is ₹ 7.
OR
(b) (i) What is meant by electrical resistivity of a material ?
(ii) A series electric circuit comprising a resistor made of a metallic wire has an ammeter which reads 300 mA. If the length of the wire is made three times, what will be the new reading in the ammeter ?
(iii) Calculate the resistance of a 500 m long aluminium wire of cross-sectional area 1 × 10-3 m2 and resistivity 2·65 × 10-8 Ω m.
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Official CBSE Marking Scheme · CBSE Board 2026 (2nd Board Examination), Set 31/7/1
(a) (i) Electric power is defined as the rate at which electrical energy is consumed in an electric circuit. S.I unit is watt. [1 + ½]
(ii) Electrical energy consumed = Power × time. Electrical energy consumed by heater in 1 day E = 1500 × 4 = 6000 Wh = 6 kWh [½]; in 30 days = 6 × 30 = 180 kWh [½]. Electrical energy consumed by oven in 1 day = 1.5 × 3 = 4.5 kWh [½]; in 30 days = 4.5 × 30 = 135 kWh [½]. Total energy consumed in whole month = 180 + 135 = 315 kWh [½]. Total energy consumed in joules = 315 × 3.6 × 106 = 1134 × 106 J [½]
(iii) Total cost = Total energy consumed × Cost of 1 unit = 315 × 7 = Rs. 2205 [1]
OR
(b) (i) Electrical resistivity is the resistance offered by a wire of length 1 m and area of cross-section 1 m2. [1]
(ii) V = IR; V = 300 × R ... (1) [½]; R1 = 3 × R; V = I1 R1; V = I1 × 3R ... (2) [½]. From (1) and (2): I1 × 3R = 300 × R; I1 = 100 mA (Reading of ammeter) [1]
(iii) R = ρlA [½]; R = 2.65 × 10-8 × 5001 × 10-3 [½]; R = 2.65 × 5 × 10-3 Ω; R = 13.25 × 10-3 Ω [1]
Q80.2026 Main 31/1/1 · Q395 marks
(a) (i) Due to change in length and area of cross-section of a conductor, resistance of conductor changes while resistivity does not change. Why ?
(ii) Conductors of electric toasters and electric iron are made of an alloy rather than a pure metal. Why ?
(iii) Define the S.I. unit of electric current.
OR
(b) (i) How many bulbs of resistance 8 Ω each should be connected in parallel combination to draw a current of 2 A from a battery of 4 V ?
(ii) Name the device used for measuring electric current. How is it connected in a circuit ?
(a) (i) As Resistance, R = ρlA, it changes with change in length and area of cross section of conductor. [1] But resistivity of conductor is the characteristic property of material and hence it does not change. [1]
(ii) The resistivity of an alloy is generally higher than that of its constituent metals. / Alloys do not oxidise (burn) readily at high temperatures. [2]
(iii) 1 Ampere is constituted by the flow of 1 Coulomb of charge per second. / 1 A = 1 C / 1 s [1]
OR
(b) (i) V = 4 V, I = 2 A. Resistance of circuit R = VI [½] = 42 = 2 Ω [½]
Let ‘n’ be the number of bulbs: 1R = 18 + 18 + 18 + … n terms [½]; 1R = n8; 12 = n8; n = 4
Therefore, 4 bulbs of resistance 8 Ω should be connected in parallel. [½]
(ii) • Ammeter [1]
• In series [1]
(iii) Heat generated through a current carrying conductor is directly proportional to square of current, resistance of conductor and time for which current flows in conductor. [1]
H = I2Rt
Q81.2026 Main 31/4/1 · Q395 marks
(A)
(i) The given electric circuit is a part of an electrical device. Use the information given in the electric circuit diagram to calculate :
(I) Potential difference across the ends of resistor R2.
(II) Value of resistor R2.
(III) Value of resistor R1.
(ii) Write the factors on which resistance of a conductor depends and derive the formula for resistance of a given conductor.
OR
(B) (i) How much electric current will an electric iron draw from 220 V source if the resistance of its heating element when hot, is 55 Ω ? Calculate the power consumed by the electric iron when it is operated at 220 V.
(ii) In a house, 3 bulbs of 100 watt each, are lit for 5 hours daily and an electric heater of 1.0 kW is used for half an hour daily. Calculate the total energy consumed in a month of 30 days and its cost at the rate of ₹ 3.60 per kWh.
(iii) With reason explain, why are alloys commonly used to make elements of electrical heating devices.
Total energy consumed (30 days) = 30 × 2 = 60 kWh = 60 units
Total cost = Units × Rate = 60 × 3.60 = ₹ 216 [1]
(iii) The resistivity of an alloy is generally higher than that of its constituent metals. / Alloys do not oxidise (burn) readily at high temperatures. [1]
Q82.2024 Main 31/1/1 · Q365 marks
(A) (i) Define electric power. Express it in terms of potential difference (V) and resistance (R).
(ii) An electric oven is designed to work on the mains voltage of 220 V. This oven consumes 11 units of electrical energy in 5 hours. Calculate :
(a) power rating of the oven
(b) current drawn by the oven
(c) resistance of the oven when it is red hot
OR
(B) (i) Write the relation between resistance R and electrical resistivity ρ of the material of a conductor in the shape of cylinder of length l and area of cross-section A. Hence derive the SI unit of electrical resistivity.
(ii) The resistance of a metal wire of length 3 m is 60 Ω. If the area of cross-section of the wire is 4×10−7 m2, calculate the electrical resistivity of the wire.
(iii) State how would electrical resistivity be affected if the wire (of part ‘ii’) is stretched so that its length is doubled. Justify your answer.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/1/1
(A) (i) • Electric power : Rate at which electrical energy is dissipated or consumed / Rate of supplying energy to maintain the flow of current through a circuit. [1]
• P = V2R [1]
(ii) (a) (1 unit = 1 kWh) Power, P = Electrical energy consumedTime [½] = 11 kWh5 h = 2.2 kW or 2200 W [½]
(b) I = PV [½] = 2200220 = 10 A [½]
(c) R = V2P [½] = (220)22200 = 22 Ω [½] (Alternate formula can be used)
OR
(B) (i) R = ρlA [1]; ρ = R × Al = ohm metre / Ω m [1]
(ii) Here l = 3 m, A = 4 × 10−7 m2, R = 60 Ω; ρ = R × Al = 60 × 4 × 10−73 = 80 × 10−7 Ω m [1]
(iii) • Resistivity will not change. [1]
• because Resistivity does not depend on the dimension of the conductor / It only depends on the nature of the material. [1]
Q83.2024 Main 31/5/1 · Q365 marks
(a) (i) The potential difference across the two ends of a circuit component is decreased to one-third of its initial value, while its resistance remains constant. What change will be observed in the current flowing through it ? Name and state the law which helps us to answer this question.
(ii) Draw a schematic diagram of a circuit consisting of a battery of four 1·5 V cells, a 5 Ω resistor, a 10 Ω resistor and a 15 Ω resistor and a plug key, all connected in series. Now find (I) the electric current passing through the circuit, and (II) potential difference across the 10 Ω resistor when the plug key is closed.
OR
(b) (i) When is the potential difference between two points said to be 1 volt ?
(ii) A copper wire has a diameter of 0·2 mm and resistivity of 1·6 × 10−8 Ω m. What will be the length of this wire to make its resistance 14 Ω ? How much does the resistance change, if the diameter of the wire is doubled ?
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/5/1
(a)
(i) • Current becomes one-third of its initial value. [½] • Ohm’s Law [½]
The potential difference across the ends of a conductor is directly proportional to the current flowing through it, provided its temperature remains the same. [1]
(i) When 1 joule of work is done to move a charge of 1 coulomb from one point to the other. [1]
(ii) d = 0·2 mm = 2 × 10−4 m; R = 14 Ω; ρ = 1·6 × 10−8 Ω m; A = πd24 [½]
R = ρlA = 4ρlπd2 or l = πd2R4ρ [½]
l = 227 × (2 × 10−4)24 × 1·6 × 10−8 × 14 = 27·5 m [1]
When the diameter is doubled, d′ = 2d, A′ = 4A [½]
R′R = AA′ or R′ = RAA′ = RA4A → R′ = 3·5 Ω [1]
Change (14·0 − 3·5) = 10·5 Ω [½]
Q84.2024 Supp 31/S/1 · Q365 marks
(a) (i) Write the relation between the electrical resistivity ‘ρ’ and the resistance ‘R’ of a cylindrical conductor of length ‘l’ and area of cross-section ‘A’. Use this relationship to determine the SI unit of ‘ρ’.
(ii) Find the electrical resistivity of the material of a wire of length 120 cm and diameter 0·4 mm. The resistance of this wire is 3 Ω.
OR
(b) (i) What is meant by heating effect of electric current ? Derive an expression for the amount of heat produced in a conductor of resistance R through which a current I flows for a time t.
(ii) Calculate the amount of heat produced in a conductor of resistance 10 Ω through which a current of 2 A flows for 100 seconds.
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Official CBSE Marking Scheme · CBSE Board 2024 (Supplementary), Set 31/S/1
(a) (i) R = ρlA ; ρ = R × Al [1]
SI unit of ρ = SI unit of R × SI unit of ASI unit of l = Ω × m2m = Ω m [1]
(ii) R = 3 Ω; l = 120 cm = 1.2 m; d = 0.4 mm or r = 0.2 mm [½]
ρ = R × Al; A = 3.14 × (0.2 mm)2 = 3.14 × 4 × 10−8 m2 [½]
= 3 Ω × 3.14 × 4 × 10−8 m21.2 m [1]
= 3.14 × 10−7 Ω m [1]
OR
(b) (i) • When electric current is passed through a resistor electric energy is dissipated and appears as heat energy. [1]
• When charge Q flows through a conductor of resistance R having potential difference of V, the work done W is given by W = V × Q = V × I × t = IR × I × t = I2Rt (∵ V = I × R, Ohm’s Law) [1]
When circuit is purely resistive electric energy is converted into heat energy. H = I2Rt [1]
(ii) Here I = 2 A; R = 10 Ω; t = 100 s; H = I2Rt = (2 A)2 × 10 Ω × 100 s [1] = 4000 J [1]
Q85.2023 Main 31/1/1 · Q365 marks
(a) An electric iron consumes energy at a rate of 880 W when heating is at the maximum rate and 330 W when the heating is at the minimum. If the source voltage is 220 V, calculate the current and resistance in each case.
(b) What is heating effect of electric current ?
(c) Find an expression for the amount of heat produced when a current passes through a resistor for some time.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/1/1
(a) When heating is at maximum rate.
Power, P = 880 W
Voltage, V = 220 V
Current, I = PV = 880220 = 4 A [½, ½]
Resistance, R = VI = 2204 = 55 Ω [½, ½]
When heating is at minimum rate
Power, P = 330 W
Voltage, V = 220 V
Current, I = PV = 330220 = 32 = 1.5 A [½]
Resistance, R = VI = 2201.5 = 146.6 Ω [½]
(b) When electric current is passed through a resistor, electrical energy is dissipated and appears as heat energy. [1]
(c) H = I2Rt / H = VIt [1]
Q86.2023 Main 31/4/1 · Q365 marks
(i) How is electric current related to the potential difference across the terminals of a conductor ? Draw a labelled circuit diagram to verify this relationship.
(ii) Why should an ammeter have low resistance ?
(iii) Two V - I graphs A and B for series and parallel combinations of two resistors are as shown. Giving reason state which graph shows (a) series, (b) parallel combination of the resistors.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/4/1
(i) Current flowing through a conductor is directly proportional to the potential difference. / V ∝ I / I ∝ V [1]
(Any one diagram) [1]
(ii) Since ammeter is connected in series, it should not increase the resistance of the circuit. / should allow maximum current to flow through the circuit. [1]
(iii) • Series combination – Graph A [½]
Less slope and more resistance [½]
• Parallel combination – Graph B [½]
More slope and less resistance [½]
Q87.2023 Main 31/5/1 · Q365 marks
(a) State Ohm’s Law.
(b) Name and define the physical quantity determined by the slope of V – I curve given in the diagram. Use this graph to find the value of this physical quantity in SI units.
(c) Establish the relationship between 1 kWh and 1 joule.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/5/1
(a) The potential difference V across the ends of a given metallic wire in an electric circuit is directly proportional to the current flowing through it provided its temperature remains the same. / V ∝ I or V = IR (temperature remaining constant) [1]
(b) Resistance [1]
Resistance is the property of a conductor to resist the flow of charges. [1]
R = slope = y2 – y1x2 – x1 / VI = 6 – 00.8 – 0 [½]
= 608 = 7.5 Ω [½]
(c) 1 kWh = 1000 Jsec × 3600 sec
1 kWh = 3.6 × 106 J [1]
Q88.2023 Main 31/6/1 · Q365 marks
(a) (i) What is meant by resistance of a conductor ? Define its SI unit.
(ii) List two factors on which the resistance of a rectangular conductor depends.
(iii) How will the resistance of a wire be affected if its
(1) length is doubled, and
(2) radius is also doubled ?
Give justification for your answer.
OR
(b) In an electric circuit three bulbs of 100 W each are connected in series to a source. In another circuit set of three bulbs of the same wattage are connected in parallel to the same source.
(i) Will the bulb in the two circuits glow with the same brightness ? Justify your answer.
(ii) Now, let one bulb in both the circuits get fused. Will the rest of the bulbs continue to glow in each circuit ? Give reason for your answer.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/6/1
(a) (i) The property of conductor to resist the flow of charges through it. [1]
If Potential difference across the two ends of a conductor is 1 V and the current through it is 1 A, then resistance ‘R’ of the conductor is 1 Ω. [1]
Alternate answer : 1 Ω = 1 volt1 ampere
(ii) • Length of the conductor
• Area of cross-section of the conductor
• Nature of the material
• Temperature
(any two) [½ + ½]
(iii) (1) The resistance will become one half of its original value.
R = ρlA = ρlπr2 [½]
R′ = ρ·2lπ(2r)2 [1]
(2) R′ = ρ·lπ(2r)2 . 2 = R2 [½]
Resistance will reduce to one half.
OR
(b) (i) No [1]
In series combination overall resistance will increase hence decreasing the current. Potential difference also divides. Therefore power consumption is less by each bulb and glows with less brightness. [1]
In parallel combination each bulb will get the required potential difference hence the required current and will glow with its normal brightness. [1]
(ii) None of the bulb glows in series combination as the circuit gets broken and current stops flowing. [1]
In parallel combination the other two bulbs will glow with same brightness as the same voltage is available to them. [1]
Q89.2023 Supp 31/C/1 · Q365 marks
(a) The commercial unit of electric energy is commonly known as ‘unit’. Write its actual name and establish the relationship between this unit and the SI unit of energy.
(b) The current rating of a circuit is 1·0 A. How many LED lamps of power rating 8 W; 220 V can safely be used simultaneously in this circuit ?
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Official CBSE Marking Scheme · CBSE Board 2023 (Supplementary), Set 31/C/1
Number of lamp = current rating / current through each lamp [½]
= 1.0 A8 W220 V = 2208 = 27.75 [1]
So, 27 lamps can safely be used in the circuit. [1]
Q90.SQP 2025-26 · Q395 marks
Attempt either option A or B.
A.
The arrangement of resistors shown in the above figure is connected to a battery.
The power dissipation in the 100 Ω resistor is 81 W. Calculate
(i) the current in the circuit
(ii) the reading in the voltmeter V2
(iii) the reading in the voltmeter V1
OR
B.
An electric heater consists of three similar heating elements A, B and C, connected as shown in the figure above. Each heating element is rated as 1.2 kW, 240 V and has constant resistance. S1, S2 and S3 are respective switches.
The circuit is connected to a 240 V supply.
(i) Calculate the resistance of one heating element.
(ii) Calculate the current in each resistor when only S1 and S3 are closed.
(iii) Calculate the power dissipated across A when S1, S2 and S3 are closed.
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Official CBSE Marking Scheme · CBSE Sample Question Paper 2025-26 Marking Scheme
A. (i) Power across the 100 Ω resistance = 81 W; P = I2R = 81 W; ∴ I2 = 81100; ∴ I = √81100 = 910 = 0.9 A
(ii) Voltage across the 25 Ω resistors = V2 = I Reqv. For the 25 Ω resistors: 1Reqv = 125 + 125 = 225; ∴ Reqv = 252 = 12.5 Ω; ∴ V2 = 0.9 A × 12.5 Ω = 11.25 V
(iii) Voltage across 100 Ω = V100 = IR = 0.9 A × 100 Ω = 90 V; ∴ V1 = 90 V + 11.25 V = 101.25 V
OR
B. (i) P = V2R; ∴ R = V2P = 240 × 2401200 = 48 Ω
(ii) For S1 and S3 closed – Current in C: V = IR (Ohm’s Law); ∴ I = VR = 240 V48 Ω = 5 A. Current in A and B: V = IR; ∴ I = VR = 240 V96 Ω = 2.5 A
(iii) Power across A for S1, S2, S3 closed: PA = I2R = 52 × 48 = 1200 W = 1.2 kW
Unit II · Effects of Current
4. Magnetic Effects of Electric Current
Q1.2026 Exam 2 31/7/1 · Q311 mark
During a lab experiment, Bhavna uses a solenoid connected to a battery. She notes down the following facts :
(i) The pattern of magnetic field lines inside the solenoid is similar to a bar magnet.
(ii) The north pole and south pole of the current-carrying solenoid can be identified by applying the right hand thumb rule.
(iii) A solenoid can be used to magnetise a piece of a soft iron, making it an electromagnet.
Choose the option enlisting all the correct statements :
(i) and (iii)
(ii) and (iii)
(i) and (ii)
(i), (ii) and (iii)
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Official CBSE Marking Scheme · CBSE Board 2026 (2nd Board Examination), Set 31/7/1
(D) (i), (ii) and (iii)
Q2.2026 Exam 2 31/8/1 · Q321 mark
Assertion (A) : The bending of a straight wire in the form of current carrying circular coil will change the pattern of magnetic field around it.
Reason (R) : Strength of magnetic field depends upon number of turns of coil and current flowing through the coil.
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.
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Official CBSE Marking Scheme · CBSE Board 2026 (2nd Board Examination), Set 31/8/1
(B) Both Assertion (A) and Reason (R) are true and Reason (R) is not the correct explanation of the Assertion (A).
Q3.2026 Main 31/2/1 · Q321 mark
For Question number 32, two statements are given — one labelled as Assertion (A) and the other labelled as Reason (R). Select the correct answer to this question from the codes (A), (B), (C) and (D) as given below.
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.
Assertion (A) : Direction of force exerted on a current-carrying conductor placed in a magnetic field remains same if the directions of both magnetic field and current flowing through the conductor are reversed.
Reason (R) : The direction of force exerted on a current-carrying conductor placed in an external magnetic field can be determined by using magnetic compass.
(C) Assertion (A) is true, but Reason (R) is false. [1]
Q4.2026 Main 31/3/1 · Q321 mark
For Question number 32, two statements are given — one labelled as Assertion (A) and the other labelled as Reason (R). Select the correct answer to this question from the codes (A), (B), (C) and (D) as given below.
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.
Assertion (A) : The needle of a compass, kept in an external magnetic field, always aligns itself in the North-South direction of the Earth.
Reason (R) : The behaviour of the needle of the compass is similar to the behaviour of a freely suspended bar magnet.
(D) Assertion (A) is false, but Reason (R) is true. [1]
Q5.2026 Main 31/4/1 · Q321 mark
Direction : For question number 32, two statements are given – one labelled as Assertion (A) and other labelled as Reason (R). Select the correct answer to this question from the codes (A), (B), (C) & (D) as given below :
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.
Assertion (A) : With the help of compass, magnetic field lines can be traced outside the bar magnet.
Reason (R) : The north pole of a compass needle always points towards the south pole of the magnet when brought close to it.
(A) Both Assertion (A) and Reason (R) are true, and Reason (R) is the correct explanation of Assertion (A). [1]
Q6.2026 Main 31/5/1 · Q321 mark
For question number 32, two statements are given – one labelled as Assertion (A) and the other labelled as Reason (R). Select the correct answer to this question from the codes (A), (B), (C) and (D) as given below :
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.
Assertion (A) : The needle of a magnetic compass kept in strong external magnetic field, always aligns itself in north-south direction on the earth.
Reason (R) : Behaviour of the needle of a compass is same as that of a freely suspended bar magnet.
(D) Assertion (A) is false but Reason (R) is true. [1]
Q7.2025 Main 31/1/1 · Q191 mark
For Questions number 17 to 20, two statements are given — one labelled as Assertion (A) and the other labelled as Reason (R). Select the correct answer to these questions from the codes (A), (B), (C) and (D) as given below.
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.
Assertion (A) : No two magnetic field lines are found to cross each other.
Reason (R) : The compass needle cannot point towards two directions at the point of intersection of two magnetic field lines.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/1/1
A. Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A). [1]
Q8.2025 Main 31/3/1 · Q141 mark
Which one of the following statements is not true about a bar magnet ?
It sets itself in north-south direction when suspended freely.
It has attractive power for iron filings.
It produces magnetic field lines.
The direction of magnetic field lines inside a bar magnet is from its north pole to its south pole.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/3/1
D. The direction of magnetic field lines inside a bar magnet is from its north pole to its south pole. [1]
Q9.2025 Main 31/3/1 · Q151 mark
The strength of magnetic field produced inside a long straight current carrying solenoid does not depend upon :
number of turns in the solenoid
direction of current flowing through the solenoid
material of the core filled inside the solenoid
radius of the coil of the solenoid
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/3/1
D. radius of the coil of the solenoid [1]
Q10.2025 Main 31/3/1 · Q191 mark
For Questions number 17 to 20, two statements are given — one labelled as Assertion (A) and the other labelled as Reason (R). Select the correct answer to these questions from the codes (A), (B), (C) and (D) as given below.
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.
Assertion (A) : Magnetic field lines around a bar magnet never intersect each other.
Reason (R) : Magnetic field produced by a bar magnet is a quantity that has both magnitude and direction.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/3/1
B. Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A). [1]
Q11.2025 Main 31/5/1 · Q191 mark
Question Nos. 17 to 20 consists of two statements – Assertion (A) and Reason (R). Answer these questions selecting the appropriate option from (A), (B), (C) and (D) given below :
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.
Assertion (A) : The pattern of the magnetic field of a solenoid carrying a current is similar to that of a bar magnet.
Reason (R) : The pattern of the magnetic field around a current carrying conductor is independent of the shape of the conductor.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/5/1
(C) Assertion (A) is true, but Reason (R) is false. [1]
Q12.2025 Main 31/6/1 · Q191 mark
Q. Nos. 17 to 20, two statements are given – one labelled as Assertion (A) and the other labelled as Reason (R). Select the correct answer to these questions from the codes (A), (B), (C) and (D) as given below :
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
Both Assertion (A) and Reason (R) are true and Reason (R) is not the correct explanation of the Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.
Assertion (A) : In the common domestic circuits the earth wire is connected to a metallic plate buried deep inside the earth.
Reason (R) : Earth wire ensures that any leakage of current to the metallic body of the appliance keeps its potential to that of the earth, so the user may not get a severe electric shock.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/6/1
(A) Both Assertion (A) and Reason (R) are true, and Reason (R) is the correct explanation of Assertion (A). [1]
Q13.2025 Supp 31/S/1 · Q141 mark
The strength of the magnetic field inside a current carrying long straight solenoid is :
maximum at its centre.
minimum at its centre.
maximum at the ends and minimum at its centre.
uniform throughout its length.
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Official CBSE Marking Scheme · CBSE Board 2025 (Supplementary), Set 31/S/1
(D) uniform throughout its length
Q14.2025 Supp 31/S/1 · Q191 mark
Assertion (A) : In our homes we receive supply of electric power through a main supply. One of the wires in this supply, usually with red insulation, is called live wire and another wire with green insulation is called neutral wire.
Reason (R) : In our country, the potential difference between the live wire and the neutral wire is 220 volts.
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.
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Official CBSE Marking Scheme · CBSE Board 2025 (Supplementary), Set 31/S/1
(D) Assertion (A) is false, but Reason (R) is true.
Q15.2024 Main 31/1/1 · Q141 mark
The pattern of the magnetic field produced inside a current carrying solenoid is :
Options (a), (b), (c), (d) are the four patterns shown in the figure.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/1/1
(a)
Q16.2024 Main 31/2/1 · Q161 mark
Strength of magnetic field produced by a current carrying solenoid DOES NOT depend upon :
number of turns in the solenoid
direction of the current flowing through it
radius of solenoid
material of core of the solenoid
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/2/1
(B) direction of current flowing through it.
Q17.2024 Main 31/2/1 · Q201 mark
Q. Nos. 17 to 20 are Assertion – Reason based questions : These questions consist of two statements – Assertion (A) and Reason (R). Answer these questions selecting the appropriate option given below :
Assertion (A) : The deflection of a compass needle placed near a current carrying wire decreases when the magnitude of an electric current in the wire is increased.
Reason (R) : Strength of the magnetic field at a point due to a current carrying conductor increases on increasing the current in the conductor.
Both (A) and (R) are true and (R) is the correct explanation of (A).
Both (A) and (R) are true, but (R) is not the correct explanation of (A).
(A) is true, but (R) is false.
(A) is false, but (R) is true.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/2/1
(D) Assertion (A) is false, but Reason (R) is true.
Q18.2024 Main 31/4/1 · Q151 mark
A rectangular loop ABCD carrying a current I is situated near a straight conductor XY, such that the conductor is parallel to the side AB of the loop and is in the plane of the loop. If a steady current I is established in the conductor as shown, the conductor XY will
remain stationary.
move towards the side AB of the loop.
move away from the side AB of the loop.
rotate about its axis.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/4/1
(B) move towards the side AB of the loop
Q19.2024 Main 31/4/1 · Q191 mark
Assertion (A) : Magnetic field lines never intersect each other.
Reason (R) : If they intersect, then at the point of intersection, the compass needle would point towards two directions, which is not possible.
For Questions number 17 to 20, two statements are given one labelled as Assertion (A) and the other labelled as Reason (R). Select the correct answer to these questions from the codes (A), (B), (C) and (D) as given below.
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/4/1
(A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A)
Q20.2024 Main 31/5/1 · Q141 mark
The current carrying device which produces a magnetic field similar to that of a bar magnet is :
A straight conductor
A circular loop
A solenoid
A circular coil
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/5/1
(C) A solenoid
Q21.2024 Main 31/5/1 · Q151 mark
A uniform magnetic field exists in the plane of paper as shown in the diagram. In this field, an electron (e−) and a positron (p+) enter as shown. The electron and positron experience forces :
both pointing into the plane of the paper.
both pointing out of the plane of the paper.
pointing into the plane of the paper and out of the plane of the paper respectively.
pointing out of the plane of the paper and into the plane of the paper respectively.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/5/1
(A) both pointing into the plane of the paper.
Q22.2023 Main 31/1/1 · Q141 mark
In domestic electric circuits the wiring with 15 A current rating is for the electric devices which have
higher power ratings such as geyser.
lower power ratings such as fan.
metallic bodies and low power ratings.
non-metallic bodies and low power ratings.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/1/1
(a) [1]
Q23.2023 Main 31/1/1 · Q161 mark
The resultant magnetic field at point ‘P’ situated midway between two parallel wires (placed horizontally) each carrying a steady current I is
in the same direction as the current in the wires.
in the vertically upward direction.
zero
in the vertically downward direction.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/1/1
(c) [1]
Q24.2023 Main 31/1/1 · Q201 mark
Q. Nos. 17 to 20 are Assertion – Reason based questions. These consist of two statements – Assertion (A) and Reason (R). Answer these questions selecting the appropriate option given below :
Assertion (A) : The strength of the magnetic field produced at the centre of a current carrying circular coil increases on increasing the number of turns in it.
Reason (R) : The current in each circular turn has the same direction and the magnetic field due to each turn then just adds up.
Both (A) and (R) are true and (R) is the correct explanation of (A).
Both (A) and (R) are true, but (R) is not the correct explanation of (A).
(A) is true, but (R) is false.
(A) is false, but (R) is true.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/1/1
(a) [1]
Q25.2023 Main 31/2/1 · Q161 mark
A positron enters a uniform magnetic field at right angles to it as shown. The direction of force experienced by the positron will be :
to the right
to the left
into the page
out of the page
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/2/1
(c) [1]
Q26.2023 Main 31/2/1 · Q201 mark
For Questions number 17 to 20, two statements are given – one labelled as Assertion (A) and the other labelled as Reason (R). Select the correct answer from the codes (a), (b), (c) and (d) as given below.
Assertion (A) : Magnetic field lines do not intersect each other.
Reason (R) : Magnetic field lines are imaginary lines, the tangent to which at any point gives the direction of the field at that point.
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/2/1
(b) [1]
Q27.2023 Main 31/4/1 · Q141 mark
The correct pattern of magnetic field lines of the field produced by a current carrying circular loop is :
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/4/1
(c) [1]
Q28.2023 Main 31/4/1 · Q161 mark
An alpha particle enters a uniform magnetic field as shown. The direction of force experienced by the alpha particle is :
towards right
towards left
into the page
out of the page
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/4/1
(d) [1]
Q29.2023 Main 31/4/1 · Q201 mark
Q. No. 17 to 20 are Assertion – Reasoning based questions. These consist of two statements – Assertion (A) and Reason (R). Answer these questions selecting the appropriate option given below.
Assertion (A) : A current carrying straight conductor experiences a force when placed perpendicular to the direction of magnetic field.
Reason (R) : The net charge on a current carrying conductor is always zero.
Both (A) and (R) are true and (R) is the correct explanation of (A).
Both (A) and (R) are true but (R) is not the correct explanation of (A).
(A) is true but (R) is false.
(A) is false but (R) is true.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/4/1
(b) [1]
Q30.2023 Main 31/5/1 · Q141 mark
A constant current flows in a horizontal wire in the plane of the paper from east to west as shown in the figure. The direction of the magnetic field will be north to south at a point :
directly above the wire.
directly below the wire.
located in the plane of the paper on the north side of the wire.
located in the plane of the paper on the south side of the wire.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/5/1
(b)
Q31.2023 Main 31/5/1 · Q161 mark
For a current in a long straight solenoid, N and S poles are created at the two ends. Among the following statements, the incorrect statement is :
The magnetic field lines inside the solenoid are in the form of straight lines, which indicates that the magnetic field is uniform at all points inside the solenoid.
The strong magnetic field produced inside the solenoid can magnetize the soft iron placed inside it.
The pattern of the magnetic field associated with a current carrying solenoid is different from the pattern of the magnetic field around a bar magnet.
The N and S poles exchange positions when the direction of current through the solenoid is reversed.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/5/1
(c)
Q32.2023 Main 31/5/1 · Q201 mark
For questions number 17 to 20, two statements are given – one labelled as Assertion (A) and the other labelled as Reason (R). Select the correct answer to these questions from the codes (a), (b), (c) and (d) as given below :
Assertion (A) : Two magnetic field lines around a current carrying straight wire do not intersect each other.
Reason (R) : The magnitude of the magnetic field produced at a given point increases as the current through the wire increases.
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Assertion (A) is false, but Reason (R) is true.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/5/1
(b)
Q33.2023 Main 31/6/1 · Q151 mark
The magnetic field inside a long straight current carrying solenoid :
is zero.
decreases as we move towards its end.
increases as we move towards its end.
is same at all points.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/6/1
(d)
Q34.2023 Supp 31/C/1 · Q161 mark
The shape of magnetic field lines produced (i) inside a solenoid (ii) around a straight conductor, both carrying current of the same magnitude are, respectively :
(i) straight, (ii) circular
(i) circular, (ii) circular
(i) straight, (ii) straight
(i) circular, (ii) straight
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Official CBSE Marking Scheme · CBSE Board 2023 (Supplementary), Set 31/C/1
(a)
Q35.2026 Exam 2 31/7/1 · Q342 marks
Draw the pattern of magnetic field produced by a current-carrying circular loop and name the factors on which the magnitude of the magnetic field due to a current-carrying circular coil depends.
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Official CBSE Marking Scheme · CBSE Board 2026 (2nd Board Examination), Set 31/7/1
Diagram of pattern of magnetic field: [1]
Factors : (i) Amount of current flowing (ii) Number of turns of loop (iii) Radius of loop (any two) [½ + ½]
Q36.2026 Main 31/4/1 · Q332 marks
(A) A fuse in electric circuit is rated 4 A. Can it be used with an electric heater of rating 2 kW, 200 V ? Explain your answer.
OR
(B) How is an electromagnet made ? Write any two ways by which the strength of electromagnet can be increased.
• Current passing through electric heater is 10 A which is much more than rated value (4 A) of fuse. Hence fuse will melt and break the circuit. So, it cannot be used. [1]
OR
(B) • An electromagnet is formed by wrapping a current carrying insulated copper wire in the form of coil around a magnetic material like soft iron core. / By placing a magnetic material like soft iron as a core material inside the current carrying solenoid. [1]
• Strength of electromagnet can be increased by increasing the (i) Number of turns of coil [½] (ii) Current flowing through the coil. [½]
Q37.2025 Main 31/4/1 · Q262 marks
What are magnetic field lines. List two important properties of magnetic field lines.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/4/1
The lines representing magnetic field around a magnet. [1]
Properties:
• No two field lines cross each other.
• Field lines emerge from north pole and merge at south pole.
• Field lines are closed curves.
• The direction of the field lines inside the magnet is from its south pole to north pole.
(any two properties) [½ + ½]
Q38.2024 Main 31/1/1 · Q262 marks
(i) Two magnetic field lines do not intersect each other. Why ?
(ii) How is a uniform magnetic field in a given region represented ? Draw a diagram in support of your answer.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/1/1
(i) If they intersect then at the point of intersection, there would be two directions of magnetic field or compass needle would point towards two directions, which is not possible. [1]
(ii) Uniform magnetic field is represented by equidistant parallel straight lines [½]
[½]
Q39.2024 Main 31/3/1 · Q252 marks
(a) Draw a labelled diagram to show the pattern of magnetic field lines produced due to a current carrying straight conductor. Mark on it the direction of current in the conductor and the direction of magnetic field lines.
OR
(b) Name the device used to magnetise a piece of magnetic material. Draw a labelled diagram to show the arrangement used for the magnetisation of a cylinder made of soft iron.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/3/1
(a)
(Fig. 12.6(a), page 199, NCERT) Diagram [1]; Directions of current and magnetic field [½ + ½]
State the rule to determine the direction of a (a) magnetic field produced around a straight conductor carrying current and (b) force experienced by a current carrying straight conductor placed in a magnetic field which is perpendicular to it.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/6/1
(a) Right-Hand Thumb Rule : Hold the current carrying conductor in right hand, such that thumb indicates direction of current, then the fingers will wrap around conductor in the direction of field lines of the magnetic field. [1]
Alternate answer of the statement :
(b) Fleming’s Left Hand Rule : Stretch the forefinger, middle finger, and thumb of the left hand such that they are mutually perpendicular to each other. If the forefinger indicates the direction of the magnetic field, the middle finger indicates the direction of current, then the thumb points in the direction of motion or force acting on the conductor. [1]
Alternate answer of the statement :
All the physical quantities mentioned in the diagram are mutually perpendicular to each other.
Q41.2023 Supp 31/C/1 · Q252 marks
What will happen if an electric oven of rating 3 kW; 220 V is operated in a domestic electric circuit (220 V) that has a current rating of 10 A ? Give reason to justify your answer.
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Official CBSE Marking Scheme · CBSE Board 2023 (Supplementary), Set 31/C/1
Short circuiting / fuse will blow or melt / break in circuit. (any one) [1]
Justification: I = P/V = 3000 W / 220 V = 13.6 A
As the current rating is only 10 A and the oven draws a current of 13.6 A, which is more than the current rating. Hence the oven will stop working. [1]
Q42.2022 Main 31/1/1 · Q62 marks
(a) (i) Name and state the rule to determine the direction of force experienced by a current carrying straight conductor placed in a uniform magnetic field which is perpendicular to it.
(ii) An alpha particle while passing through a magnetic field gets projected towards north. In which direction will an electron project when it passes through the same magnetic field ?
OR
(b) (i) What is a solenoid ?
(ii) Draw the pattern of magnetic field lines of the magnetic field produced by a solenoid through which a steady current flows.
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Official CBSE Marking Scheme · CBSE Board 2022 (Term II), Marking Scheme Set 31/1/1
(a) (i) Fleming's left-hand rule [½] Stretch the thumb, forefinger and middle finger of your left hand such that they are mutually perpendicular. If the first finger points in the direction of magnetic field and the second finger in the direction of current, then the thumb will point in the direction of motion or the force acting on the conductor. [1]
(ii) South [½]
OR
(b) (i) A coil of many circular turns of insulated copper wire wrapped closely in the shape of a cylinder. [1]
(ii) [1]
Q43.2022 Main 31/2/1 · Q62 marks
(a) Name the poles P, Q, R and S of the magnets in the following figures 'a' and 'b' :
(b) State the inference drawn about the direction of the magnetic field lines on the basis of these diagrams.
OR
When is the force experienced by a current – carrying straight conductor placed in a uniform magnetic field.
(i) Maximum ;
(ii) Minimum ?
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Official CBSE Marking Scheme · CBSE Board 2022 (Term II), Marking Scheme Set 31/2/1
(a) P – North pole ; Q – South pole [½] R – North pole ; S – South pole [½]
(b) The magnetic field lines emerge from the North-pole and merge to South-pole outside the magnet. (Inside the magnet the direction is from South pole to North pole.) [1] Alternative answer: Closed curves which emerge from North pole and merge at the South pole.
OR
(i) Maximum - when the direction of current (current carrying conductor) is perpendicular to the direction of magnetic field. [1]
(ii) Minimum - (zero) when the direction of current (current carrying conductor) is parallel / antiparallel / along the direction of magnetic field. [1]
Q44.2022 Main 31/4/1 · Q22 marks
As shown in the diagram an aluminium rod 'AB' is suspended horizontally between the two poles of a strong horse shoe magent in such a way that the axis of rod is horizontal and the direction of the magnetic field is vertically upward. The rod is connected in series with a battery and a key.
State giving reason :
(a) What is observed when a current is passed through the aluminum rod from end B to end A ?
(b) What change is observed in a situation in which the axis of the rod 'AB' is moved and aligned parallel to the magnetic field and current is passed in the rod in the same direction ?
OR
"Magnetic field is a physical quantity that has both direction and magnitude." How can this statement be proved with the help of magnetic field lines of a bar magnet ?
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Official CBSE Marking Scheme · CBSE Board 2022 (Term II), Marking Scheme Set 31/4/1
(a) Rod AB would get displaced [½] Reason: When a current carrying conductor is placed in an external magnetic field perpendicularly, it experiences a force. [½]
(b) As current and magnetic field are parallel, there will be no force experienced by the conductor hence no displacement in rod. [1]
OR
Field lines emerge from the north pole and merge at south pole / the direction in which a north pole of the compass needle moves inside it. [1] The relative strength of the magnetic field is shown by the degree of closeness of the field lines. Crowded are the field lines, stronger is the field. [1] OR diagrammatic expression.
Q45.2022 Supp 31/6/1 · Q62 marks
(a) (i) A magnetic compass shows a deflection when placed near a current carrying wire. How will the deflection of the compass get affected if the current in the wire is increased ? What does it indicate ?
(ii) State Right hand thumb rule.
OR
(b) List two factors on which the strength of magnetic field at a point due to a current carrying straight conductor depends. State the rule that determines the direction of magnetic field produced in this case.
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Official CBSE Marking Scheme · CBSE Board 2022 (Term II, Supplementary), Marking Scheme Set 31/6/1
(a) (i) The deflection will increase. [½] It indicates that the magnitude of the magnetic field produced at a given point increases as the current through the wire increases. [½]
(ii) If a current carrying conductor is imagined to be held in right hand such that the thumb points along the direction of current then the direction of the wrapped fingers will give the direction of magnetic field lines. [1] (Give full credit if explained by labelled figure)
OR
(b) Two factors: (i) Strength of current [½] (ii) Distance of the point from the straight conductor [½] Imagine that you are holding a current carrying straight conductor in your right hand such that the thumb points towards the direction of the current then your fingers will wrap around the conductor in the direction of magnetic lines. [1]
Q46.2026 Exam 2 31/7/1 · Q373 marks
What is the use of fuse in domestic electric circuits ? How is its role different from the role of a green coloured wire given in domestic electric circuits ? What will happen if an electrician installs a fuse with higher-rated value than prescribed for a given electric circuit ?
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Official CBSE Marking Scheme · CBSE Board 2026 (2nd Board Examination), Set 31/7/1
Fuse – It is used to protect the appliances from overloading (Short circuiting). [1]
Green colour wire – Earth wire – Provides a low resistance conducting path for current to flow to the earth, if there is any leakage of current to metallic body of appliance, hence prevents from electric shock. [1]
Fuse will not be able to protect the circuit during overloading. [1]
Q47.2026 Exam 2 31/8/1 · Q353 marks
(A) A vertical wire is carrying a current in the upward direction. It is placed in a magnetic field, pointing towards the East direction. Find out the direction of force on the wire.
(B) Out of the two current carrying circular coils, coil ‘A’ has 10 turns while coil B has 15 turns. Which of the two coils will produce a stronger magnetic field at its centre if same current is flowing through both the coils ? Explain with reason.
(C)
In the given figure, AB and CD are two magnetic field lines intersecting each other at point O. If a compass is placed at point O, what will happen ? State your conclusions.
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Official CBSE Marking Scheme · CBSE Board 2026 (2nd Board Examination), Set 31/8/1
(A) Towards North [1]
(B) Coil B [½]. Strength of Magnetic field is directly proportional to the number of turns. [½]
(C) The given figure shows that field has two directions at O. The compass needle may point towards two directions (along OB and along OD) which is not possible. This is an unreal situation. [½] Conclusion : Two magnetic field lines never intersect. [½]
Q48.2026 Exam 2 31/8/1 · Q373 marks
(A) Write any two precautions to be taken to avoid electrical accidents.
(B) State how these precautions prevent possible damage to the electric circuit.
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Official CBSE Marking Scheme · CBSE Board 2026 (2nd Board Examination), Set 31/8/1
(A) Use fuse of appropriate rating. [½] There must be earth wire in circuit. [½]
(B) During overloading fuse melts and protect the appliances. [1] Earth wire protect us from electric shock due to leakage of current to metallic body of appliances by providing a low resistance path to earth. [1]
Q49.2026 Main 31/1/1 · Q363 marks
(a) Describe an activity to show that a current carrying conductor, placed in an external magnetic field experiences a force.
(b) Imagine that you are sitting in a chamber with your back to one wall. An electron beam, moving horizontally towards the front wall from the back wall, is deflected by a strong magnetic field to your right side. Find the direction of the magnetic field.
Take a small aluminium rod AB and using two connecting wires suspend it horizontally from a stand. Place a strong horse-shoe magnet in such a way that the rod lies between the two poles perpendicularly. Connect the aluminium rod in series with a battery and a key. Now pass a current through the aluminium rod from one end to another. [1]
(Procedure can also be explained with a Diagram)
Observation
It is observed that the rod is displaced on passing current though it. [1]
(b) Magnetic field will be vertically downwards. [1]
Q50.2026 Main 31/1/1 · Q373 marks
(a) The pattern of magnetic field due to a current carrying wire depends upon the shape made by that wire. Justify.
(b) A current carrying straight wire AB is shown in the given diagram. Out of X, Y and Z on which point will the strength of magnetic field be maximum and why ?
• Magnetic field pattern for a current carrying straight conductor – concentric circles.
• Magnetic field pattern for a current carrying solenoid – magnetic field lines similar to that of a bar magnet.
• Magnetic field pattern for a current carrying circular loop – a pair of concentric circles with parallel straight lines at the centre. (any two cases)
(b) • At X. [½]
• Magnetic field decreases as the distance from the conducting wire increases. [½]
Q51.2026 Main 31/4/1 · Q373 marks
On the basis of the given circuit arrangement, answer the following questions :
(a) What happens to the rod AB when the key K is closed and why ?
(b) Name and state the rule that determines this behaviour of the rod AB in the above situation.
(a) • The rod AB gets displaced from its original position [½]
• Because it experiences a force when placed in external magnetic field [½]
(b) • Fleming’s Left Hand Rule [1]
• Stretch the thumb, fore finger and middle finger of your left hand such that they are mutually perpendicular. If forefinger points in the direction of magnetic field, second finger in the direction of current, then the thumb will point in the direction of motion or force acting on the conductor. [1]
Q52.2025 Main 31/3/1 · Q323 marks
Consider a rectangular cardboard having two holes P and Q through which a current carrying circular loop has been inserted as shown in the diagram.
(a) Make this diagram on your answer sheet and draw three magnetic field lines, one each passing through the points 1 (near P), 2 (at the centre of the loop) and 3 (near Q).
(b) List two factors on which the intensity of the magnetic field produced at the centre of the loop depends.
(c) Name the rule you will apply to determine the direction of magnetic field produced due to a current carrying straight conductor.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/3/1
(a)
Marking magnetic lines for points 1, 2 and 3 [½ × 3]
(b) Strength of the current in the loop; No. of turns of loop [½ × 2]
(c) Right hand thumb rule [½]
Q53.2025 Main 31/5/1 · Q333 marks
(a) “The third wire of earth connection is very important in domestic electric appliances.” Justify this statement.
(b) List two precautions to be taken to avoid the overloading of domestic electric circuits.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/5/1
(a) The third wire (earth wire) is a safety measure to ensure that in case of any leakage of current to the metallic body of the appliance, it keeps its potential to that of the Earth and the user may not get a severe shock. [2]
(b) (i) Use of electric fuse of proper rating
(ii) Not connecting too many appliances to a single socket. (any other) [½ + ½]
Q54.2025 Supp 31/S/1 · Q323 marks
As shown in the figure a small aluminum rod AB is suspended horizontally between the poles of a strong horseshoe magnet. This rod is also connected with a battery and a key. Study the arrangement shown.
(a) State Fleming’s left-hand rule.
(b) Apply Fleming’s left-hand rule to determine :
(i) What is observed when a current is passed from B to A in the rod ?
(ii) What is observed when a current is passed from A to B in the rod ?
(iii) What is observed when the rod AB is aligned parallel to the magnetic field and current is passed through it from B to A ? Justify your answer in this case.
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Official CBSE Marking Scheme · CBSE Board 2025 (Supplementary), Set 31/S/1
(a) According to this rule, stretch the thumb, forefinger and middle finger of your left hand such that they are mutually perpendicular. If the first finger points in the direction of magnetic field and the second finger in the direction of current, then the thumb will point in the direction of motion or the force acting on the conductor. [1]
(b) (i) Rod is displaced towards left. [½]
(ii) Rod is displaced towards right. [½]
(iii) No displacement is observed in rod. [½] This is because current and magnetic field are parallel, so there will be no force experienced by the conductor. [½]
Q55.2024 Main 31/1/1 · Q323 marks
Name and state the rule to determine the direction of a :
(i) magnetic field produced around a current carrying straight conductor.
(ii) force experienced by a current carrying straight conductor placed in a magnetic field which is perpendicular to it.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/1/1
(i) • Right-Hand Thumb Rule [½]
• If the wire carrying current is held in our right hand such that the thumb points towards the direction of current, then the fingers wrap around the conductor in the direction of field lines of the magnetic field. [1]
(ii) • Fleming’s Left-Hand Rule [½]
• Stretch the thumb, forefinger and middle finger of left hand mutually perpendicular to each other, such that first finger points in the direction of magnetic field, second finger in the direction of current, then thumb in the direction of motion or force acting on the conductor. [1]
Q56.2024 Main 31/2/1 · Q323 marks
Draw a diagram to show the pattern of magnetic field lines on a horizontal sheet of paper due to a straight conductor passing through its centre and carrying current vertically upwards. Mark on it (i) the direction of current in the conductor and (ii) the corresponding magnetic field lines. State right hand thumb rule and check whether the directions marked by you are in accordance with this rule or not.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/2/1
•
[1] Direction of current [½]; Direction of magnetic field lines [½]
• Right-Hand Thumb Rule : When a current-carrying straight conductor is being held in right-hand such that the thumb points towards the direction of current, then fingers will wrap around the conductor in the direction of the magnetic field lines. [1]
Q57.2024 Main 31/3/1 · Q323 marks
Explain in brief the function of an electric fuse in a domestic circuit. An electric heater of current rating 3 kW; 220 V is to be operated in an electric circuit of rating 5 A. What is likely to happen when the heater is switched ‘ON’ ? Justify your answer with necessary calculation.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/3/1
• It prevents damage to the appliances and the electrical circuit from overloading and short circuiting. [1]
• Here P = 3 kW = 3000 W, V = 220 V, I = ?
P = VI [½]
I = PV = 3000 W220 V = 13·63 A [1]
13·63 A > Rating of fuse 5 A, therefore fuse wire will melt and break the circuit. [½]
Q58.2024 Main 31/4/1 · Q323 marks
A student fixes a sheet of white paper on a drawing board. He places a bar magnet in the centre of it. He sprinkles some iron filings uniformly around the bar magnet. Then he taps the drawing board gently and observes that the iron filings arrange themselves in a particular pattern.
(a) Why do iron filings arrange in a particular pattern ?
(b) What does the crowding of iron filings at the ends of the magnet indicate ?
(c) What do the lines, along which the iron filings align, represent ?
(d) If the student places a cardboard horizontally in a current carrying solenoid and repeats the above activity, in what pattern would the iron filings arrange ? State the conclusion drawn about the magnetic field based on the observed pattern of the lines.
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/4/1
(a) Because a magnetic field exists around the bar magnet [½]
(b) Strength of the magnetic field is maximum near the poles of the magnet [1]
(c) The lines represent the magnetic field lines [½]
(d) Equidistant parallel lines, magnetic field inside the solenoid is uniform [½ + ½]
Q59.2024 Main 31/5/1 · Q323 marks
(a) What happens when a bundle of wires of soft iron is placed inside the coil of a solenoid carrying a steady current ? Name the device obtained. Why is it called so ?
(b) Draw the magnetic field lines inside a current carrying solenoid. What does this pattern of magnetic field lines indicate ?
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Official CBSE Marking Scheme · CBSE Board 2024 (Main), Set 31/5/1
(a) • It gets magnetised [½]
• Electromagnet. [½]
• It behaves as a magnet only when current passes through the solenoid. [½]
(b)
(Any one diagram) [1]
• This pattern indicates that the magnetic field is uniform. [½]
Q60.2024 Supp 31/S/1 · Q323 marks
(a) State (i) right-hand thumb rule, and (ii) Fleming’s left-hand rule.
(b) Using Fleming’s left-hand rule determine the direction of force experienced by a proton, which enters vertically downwards in a uniform magnetic field acting horizontally from west to east as shown in the diagram.
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Official CBSE Marking Scheme · CBSE Board 2024 (Supplementary), Set 31/S/1
(a)
(i) Imagine that you are holding a current-carrying straight conductor in your right hand such that the thumb points towards the direction of current. Then your fingers will wrap around the conductor in the direction of the field lines of the magnetic field. This is known as the right-hand thumb rule. [1]
Note : Award full marks if explained diagrammatically.
(ii) Stretch the thumb, forefinger and middle finger of your left hand such that they are mutually perpendicular. If the first finger points in the direction of magnetic field and the second finger in the direction of current, then the thumb will point in the direction of motion or the force acting on the conductor. [1]
Note : Award full marks if explained diagrammatically.
(b) Out of plane of the paper. [1]
Q61.2023 Main 31/1/1 · Q323 marks
(a) (i) State the rule used to find the force acting on a current carrying conductor placed in a magnetic field.
(ii) Given below are three diagrams showing entry of an electron in a magnetic field. Identify the case in which the force will be (1) maximum and (2) minimum respectively. Give reason for your answer.
OR
(b) (i) Draw the pattern of magnetic field lines of
(1) a current carrying solenoid
(2) a bar magnet
(ii) List two distinguishing features between the two fields.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/1/1
(a) (i) Fleming’s left-hand rule: Stretch the forefinger, the central finger and the thumb of your left hand in mutually perpendicular directions. If the forefinger shows the direction of the magnetic field and the central finger that of the current, then the thumb will point towards the direction of motion of the conductor or direction of force / [1]
(ii) (1) Force on electron is maximum in Fig (i) because the direction of motion of electron/current is at right angle/perpendicular to that of magnetic field. [½, ½]
(2) Force on electron is minimum in Fig (iii) because the electron is moving along / parallel to the direction of magnetic field. [½, ½]
OR
(b) (i) (1)
Magnetic field lines of a current carrying solenoid [1]
(2)
Magnetic field lines of a bar magnet [1]
(ii)
Magnetic field of a solenoid
Magnetic field of a bar magnet
1. The strength of the magnetic field can be changed by changing the current.
1. The strength of the magnetic field for a bar magnet cannot be changed.
2. The direction of magnetic field can be reversed by reversing the direction of current.
2. The direction of magnetic field for a bar magnet cannot be changed.
3. It is a temporary magnetic field.
3. It is a permanent magnetic field.
(Any two) [½, ½]
Q62.2023 Main 31/2/1 · Q323 marks
Explain the meaning of overloading of an electrical circuit. List two possible causes due to which overloading may occur in household circuits. Write one preventive measure that should be taken to avoid overloading of domestic circuits.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/2/1
Overloading : Overloading of an electrical circuit happens when an excessive amount of electric current flows through the wires. [1]
Two causes :
(i) Contact between live and neutral wire / short circuiting [½]
(ii) Connecting too many appliances to a single socket. [½]
(iii) Accidental hike in supply voltage (Any two points) (Any other)
Preventive measure :
(i) To use wires of proper insulation/proper rating
(ii) Not connecting too many appliances to a single socket.
(iii) Fuse wires (Any one) [1]
Q63.2023 Main 31/4/1 · Q323 marks
(A) (i) Why is an alternating current (A.C.) considered to be advantageous over direct current (D.C.) for the long distance transmission of electric power ?
(ii) How is the type of current used in household supply different from the one given by a battery of dry cells ?
(iii) How does an electric fuse prevent the electric circuit and the appliances from a possible damage due to short circuiting or overloading.
OR
(B) For the current carrying solenoid as shown, draw magnetic field lines and give reason to explain that out of the three points A, B and C, at which point the field strength is maximum and at which point it is minimum ?
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/4/1
(A) (i) Alternating current can be transmitted over long distances without much loss of electric energy. [1]
(ii) Household supply – Alternating current (AC) [½]
Battery of dry cell – Direct current (DC) [½]
(iii) It melts and breaks the circuit when a current of higher value than its rating flows through it. [1]
OR
(B) •
[1] [Deduct ½ mark if direction of current or magnetic field is not marked]
• Maximum at A [½]
Magnetic field lines are crowded. / Magnetic field adds up due to ‘n’ number of turns of a solenoid. [½]
• Minimum at B [½]
Magnetic field lines are far apart. [½]
Q64.2023 Main 31/5/1 · Q323 marks
(a) (i) A straight cylindrical conductor is suspended with its axis perpendicular to the magnetic field of a horse-shoe magnet. The conductor gets displaced towards left when a current is passed through it. What will happen to the displacement of the conductor if the
(1) current through it is increased ?
(2) horse-shoe magnet is replaced by another stronger horse-shoe magnet ?
(3) direction of current through it is reversed ?
(ii) Name and state the rule for determining the direction of force on a current carrying conductor in a magnetic field.
OR
(b) Draw the pattern of the magnetic field produced around a vertical current carrying straight conductor passing through a horizontal cardboard. Mark the direction of current and the magnetic field lines. Name and state the rule which is used to determine the direction of magnetic field associated with a current carrying conductor.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/5/1
(a) (i) (1) Increased. [½]
(2) Increased. [½]
(3) The direction of displacement is reversed [½]
(ii) • Fleming’s left-hand rule [½]
• According to this rule, stretch the thumb, forefinger and middle finger of left hand such that they are mutually perpendicular. If the first finger points in the direction of magnetic field and the second finger in the direction of current, then the thumb will point in the direction of motion or the force acting on the conductor. [1]
Alternate answer of the statement :
All the physical quantities mentioned in the diagram should be perpendicular to each other.
OR
(b) •
• Pattern [½]
• Direction of current [½]
• Magnetic field direction [½]
(Note: If the variable resistor and ammeter are not drawn, do not deduct marks.)
• Right hand thumb Rule [½]
• Imagine that we are holding a current carrying straight conductor in our right hand such that the thumb points towards the direction of current. Then our finger will wrap around the conductor in the direction of the field lines of the magnetic field. [1]
Alternate answer of the statement :
Q65.2023 Main 31/6/1 · Q323 marks
What is a solenoid ? When does a solenoid behave as a magnet ? Draw the pattern of the magnetic field produced inside it showing the directions of the magnetic field lines.
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Official CBSE Marking Scheme · CBSE Board 2023 (Main), Set 31/6/1
A solenoid is a coil of many turns of insulated copper wires wrapped closely in the shape of a cylinder [1]
When electric current is passed through it [1]
[1] (Deduct ½ mark if direction of current or magnetic field is not marked.)
Q66.2023 Supp 31/C/1 · Q323 marks
(a) (i) Differentiate between a solenoid and a circular coil.
(ii) Explain how a solenoid can be made in a school laboratory.
(iii) Write one use of the strong magnetic field produced inside a current carrying solenoid.
OR
(b) With the help of a labelled circuit diagram, illustrate the pattern of the magnetic field lines of the magnetic field produced around a straight current carrying conductor. Explain how, with the help of right-hand thumb rule, we can determine and mark the direction of magnetic field lines due to a current.
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Official CBSE Marking Scheme · CBSE Board 2023 (Supplementary), Set 31/C/1
(a) (i) Solenoid : A coil of many turns of insulated copper wire wrapped closely in the shape of cylinder. Circular coil : Straight wire bent in the form of circular loop with many turns. [1]
(ii) By taking a non-conducting cylindrical tube and winding a long, insulated copper wire tightly over it in the shape of a spring such that the turns are closely placed and lie side by side. [1]
(iii) To magnetise a piece of magnetic material like soft iron / To make an electromagnet (any one) [1]
OR
(b)
Diagram [1]; Labelling of magnetic field [1]
(Please check the direction of magnetic field lines corresponding to the direction of current in the conductor.)
• Right Hand Thumb Rule : Imagine that you are holding a current-carrying straight conductor in your right hand such that the thumb points towards the direction of current. Then your fingers will wrap around the conductor in the direction of the field lines of the magnetic field. [1]
Q67.2022 Main 31/3/1 · Q113 marks
What is a Solenoid ? Draw the pattern of the magnetic field lines around a current carrying solenoid. Mark on the pattern the region where the magnetic field is uniform.
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Official CBSE Marking Scheme · CBSE Board 2022 (Main), Set 31/3/1
• Solenoid : A coil of many circular turns of insulated copper wire wrapped closely in the shape of a cylinder. [1]
• Pattern of field lines : [1½]
• Field is uniform only inside the solenoid. (Position of the uniform field to be marked in the figure) [½]
Q68.2022 Main 31/3/1 · Q123 marks
(a) In the diagram given below, Coil – 1 is connected in series with a battery and a plug key while Coil – 2 is connected with a galvanometer.
(i) Why does the galvanometer show deflection only when the key (K) is plugged in and not when a steady current starts flowing in the circuit ?
(ii) What is observed in the galvanometer, when the key is plugged out ?
(iii) State the conclusion based on the observation of this activity.
OR
(b) In the figure given below, a simple electric motor is shown :
As shown in the figure, the current in the coil ABCD flows from A to B in the arm AB and C to D in the arm CD.
(i) State the directions in which the arms AB and CD will experience a force.
(ii) Identify the part of the electric motor that reverses the flow of current in the coil ABCD and write its name.
(iii) After the reversal of flow of current in the coil ABCD, state the directions in which the arms AB and CD will experience a force.
(iv) Name the rule which is applied to determine the direction of force on a current carrying conductor placed in a magnetic field.
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Official CBSE Marking Scheme · CBSE Board 2022 (Main), Set 31/3/1
(a) (i) • When the key is plugged-in, current starts in coil-1, the magnetic field around the coil is changed. This produces induced current in the coil – 2 and galvanometer shows deflection
• There is no change in magnetic field when a steady current starts flowing in the circuit. [1]
(ii) Galvanometer shows deflection in the opposite direction. [1]
(iii) Conclusion : Induced current is produced only when there is a change in magnetic field which occurs only when the key is plugged in or plugged out. [1]
OR
(b) (i) Arm AB — Downward, Arm CD — Upward [½ + ½]
(ii) P and Q — Split ring / Commutator [½, ½]
(iii) Arm AB upward, Arm CD downward / Direction of force will get reversed [½]
(iv) Fleming’s left-hand rule [½]
Q69.2022 Main 31/4/1 · Q123 marks
(a) A student wants to use an electric heater, an electric bulb and an electric fan simultaneously.
How should these gadgets be connected with the mains ? Justify your answer giving three reasons.
(b) What is an electric fuse ? How is it connected in a circuit ?
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Official CBSE Marking Scheme · CBSE Board 2022 (Term II), Marking Scheme Set 31/4/1
(a) These appliances/gadgets should be connected in parallel. [½] Justification (any three) [½ × 3]: • These gadgets need current of widely different values to operate properly. • Independent switching can be done for different appliances. • If any component fails, other gadgets may function. • All gadgets get the required voltage for their operation. • Effective resistance decreases hence heat loss minimizes.
(b) It is a device which protects the circuit/appliance by stopping the flow of any unduly high current / safety device in electrical circuit. [½] It is connected in series with the device. [½]
Q70.SQP 2025-26 · Q373 marks
Magnetic field lines are shown in the given diagram. A student makes a statement that the magnetic field at X is stronger than at Y.
(i) Explain with reason if the student’s claim is correct.
(ii) Also redraw the diagram and mark the direction of magnetic field lines.
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Official CBSE Marking Scheme · CBSE Sample Question Paper 2025-26 Marking Scheme
Closeness of magnetic field lines is directly related to strength of magnetic field.
Strength of magnetic field at point X (pole) is more than point Y.
If the student redraws the diagram he/she should mark arrows correctly from North to South.
Q71.SQP 2026-27 · Q363 marks
A. State the Right-Hand Thumb Rule and describe how it helps determine the direction of magnetic field around a current-carrying conductor.
B. Explain how the magnetic field changes with distance from the conductor.
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Official CBSE Marking Scheme · CBSE Sample Question Paper 2026-27 Marking Scheme
A. Right-hand thumb rule: Imagine that you are holding a current-carrying straight conductor in your right hand such that the thumb points towards the direction of current. Then your fingers will wrap around the conductor in the direction of the field lines of the magnetic field. [1]
If the thumb of the right hand points in the direction of conventional current, the curled fingers indicate the direction of the magnetic field lines around the conductor. This helps determine the direction of the magnetic field. [1]
B. Variation with distance: Magnetic field magnitude around a long straight conductor at distance r falls as B ∝ Ir, i.e. it decreases inversely with distance from the conductor. [1]
Q72.2025 Main 31/1/1 · Q394 marks
In our homes, we receive the supply of electric power through a main supply also called mains, either supported through overhead electric poles or by underground cables. In our country the potential difference between the two wires (live wire and neutral wire) of this supply is 220 V.
(a) Write the colours of the insulation covers of the line wires through which supply comes to our homes.
(b) What should be the current rating of the electric circuit (220 V) so that an electric iron of 1 kW power rating can be operated ?
(c) (i) What is the function of the earth wire ? State the advantage of the earth wire in domestic electric appliances such as electric iron.
OR
(c) (ii) List two precautions to be taken to avoid electrical accidents. State how these precautions prevent possible damage to the circuit/appliance.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/1/1
(a) Live wire – Red [½]
Neutral wire – Black [½]
(b) Power, P = 1 kW = 1 × 1000 W = 1000 W
Voltage, V = 220 V
Current drawn I = ? P = VI [½]
I = 1000 W220 V = 4·54 A
Current rating should be of 5 A. [½]
(c) (i) The earth wire provides a low resistance conducting path for the current which ensures that any leakage of current to flow to the metallic body of the appliances, keeps its potential to that of the earth. [1]
The user will not get an electric shock. [1]
OR
(c) (ii) Fuse wire [½]
Earth wire [½]
A fuse in a circuit prevents damage to the circuit due to overloading. [½]
Earth wire prevents electric shock due to leakage of current. [½]
Q73.2025 Main 31/5/1 · Q394 marks
In order to obtain magnetic field lines around a bar magnet, a student performed an experiment using a magnetic compass and a bar magnet. The magnet was placed on a sheet of white paper fixed on a drawing board. Using magnetic needle he obtained on the paper a pattern of magnetic field lines (as shown below) around the bar magnet.
(a) By convention, the field lines emerge from north pole and merge at south pole. Why ? Give reason.
(b) State the relationship between strength of the magnetic field and the degree of closeness of the field lines.
(c) (A) (i) No two field lines can ever intersect each other. Give reason.
(ii) The magnetic field in a given region is uniform. Draw a diagram to represent it.
OR
(c) (B) Draw the pattern of the magnetic field lines through and around a current carrying solenoid. What does the pattern of field lines inside the solenoid represent ?
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/5/1
(a) The direction of the magnetic field is taken to be the direction in which a north pole of the compass needle moves inside it. [1]
(b) Closer the field lines stronger is the magnetic field. [1]
(c) (A) (i) It would mean that at the point of intersection, the compass needle would point towards two directions, which is not possible. [1]
(ii)
Equidistant parallel lines (Award marks if magnetic field is shown through a solenoid) [1]
OR
(B)
[1]
Uniform Magnetic Field [1]
Q74.2022 Main 31/1/1 · Q154 marks
A student fixes a sheet of white paper on a drawing board using some adhesive materials. She places a bar magnet in the centre of it and sprinkles some iron filings uniformly around the bar magnet using a salt-sprinkler. On tapping the board gently, she observes that the iron filings have arranged themselves in a particular pattern.
(a) Draw a diagram to show this pattern of iron filings. (1)
(b) Draw the magnetic field lines of a bar magnet showing the poles of the bar magnet as well as the direction of the magnetic field lines. (1)
(c) (i) How is the direction of magnetic field at a point determined using the field lines ? Why do two magnetic field lines not cross each other ? (2)
OR
(ii) How are the magnetic field lines of a bar magnet drawn using a small compass needle ? Draw one magnetic field line each on both sides of the magnet. (2)
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Official CBSE Marking Scheme · CBSE Board 2022 (Term II), Marking Scheme Set 31/1/1
(a) [1]
(b) [1]
(c) (i) By placing a compass needle on magnetic field lines, direction of north pole will give direction of magnetic field. [1] If they cross or intersect, it means that at the point of intersection the compass needle would point into two directions, which is not possible. / If they cross or intersect, it means that at the point of intersection there will be direction of two resultant fields which is not possible. [1]
OR
(c) (ii) Take a small bar magnet, place it in the centre of the drawing sheet fixed on a drawing board and mark its boundary. [½] Place a small compass needle near the north pole of the magnet, south pole of the compass needle points towards the north pole. [½] Mark the position of two ends of the needle. Now move the needle to a new position such that the south pole of needle occupies the position previously occupied by the north pole and again mark the new position of the north pole. In this way proceed step by step till you reach the south pole of the magnet. Join the points marked to get a field line. Similarly draw one more field line on the other side of the magnet. [½]
[½]
Q75.2022 Main 31/2/1 · Q154 marks
A student was asked to perform an experiment to study the force on a current carrying conductor in a magnetic field. He took a small aluminum rod AB, a strong horse shoe magnet, some connecting wires, a battery and a switch and connected them as shown. He observed that on passing current, the rod gets displaced. On reversing the direction of current, the direction of displacement also gets reversed. On the basis of your understanding of this phenomenon, answer the following questions :
(a) Why does the rod get displaced on passing current through it ?
(b) State the rule that determines the direction of the force on the conductor AB.
(c) (i) If the U shaped magnet is held vertically and the aluminum rod is suspended horizontally with its end B towards due north, then on passing current through the rod from B to A as shown, in which direction will the rod be displaced ?
(ii) Name any two devices that use current carrying conductors and magnetic field.
OR
Draw the pattern of magnetic field lines produced around a current carrying straight conductor held vertically on a horizontal cardboard. Indicate the direction of the field lines as well as the direction of current flowing through the conductor.
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Official CBSE Marking Scheme · CBSE Board 2022 (Term II), Marking Scheme Set 31/2/1
(a) A force is exerted on the current carrying rod when it is placed perpendicular to the magnetic field. [1]
(b) Fleming's left-hand rule : Stretch the thumb, forefinger and middle finger of your left-hand such that they are mutually perpendicular. If the first finger points to the direction of magnetic field and the second finger in the direction of current, then the thumb will point in the direction of motion or the force acting on the conductor. [1]
(c) (i) Towards left or towards west / Into U shape magnet [1] (ii) Electric motor / electric generator / loudspeakers / microphones / electrical measuring instruments (any two) [½ + ½]
OR
(c)
Direction of current - downward [½] Direction of field lines – clockwise [½] Alternatively, if the direction of current is marked upwards then direction of field lines will be anticlockwise. (Credit full marks if direction of current and field lines are marked in the diagram) [Diagram: 1]
Q76.2022 Main 31/4/1 · Q144 marks
AB is a coil of copper wire having a large number of turns. The ends of the coil are connected with a galvanometer as shown. When the north pole of a strong bar magnet is moved towards the end B of the coil, a deflection is observed in the galvanometer.
(a) State the reason for using galvanometer in the activity and why does its needle deflects momentarily when magnet is moved towards the coil.
(b) What would be observed in the galvanometer in a situation when the coil and the bar magnet both move with the same speed in the same direction ? Justify your answer.
(c) State the conclusion that can be drawn from this activity.
Will there be any change in the momentary deflection in the galvanometer if number of turns in the coil is increased and a more stronger magnet is moved towards the coil ?
OR
What is electromagnetic induction ? What is observed in the galvanometer when a strong bar magnet is held stationary near one end of a coil of large number of turns ? Justify your answer.
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Official CBSE Marking Scheme · CBSE Board 2022 (Term II), Marking Scheme Set 31/4/1
(a) Galvanometer is used to detect the presence of current along with its direction. [½] Needle deflects momentarily due to momentary change in magnetic field associated with the coil due to which current induces. [½]
(b) There would be no deflection in the galvanometer because there is no induced current flowing in galvanometer as there is no relative motion between the magnet and the coil and no change in magnetic field associated with coil. [1]
(c) The relative motion of a magnet and coil produces an induced potential difference which sets up an induced current in the circuit and it lasts so long the relative motion is there. [1] Momentary deflection will be there with increased magnitude. [1]
OR
It is a process by which a changing magnetic field in a conductor induces current in another conductor. [1] No deflection in galvanometer. As there is no relative motion between the coil and magnet which leads to no change in magnetic field associated with coil hence no induced current generates. [½, ½]
Q77.2022 Supp 31/6/1 · Q154 marks
Take two different coils of copper wire having large number of turns, say 50 and 100 turns respectively. Insert them over a non-conducting roll as shown in the given figure. Connect the Coil-1, having large number of turns, in series with a battery and a plug key. Also connect the other Coil-2 with a galvanometer.
(a) State what is observed in the galvanometer, when
(i) the key is closed.
(ii) the key is opened.
(b) Define the phenomenon involved in this case.
(c) (i) Explain the reason for the current which is responsible for the deflection in the galvanometer.
OR
(ii) A coil AB of copper wire is connected to a galvanometer as shown in the figure. What is observed when N-pole of a strong bar magnet is
(I) pushed into the coil, and
(II) held stationary inside the coil ?
State the reason for each observation.
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Official CBSE Marking Scheme · CBSE Board 2022 (Term II, Supplementary), Marking Scheme Set 31/6/1
(a) (i) Needle of the galvanometer deflects in one direction momentarily. [½] (ii) Needle of the galvanometer deflects in opposite to previous direction momentarily. [½]
(b) The process by which a change in magnetic field in a conductor induce a current in another conductor. [1]
(c) (i) Reason – Induced current is generated due to change in the magnetic field associated with conductor. [2]
OR
(ii) (I) Deflection in the galvanometer. [½] (II) No deflection [½] Reason: (I) Motion of the magnet causes change in the magnetic field associated with coil which gives induced current. [½] (II) No change in magnetic field associated with coil and hence no induced current. [½]
Q78.SQP 2026-27 · Q384 marks
A school has installed an automatic electromagnetic door-locking system at the main entrance. The locking mechanism uses a solenoid controlled by a switch at the security desk. When electricity flows through the solenoid, it creates a magnetic field strong enough to pull an iron bolt, unlocking the door.
As soon as the switch is turned off, the magnetic field disappears, and a spring pushes the bolt back, locking the door.
A. Why is an iron core kept inside the solenoid in this locking mechanism?
B. How can we determine the magnetic poles in this solenoid?
Attempt either subpart (C) or (D).
C. If the current in the solenoid is increased from 1 A to 2 A, explain how the magnetic effect changes and its effect on unlocking the door.
OR
D. If the source of the current is fixed, how can we increase the magnetic field in the solenoid?
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Official CBSE Marking Scheme · CBSE Sample Question Paper 2026-27 Marking Scheme
A. An iron core placed inside the solenoid concentrates and amplifies the magnetic field, producing a stronger pulling force on the bolt. [1]
B. Using the right-hand thumb rule (Curl the fingers of your right hand in the direction of current, then the direction of thumb will point towards the direction of north pole of the solenoid). Use a bar magnet with a known north pole towards one of the ends of the solenoid, Repulsion will indicate North pole. [1]
Attempt either sub-part C or D.
C. If current increases then the magnetic field B inside a solenoid will also increases as magnetic field is directly proportional to current. As the magnetic field increases, a stronger magnetic pull unlocks the door more effectively. [2]
OR
D. Increase the number of turns N of the coil, reduce coil length, or insert a soft iron core. (any two points) [2]
Q79.2026 Main 31/2/1 · Q395 marks
Attempt either (a) or (b) :
(a) (i) State the rule which gives the direction of force acting on a current-carrying conductor placed in a magnetic field.
(ii) What is a fuse ? Why is it called a safety device ?
(iii) Why are electrical appliances with metallic bodies connected to the mains through a three-pin plug, whereas an electric bulb is connected with a two-pin plug ?
(iv)
What will be the direction of force experienced by the conductor AB due to the magnetic field, when current flows in the direction shown ? Name the law you applied to find the direction.
OR
(b) (i) Draw the pattern of magnetic field lines through and around a current-carrying circular loop.
(ii) State the rule to find out the direction of the magnetic field inside and around the circular loop.
(iii) Give reasons :
(I) Why should a burnt-out fuse be replaced by another fuse of identical rating only, in an electric circuit ?
(II) Why is soft iron-core used in making an electromagnet ?
(a) (i) Stretch the thumb, fore finger and middle finger of your left hand such that they are mutually perpendicular. If the first finger (forefinger) points in the direction of the magnetic field and the middle finger (second finger) in the direction of the current, then the thumb will point in the direction of motion or the force acting on the conductor. [1]
(ii) • A fuse is a safety device in electric circuit designed to protect against overloading. [½]
• Because it prevents damage to the circuit and appliance. [½]
(iii) Three pin plug connects the metallic body of an appliance with the earth wire which provides a low resistance path for electric current to flow to the ground and hence prevents us from electric shock. The bulb with a non metallic body does not require earthing and so is connected to a two pin plug. [1]
(iv) • Into the page. [1]
• Fleming’s Left-hand rule [1]
OR
(b) (i) (Any one diagram) [1 + 1 for direction of magnetic field lines and current]
(ii) Imagine that you are holding a current carrying straight conductor in your right hand such that the thumb points towards the direction of current. Then your fingers will wrap around the conductor in the direction of the field lines of the magnetic field. [1]
(iii) (I) If a fuse of higher rating is used it will not be able to prevent the damage due to overloading. / If a fuse of lower rating is used, it will melt and the appliance will not work. [1]
(II) Soft iron core can be easily magnetised when current flows through the solenoid and gets demagnetised quickly when current stops flowing. [1]
Q80.2026 Main 31/3/1 · Q395 marks
Attempt either (a) or (b) :
(a) (i) What is a solenoid ? Draw a diagram showing the magnetic field pattern due to a current-carrying solenoid (inside and outside).
(ii) Name any two factors on which the magnitude of the magnetic field due to a current-carrying solenoid depends.
(iii) A current-carrying solenoid is stretched and converted into a straight wire carrying current. Draw a diagram showing the magnetic field pattern around it and mark the direction of the magnetic field.
OR
(b) (i) With the help of a diagram, show that a current-carrying conductor placed in an external magnetic field, experiences a force. Indicate the direction of the field, current and force clearly.
(ii) The diagram given below shows an electron moving in a uniform magnetic field.
(I) What will be the direction of the force acting on the electron ?
(II) What will happen to the direction of the force acting on the electron, if the direction of the magnetic field as well as the direction of motion of the electron, both are reversed ?
(a) (i) Solenoid – A coil of many circular turns of insulated copper wire, wrapped closely in the shape of cylinder. [1]
[2 for diagram]
(ii) • Current flowing through the solenoid [½]
• No. of turns of the coil [½]
(iii) [1]
Note: Award marks if a different direction of current is shown with the correct corresponding direction of magnetic field.
OR
(b) (i) When current is passed through the conductor, it experiences a force and gets displaced.
diagram [1½]; direction of current [½]; direction of magnetic field [½]; direction of force [½]
(ii) (I) Into the plane of paper [1]
(II) The direction of force will remain same. [1]
Q81.2026 Main 31/5/1 · Q395 marks
(A) (i) Draw a diagram showing the magnetic field lines around a bar magnet. Write any two characteristics of magnetic field lines.
(ii) Write the statement of Right hand thumb rule.
(iii) The concentric circles representing the magnetic field around a current carrying straight wire become larger and larger as we move away from the wire. How does magnetic field change on these concentric circles ?
OR
(B) (i) Draw a diagram, showing the magnetic field lines in and around the current carrying solenoid. Write any two salient features of these lines.
(ii) What is an electromagnet and how is it made ?
• The magnetic field lines emerge from north pole and merge at south pole. Inside the magnet, the direction of field lines is from its south pole to its north pole. Thus, the magnetic field lines are closed curves.
• The relative strength of the magnetic field is shown by the degree of closeness of the field lines.
• No two field-lines are found to cross each other. (any two) [1+1]
(ii) Imagine that you are holding a current carrying straight conductor in your right hand such that the thumb points towards the direction of current. Then your fingers will wrap around the conductor in the direction of field lines of the magnetic field. [1]
(iii) As the concentric circles become larger and larger, the magnetic field decreases. [1]
OR
(B) (i)
[1]
Salient features:
• The pattern of the magnetic field lines in a solenoid is similar to that of a bar magnet. [1]
• Field lines inside the solenoid are in the form of parallel straight lines. [1]
(ii) • A magnetic material which behaves like a magnet on passing electric current through it is called an electromagnet. [1]
• It is made by wrapping a current carrying insulated copper wire in the form of a coil around a magnetic material like soft iron / By placing a magnetic material like soft iron as a core material inside the current carrying solenoid. [1]
Q82.2025 Main 31/2/1 · Q365 marks
(a) The given figure shows the current passing through the straight conductor XY.
(i) Copy the diagram and draw the magnetic field lines when current flows from conductor X to Y.
(ii) Name and state the rule used in determining the direction of the magnetic field lines in the situation given above.
(iii) State Fleming’s left hand rule. Using this rule, determine the direction of force applied on an electron entering a uniform magnetic field as shown in the figure.
OR
(b) (i) Define the term solenoid. Draw the pattern of the magnetic field lines in and around a current carrying straight solenoid. Mark on the pattern the (i) direction of current, (ii) direction of field lines near the ends of the solenoid, and (iii) region where the magnetic field is uniform.
(ii) How would you make an electromagnet using a current carrying solenoid ?
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/2/1
(a) (i)
[1½]
(ii) Right hand thumb rule [½]
Statement of the rule – Imagine holding a current carrying straight conductor in the right hand such that the thumb points towards the direction of current, then the fingers will wrap around the conductor in the direction of the field lines of the magnetic field. [1]
(iii) According to Fleming’s left-hand rule, stretch the thumb, forefinger and middle finger of your left hand such that they are mutually perpendicular. If the first finger points in the direction of magnetic field and the second finger in the direction of current, then the thumb will point in the direction of motion or the force acting on the conductor. [1]
Out of the plane / upwards [1]
OR
(b) (i) Solenoid is a coil of many turns of insulated copper wire wrapped closely in the shape of a cylinder. [1]
Diagram [1½]; Marking (i), (ii) and (iii) [½ × 3]
(ii) By inserting a piece of magnetic material like soft iron inside the current carrying solenoid. [1]
Q83.2025 Main 31/4/1 · Q365 marks
(A) (i) Draw the pattern of the magnetic field lines for the two parallel straight conductors carrying current of same magnitude ‘I’ in opposite directions as shown. Show the direction of magnetic field at a point O which is equidistant from the two conductors. (Consider that the conductors are inserted normal to the plane of a rectangular cardboard.)
(ii) In our houses we receive A.C. electric power of 220 V. In electric iron or electric heater cables having three wires with insulation of three different colours – red, black and green are used to draw current from the mains.
(a) What are these three different wires called? Name them colourwise.
(b) What is the potential difference between the red wire and the black wire?
(c) What is the role of the wire with green insulation in case of accidental leakage of electric current to the metallic body of an electrical appliance?
OR
(B) (i) By using the given experimental set-up. How can it be shown that :
(a) a force is exerted on the current-carrying conductor AB when it is placed in a magnetic field.
(b) the direction of force can be reversed in two ways.
(ii) When will the magnitude of the force be highest?
(iii) State Fleming’s left hand rule.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/4/1
(A) (i)
Correct pattern [1]
Correct direction [1]
(ii) (a) red wire : Live wire; black wire : Neutral wire; green wire : Earth wire [½ × 3]
(b) 220 V [½]
(c) This is used as a safety measure. It ensures that any leakage of the current to the metallic body of the appliance keeps its potential to that of the earth and the user may not get a severe electric shock. [1]
OR
(B) (i) (a) The conductor AB gets displaced. [1]
(b) – By reversing the direction of the current.
– By reversing the direction of the magnetic field. [1 + 1]
(ii) When the direction of current is at right angles to the direction of the magnetic field. [1]
(iii) Stretch the thumb, fore finger and middle finger of your left hand such that they are mutually perpendicular. If the first finger points in the direction of magnetic field and the second finger in the direction of the current, then the thumb will point in the direction of the force acting on the conductor. [1]
Q84.2025 Main 31/6/1 · Q365 marks
(a) What are magnetic field lines ? How is the direction of magnetic field at a point determined ? Draw the pattern of magnetic field lines of the magnetic field produced by a current carrying circular loop. Mark on it the direction of (i) current and (ii) magnetic field lines.
Name the two factors on which the magnitude of the magnetic field due to a current carrying coil depends.
OR
(b) Why can’t two magnetic field lines cross each other ? Draw magnetic field lines showing the direction of the magnetic field due to a current carrying long straight solenoid. State the conclusion which can be drawn from the pattern of magnetic field lines inside the solenoid.
Name any two factors on which the magnitude of the magnetic field due to this solenoid depends.
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Official CBSE Marking Scheme · CBSE Board 2025 (Main), Set 31/6/1
(a) • Magnetic field lines are the imaginary lines around the magnet [½]
• Magnetic field line directions at a point are determined by placing a small compass needle. [½]
• Figure of magnetic field produced by a current carrying circular coil –
(1 Mark for each labelling) [2]
• Amount of the electric current flowing through it.
• The number of turns in the circular coil
• The radius of circular coil (Any two) [2]
OR
(b) • There will be two directions of the field at the same point i.e. the point where the two field lines intersect which is not possible. / At the point of intersection, the compass needle would point towards two directions, which is not possible. [1]
[1]
• Magnetic field lines are equidistant and parallel i.e. the magnetic field is the same at all points inside the solenoid. [1]
• Number of turns
• Amount of current in solenoid,
• Core material inside the solenoid (Any two) [1 × 2]